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  • bzoj 4822: [Cqoi2017]老C的任务

    4822: [Cqoi2017]老C的任务

    练手速...

    #include <iostream>
    #include <cstdio>
    #include <cstring>
    #include <algorithm>
    using namespace std;
    typedef long long ll;
    const int N = 1e6+5;
    inline int read() {
        char c=getchar(); int x=0,f=1;
        while(c<'0' || c>'9') {if(c=='-')f=-1; c=getchar();}
        while(c>='0' && c<='9') {x=x*10+c-'0'; c=getchar();}
        return x*f;
    }
    
    int n, Q, mp[N], tot, x1, y1, x2, y2; ll ans[N];
    struct meow {
    	int x, y, type, qid; ll v;
    	bool operator <(const meow &a) const {return x == a.x ? type < a.type : x < a.x;}
    } q[N];
    namespace bit {
    	int n; ll c[N];
    	inline void add(int p, ll v) {for(; p<=n; p+=p&-p) c[p] += v;}
    	inline ll sum(int p) {ll ans = 0; for(; p; p-=p&-p) ans += c[p]; return ans;}
    }
    int main() {
    	freopen("in", "r", stdin);
    	n = read(); Q = read();
    	for(int i=1; i<=n; i++) 
    		mp[++mp[0]] = q[i].x = read(), mp[++mp[0]] = q[i].y = read(), q[i].v = read(), q[i].type = 0;
    	tot = n;
    	for(int i=1; i<=Q; i++) {
    		mp[++mp[0]] = x1 = read()-1; mp[++mp[0]] = y1 = read()-1;
    		mp[++mp[0]] = x2 = read();   mp[++mp[0]] = y2 = read();
    		tot++; q[tot] = (meow){x1, y1, 1, i, 1LL};
    		tot++; q[tot] = (meow){x2, y2, 1, i, 1LL};
    		tot++; q[tot] = (meow){x2, y1, 1, i, -1LL};
    		tot++; q[tot] = (meow){x1, y2, 1, i, -1LL};
    	}
    	sort(mp+1, mp+1+mp[0]); mp[0] = unique(mp+1, mp+1+mp[0]) - mp - 1;
    	for(int i=1; i<=tot; i++) {
    		q[i].x = lower_bound(mp+1, mp+1+mp[0], q[i].x) - mp;
    		q[i].y = lower_bound(mp+1, mp+1+mp[0], q[i].y) - mp;
    	}
    
    	sort(q+1, q+1+tot);
    	bit::n = mp[0];
    	for(int i=1; i<=tot; i++) {
    		if(q[i].type) ans[q[i].qid] += q[i].v * bit::sum(q[i].y);
    		else bit::add(q[i].y, q[i].v);
    	}
    	for(int i=1; i<=Q; i++) printf("%lld
    ", ans[i]);
    }
    
    
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  • 原文地址:https://www.cnblogs.com/candy99/p/6764757.html
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