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  • HDU 1686 Oulipo(优化的KMP)

    Oulipo

    Time Limit: 3000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)
    Total Submission(s): 17441    Accepted Submission(s): 6938


    Problem Description
    The French author Georges Perec (1936–1982) once wrote a book, La disparition, without the letter 'e'. He was a member of the Oulipo group. A quote from the book:

    Tout avait Pair normal, mais tout s’affirmait faux. Tout avait Fair normal, d’abord, puis surgissait l’inhumain, l’affolant. Il aurait voulu savoir où s’articulait l’association qui l’unissait au roman : stir son tapis, assaillant à tout instant son imagination, l’intuition d’un tabou, la vision d’un mal obscur, d’un quoi vacant, d’un non-dit : la vision, l’avision d’un oubli commandant tout, où s’abolissait la raison : tout avait l’air normal mais…

    Perec would probably have scored high (or rather, low) in the following contest. People are asked to write a perhaps even meaningful text on some subject with as few occurrences of a given “word” as possible. Our task is to provide the jury with a program that counts these occurrences, in order to obtain a ranking of the competitors. These competitors often write very long texts with nonsense meaning; a sequence of 500,000 consecutive 'T's is not unusual. And they never use spaces.

    So we want to quickly find out how often a word, i.e., a given string, occurs in a text. More formally: given the alphabet {'A', 'B', 'C', …, 'Z'} and two finite strings over that alphabet, a word W and a text T, count the number of occurrences of W in T. All the consecutive characters of W must exactly match consecutive characters of T. Occurrences may overlap.

     
    Input
    The first line of the input file contains a single number: the number of test cases to follow. Each test case has the following format:

    One line with the word W, a string over {'A', 'B', 'C', …, 'Z'}, with 1 ≤ |W| ≤ 10,000 (here |W| denotes the length of the string W).
    One line with the text T, a string over {'A', 'B', 'C', …, 'Z'}, with |W| ≤ |T| ≤ 1,000,000.
     
    Output
    For every test case in the input file, the output should contain a single number, on a single line: the number of occurrences of the word W in the text T.

     
    Sample Input
    3 BAPC BAPC AZA AZAZAZA VERDI AVERDXIVYERDIAN
     
    Sample Output
    1 3 0
     1 #include <iostream>
     2 #include<cstdio>
     3 #include<string>
     4 #include<cstring>
     5 int next[10001], num;
     6 char a[1000001], b[10001];
     7 int lena, lenb;
     8 void  get_next()//自身和自身比较,找某种特征
     9 {
    10     int i, j;
    11     i = 0; next[0] = -1; j = -1;
    12     while (i<lenb)
    13     {
    14         if (j == -1 || b[i] == b[j])//匹配成功的话,继续下一位
    15         {
    16             i++;
    17             j++;
    18             if (b[i] == b[j])
    19             {
    20                 next[i] = next[j];
    21             }
    22             else
    23             {
    24                 next[i] = j;
    25             }
    26         }
    27         else//否则返回到可以匹配的位置 
    28         {
    29             j = next[j];
    30         }
    31     }
    32 }
    33 void index_KMP()
    34 {
    35     int i, j;
    36     i = 0;
    37     j = 0;
    38     num = 0;
    39     while (i<lena)
    40     {
    41         if (a[i] == b[j] || j == -1) //进行两个字符串的匹配  
    42         {
    43             i++;//匹配成功,往后继续匹配  
    44             j++;
    45         }
    46         else//匹配完成一次,代表出现了一次,记录下来
    47         {
    48             j = next[j];
    49         }
    50         if (j == lenb)//匹配失败,寻找数组中可以匹配的位置  
    51         {
    52             num++;
    53             j = next[j];
    54         }
    55     }
    56     printf("%d
    ", num);
    57 }
    58 int main()
    59 {
    60     int n;
    61     while (scanf("%d", &n) != EOF)
    62     {
    63         getchar();
    64         while (n--)
    65         {
    66             gets(b);
    67             gets(a);
    68             lena = strlen(a);
    69             lenb = strlen(b);
    70             get_next();
    71             index_KMP();
    72         }
    73     }
    74     return 0;
    75 }
     
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  • 原文地址:https://www.cnblogs.com/caiyishuai/p/13271224.html
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