zoukankan      html  css  js  c++  java
  • codeforces_346A Alice and Bob(数学)

    题目链接:http://codeforces.com/problemset/problem/346/A

    参考链接:http://blog.csdn.net/loy_184548/article/details/50174615

    感受到数学在博弈论中的强大。

    考虑最后终止状态的序列-无法取出任意两个数他们的差值不存在这个序列中:那么这必定是个首项等于公差的等差序列

    而这个序列是 d 2d 3d....,因此可以通过a[1] a[2] a[3] ...的最大公约数得到

    然后计算有几个数没在数组中,判断奇偶性即可

    代码:

     1 #include <cstdio>
     2 #include <cstdlib>
     3 #include <iostream>
     4 #include <cstring>
     5 #include <cmath>
     6 #include <algorithm>
     7 #include <set> 
     8 using namespace std;
     9 int a[105];
    10 
    11 int gcd(int x, int y){
    12     return x == 0? y : gcd(y % x, x);
    13 }
    14 
    15 int main(){
    16     int n, maxn = 0;
    17     scanf("%d", &n);
    18     for(int i = 0; i < n; i++){
    19         scanf("%d", &a[i]);
    20         maxn = max(a[i], maxn);
    21     }
    22     int cnt = 0;
    23     int g = a[0];
    24     for(int i = 1; i < n; i++){
    25         g = gcd(a[i], g);
    26     }
    27     cnt = maxn / g;
    28     for(int i = 0; i < n; i++){
    29         if(a[i] % g == 0) cnt--;
    30     }
    31     if(cnt & 1){
    32         printf("Alice
    ");
    33     }
    34     else{
    35         printf("Bob
    ");
    36     }
    37 }

    题目:

    A. Alice and Bob
    time limit per test
    2 seconds
    memory limit per test
    256 megabytes
    input
    standard input
    output
    standard output

    It is so boring in the summer holiday, isn't it? So Alice and Bob have invented a new game to play. The rules are as follows. First, they get a set ofn distinct integers. And then they take turns to make the following moves. During each move, either Alice or Bob (the player whose turn is the current) can choose two distinct integers x and y from the set, such that the set doesn't contain their absolute difference |x - y|. Then this player adds integer |x - y| to the set (so, the size of the set increases by one).

    If the current player has no valid move, he (or she) loses the game. The question is who will finally win the game if both players play optimally. Remember that Alice always moves first.

    Input

    The first line contains an integer n (2 ≤ n ≤ 100) — the initial number of elements in the set. The second line contains n distinct space-separated integers a1, a2, ..., an (1 ≤ ai ≤ 109) — the elements of the set.

    Output

    Print a single line with the winner's name. If Alice wins print "Alice", otherwise print "Bob" (without quotes).

    Examples
    input
    2
    2 3
    output
    Alice
    input
    2
    5 3
    output
    Alice
    input
    3
    5 6 7
    output
    Bob
    Note

    Consider the first test sample. Alice moves first, and the only move she can do is to choose 2 and 3, then to add 1 to the set. Next Bob moves, there is no valid move anymore, so the winner is Alice.

  • 相关阅读:
    力扣(LeetCode)验证回文串 个人题解(C++)
    力扣(LeetCode)平方数之和 个人题解
    Exclusive Access 2 UVA
    C语言中指针*p[N], (*P)[N]的区别
    2018年蓝桥杯国赛比赛心得
    2018acm/icpc西安邀请赛比赛心得
    [最小割]Cable TV Network UVA
    Tree Reconstruction UVA
    Twenty Questions UVA
    python中的enumerate 函数(编号的实现方式)
  • 原文地址:https://www.cnblogs.com/bolderic/p/6818711.html
Copyright © 2011-2022 走看看