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  • 【HDOJ】5564 Clarke and digits

    DP+快速矩阵幂。注意base矩阵的初始化,不难。

      1 /* 5564 */
      2 #include <iostream>
      3 #include <string>
      4 #include <map>
      5 #include <queue>
      6 #include <set>
      7 #include <stack>
      8 #include <vector>
      9 #include <deque>
     10 #include <algorithm>
     11 #include <cstdio>
     12 #include <cmath>
     13 #include <ctime>
     14 #include <cstring>
     15 #include <climits>
     16 #include <cctype>
     17 #include <cassert>
     18 #include <functional>
     19 #include <iterator>
     20 #include <iomanip>
     21 using namespace std;
     22 //#pragma comment(linker,"/STACK:102400000,1024000")
     23 
     24 #define sti                set<int>
     25 #define stpii            set<pair<int, int> >
     26 #define mpii            map<int,int>
     27 #define vi                vector<int>
     28 #define pii                pair<int,int>
     29 #define vpii            vector<pair<int,int> >
     30 #define rep(i, a, n)     for (int i=a;i<n;++i)
     31 #define per(i, a, n)     for (int i=n-1;i>=a;--i)
     32 #define clr                clear
     33 #define pb                 push_back
     34 #define mp                 make_pair
     35 #define fir                first
     36 #define sec                second
     37 #define all(x)             (x).begin(),(x).end()
     38 #define SZ(x)             ((int)(x).size())
     39 #define lson            l, mid, rt<<1
     40 #define rson            mid+1, r, rt<<1|1
     41 
     42 const int mod = 1e9+7;
     43 const int maxn = 75;
     44 int ID[maxn][maxn];
     45 int n;
     46 
     47 typedef struct mat_t {
     48     __int64 m[maxn][maxn];
     49 
     50     mat_t() {
     51         memset(m, 0, sizeof(m));
     52     }
     53 
     54     void init() {
     55         memset(m, 0, sizeof(m));
     56     }
     57 
     58     void print() {
     59         rep(i, 0, n) {
     60             rep(j, 0, n) {
     61                 printf("%I64d ", m[i][j]);
     62             }
     63             putchar('
    ');
     64         }
     65     }
     66 } mat_t;
     67 
     68 mat_t matMult(mat_t& a, mat_t& b) {
     69     mat_t c;
     70 
     71     rep(i, 0, n)
     72         rep(j, 0, n)
     73             rep(k, 0, n)
     74                 c.m[i][j] = (c.m[i][j] + a.m[i][k]*b.m[k][j]%mod)%mod;
     75 
     76     return c;
     77 }
     78 
     79 mat_t matPow(mat_t a, int m) {
     80     mat_t ret;
     81 
     82     rep(i, 0, n)
     83         ret.m[i][i] = 1;
     84     while (m) {
     85         if (m & 1)
     86             ret = matMult(ret, a);
     87         a = matMult(a, a);
     88         m >>= 1;
     89     }
     90 
     91     return ret;
     92 }
     93 
     94 mat_t e;
     95 mat_t base;
     96 
     97 void init(int s) {
     98     // first column is one
     99     // first row is zero(accept first one)
    100     rep(j, 0, n) {
    101         e.m[0][j] = 0;
    102         if (j%7 == 1)
    103             e.m[j][0] = 1;
    104         else
    105             e.m[j][0] = 0;
    106     }
    107     e.m[0][0] = 1;
    108     
    109     rep(i, 0, 10) {
    110         rep(j, 0, 7) {
    111             rep(ii, 0, 10) {
    112                 int jj = (10*j+ii)%7;
    113                 int id = ID[i][j];
    114                 int id_ = ID[ii][jj];
    115                 if (i+ii == s)
    116                     e.m[id][id_] = 0;
    117                 else
    118                     e.m[id][id_] = 1;
    119             }
    120         }
    121     }
    122 
    123     #ifndef ONLINE_JUDGE
    124         // e.print();
    125     #endif
    126 }
    127 
    128 void init_base() {
    129     int cnt = 1;
    130     n = 7*10+1;
    131 
    132     rep(i, 0, 10)
    133         rep(j, 0, 7)
    134             ID[i][j] = cnt++;
    135     rep(i, 1, 10)
    136         base.m[0][ID[i][i%7]] = 1;
    137 }
    138 
    139 __int64 cal(int len) {
    140     if (len == 0)
    141         return 0;
    142 
    143     __int64 ret = 0;
    144     mat_t res = matPow(e, len);
    145 
    146     rep(i, 0, n)
    147         ret = (ret + base.m[0][i]*res.m[i][0]%mod)%mod;
    148     return ret;
    149 }
    150 
    151 int main() {
    152     ios::sync_with_stdio(false);
    153     #ifndef ONLINE_JUDGE
    154         freopen("data.in", "r", stdin);
    155         freopen("data.out", "w", stdout);
    156     #endif
    157 
    158     int t;
    159     int l, r, s;
    160     __int64 nl, nr, ans;
    161 
    162     init_base();
    163     scanf("%d", &t);
    164     while (t--) {
    165         scanf("%d %d %d", &l, &r, &s);
    166         init(s);
    167         nl = cal(l-1);
    168         nr = cal(r);
    169         ans = (nr-nl+mod) % mod;
    170         #ifndef ONLINE_JUDGE
    171             printf("nl = %I64d, nr = %I64d
    ", nl, nr);
    172         #endif
    173         printf("%I64d
    ", ans);
    174     }
    175 
    176     #ifndef ONLINE_JUDGE
    177         printf("time = %d.
    ", (int)clock());
    178     #endif
    179 
    180     return 0;
    181 }
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  • 原文地址:https://www.cnblogs.com/bombe1013/p/4972272.html
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