HDU 2602 Bone Collector

http://acm.hdu.edu.cn/showproblem.php?pid=2602

                              Bone Collector

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 32408    Accepted Submission(s): 13329

Problem Description

Many years ago , in Teddy’s hometown there was a man who was called “Bone Collector”. This man like to collect varies of bones , such as dog’s , cow’s , also he went to the grave … The bone collector had a big bag with a volume of V ,and along his trip of collecting there are a lot of bones , obviously , different bone has different value and different volume, now given the each bone’s value along his trip , can you calculate out the maximum of the total value the bone collector can get ?

 

Input

The first line contain a integer T , the number of cases. Followed by T cases , each case three lines , the first line contain two integer N , V, (N <= 1000 , V <= 1000 )representing the number of bones and the volume of his bag. And the second line contain N integers representing the value of each bone. The third line contain N integers representing the volume of each bone.

 

Output

One integer per line representing the maximum of the total value (this number will be less than 2³¹).

 

Sample Input

1 5 10 1 2 3 4 5 5 4 3 2 1

 

Sample Output

14

分析：

http://blog.csdn.net/dapengbusi/article/details/7463968

 

#include<iostream>
#include<cstdio>
#include<cstring>
using namespace std;
int v[1000],w[1005];
int n,c;
int f[1005][1005];//对于dp(i,j)就表示可选物品为i…n背包容量为j(总重量)时背包中所放物品的最大价值。
void backpack()
{
    int i,j;
    for(i=1;i<=n;i++)
      for(j=0;j<=c;j++)
      {
          if(i==1)
             f[i][j]=0;
          else
            f[i][j]=f[i-1][j];
         if(j>=v[i])
           f[i][j]=max(f[i][j],f[i-1][j-v[i]]+w[i]);
      }
    printf("%d
",f[n][c]);
}
int main()
{
   int t;
   scanf("%d",&t);
  while(t--)
  {
      int i;
     scanf("%d%d",&n,&c);
    for(i=1;i<=n;i++)
      scanf("%d",&w[i]);
    for(i=1;i<=n;i++)
      scanf("%d",&v[i]);
    backpack();
  }
 return 0;
}