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  • MySQL之学生名次问题

    --对输入的数据进行约束
    create table t(studentID char(10), [name] varchar(8),
    startDate char(10) Check (isdate(startdate)=1 and cast(startdate as datetime)=convert(datetime,startdate,120)))
    insert into t
    select 'aa','bb','77799820'
    union all select 'bb','ggg','2007-10-11'
    union all select 'cc','ddd','2007-20-11'
    select * from t
    --创建测试表
    create table tbl ([name] varchar(8), chinese float, math float,zong float,px int)
    insert tbl
    select 'a', 80, 90,null,null
    union all select 'b', 85, 88,null,null
    union all select 'c', 77, 93,null,null
    union all select 'd', 80, 90,null,null
    union all select 'e', 99, 100,null,null
    --另一种方法
    select *,zong=chinese + math,
    px=(select count(1)+1 from tbl b where b.chinese + b.math >a.chinese + a.math )
    from tbl a order by px,chinese


    --创建存储过程
    create proc mysql
    as
    update bb set zong=tt.zong,px=tt.px from tbl bb,
    (SELECT name,zong , px=(SELECT COUNT(zong) FROM
    (
    select name,chinese,math,zong = chinese + math from tbl
    ) t
    WHERE zong > a.zong or (zong = a.zong and chinese > a.chinese)) + 1
    FROM
    (
    select name,chinese,math,zong = chinese + math from tbl
    ) a
    ) tt
    where bb.name=tt.name
    go
    --调用存储过程
    exec mysql
    --查看
    select * from tbl

    --删除
    drop table tbl
    drop proc mysql


    --创建表
    create table tb(ID int,TEAM varchar(10),SCORE int,SCORE2 int,SCORE3 int)
    insert into tb values(1, 'A ', 100 , 100 , 100)
    insert into tb values(2, 'A ', 90 , 100 , 100)
    insert into tb values(3, 'B ', 50 , 40 , 30 )
    insert into tb values(4, 'B ', 50 , 40 , 30)
    insert into tb values(5, 'A ', 90 , 100 , 80)
    insert into tb values(6, 'B ', 55 , 50 , 50)
    insert into tb values(7, 'A ', 90 , 100 , 50)

    --查询
    select *,px=(select count(1)+1 from tb
    where team=a.team and (score >a.score)
    or (score = a.score and score2 >a.score2)
    or (score = a.score and score2=a.score2 and score3 >a.score3)
    or (score = a.score and score2=a.score2 and score3=a.score3 and id <a.id))
    from tb a order by team

    --删除
    drop table tb

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  • 原文地址:https://www.cnblogs.com/caidupingblogs/p/5990504.html
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