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  • 计算一年中的第几天

    #include<iostream>
    using namespace std;
    
    int main()
    {
     int year,month,day;
     int m[12]={31,28, 31,30,31,30,31,31,30,31,30,31};
     cout<<"请输入年月日:";
     cin>>year>>month>>day;
     if(year%400==0 || year%4==0 && year%100!=0)
      m[1]=29;
     int sumdays=0;
     for(int i=0;i<month-1;i++){
      sumdays+=m[i];
     }
     sumdays+=day;
     cout<<year<<"年"<<month<<"月"<<day<<"日是一年中的第"<<sumdays<<"天"<<endl;
     system("pause");
     return 0;
    }
    
    


     

    系统函数:

    #include<iostream>
    #include <stdio.h>   
    #include <stddef.h>   
    #include <time.h>
    using namespace std;
    
    int main()
    {
    	time_t tmBeginTime = time(NULL);
    	struct tm *tmNowBegin = localtime(&tmBeginTime);
    	if (NULL == tmNowBegin)
    		return false;
    	int nCreateYear = tmNowBegin->tm_year+1900;
    	int nCreateMon = tmNowBegin->tm_mon+1;
    	int nCreateDay = tmNowBegin->tm_mday;
    	int nCreateYearDay = tmNowBegin->tm_yday;
    	int nCreateWeek = tmNowBegin->tm_wday;
    	cout<<nCreateYear<<","<<nCreateMon<<","<<nCreateDay<<","<<nCreateYearDay<<","<<nCreateWeek<<endl;
    	system("pause");
    	return 0;	
    }


     

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  • 原文地址:https://www.cnblogs.com/byfei/p/3112162.html
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