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    树剖板子题……开战的话我们把深度比较深的那个点点权设为1,然后每次在一条路径上query即可。停战的话改回来。

    #include<cstdio>
    #include<algorithm>
    #include<cstring>
    #include<iostream>
    #include<cmath>
    #include<set>
    #include<queue>
    #define rep(i,a,n) for(int i = a;i <= n;i++)
    #define per(i,n,a) for(int i = n;i >= a;i--)
    #define enter putchar('
    ')
    
    using namespace std;
    typedef long long ll;
    const int M = 300005;
    const int INF = 1000000009;
    
    int read()
    {
        int ans = 0,op = 1;
        char ch = getchar();
        while(ch < '0' || ch > '9')
        {
        if(ch == '-') op = -1;
        ch = getchar();
        }
        while(ch >= '0' && ch <= '9')
        {
        ans *= 10;
        ans += ch - '0';
        ch = getchar();
        }
        return ans * op;
    }
    
    struct edge
    {
        int next,to;
    }e[M<<1];
    
    struct seg
    {
        int v;
    }t[M<<2];
    
    int n,m,p,q,dep[M],size[M],top[M],hson[M],head[M],dfn[M],war[M],ecnt,x,idx,cnt,fa[M];
    char s[5];
    
    void add(int x,int y)
    {
        e[++ecnt].to = y;
        e[ecnt].next = head[x];
        head[x] = ecnt;
    }
    
    int Max(int x,int y)
    {
        return (dep[x] > dep[y]) ? x : y;
    }
    
    void dfs1(int x,int f,int depth)
    {
        size[x] = 1,fa[x] = f,dep[x] = depth;
        int maxson = -1;
        for(int i = head[x];i;i = e[i].next)
        {
        if(e[i].to == f) continue;
        dfs1(e[i].to,x,depth+1);
        size[x] += size[e[i].to];
        if(size[e[i].to] > maxson) maxson = size[e[i].to],hson[x] = e[i].to;
        }
    }
    
    void dfs2(int x,int t)
    {
        top[x] = t,dfn[x] = ++idx;
        if(!hson[x]) return;
        dfs2(hson[x],t);
        for(int i = head[x];i;i = e[i].next)
        {
        if(e[i].to == fa[x] || e[i].to == hson[x]) continue;
        dfs2(e[i].to,e[i].to);
        }
    }
    
    void modify(int p,int l,int r,int pos,int val)
    {
        if(l == r)
        {
        t[p].v = val;
        return;
        }
        int mid = (l+r) >> 1;
        if(pos <= mid) modify(p<<1,l,mid,pos,val);
        else modify(p<<1|1,mid+1,r,pos,val);
        t[p].v = t[p<<1].v + t[p<<1|1].v;
    }
    
    int query(int p,int l,int r,int kl,int kr)
    {
        if(l == kl && r == kr) return t[p].v;
        int mid = (l+r) >> 1;
        if(kr <= mid) return query(p<<1,l,mid,kl,kr);
        else if(kl > mid) return query(p<<1|1,mid+1,r,kl,kr);
        else return query(p<<1,l,mid,kl,mid) + query(p<<1|1,mid+1,r,mid+1,kr);
    }
    
    void mrange(int x,int y)
    {
        while(top[x] != top[y])
        {
        if(dep[top[x]] < dep[top[y]]) swap(x,y);
        int g = query(1,1,n,dfn[top[x]],dfn[x]);
        if(g)
        {
            printf("No
    ");
            return;
        }
        x = fa[top[x]];
        }
        if(dep[x] > dep[y]) swap(x,y);
        if(dfn[x] + 1 > dfn[y])
        {
        printf("Yes
    ");
        return;
        }
        int g = query(1,1,n,dfn[x]+1,dfn[y]);
        g ? printf("No
    ") : printf("Yes
    ");
    }
    
    int main()
    {
        n = read(),m = read();
        rep(i,1,n-1) p = read(),q = read(),add(p,q),add(q,p);
        dfs1(1,1,0),dfs2(1,1);
        rep(i,1,m)
        {
        scanf("%s",s);
        if(s[0] == 'Q') p = read(),q = read(),mrange(p,q);
        else if(s[0] == 'C') p = read(),q = read(),modify(1,1,n,dfn[Max(p,q)],1),war[++cnt] = Max(p,q);
        else if(s[0] == 'U') x = read(),modify(1,1,n,dfn[war[x]],0);
        }
        return 0;
    }
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  • 原文地址:https://www.cnblogs.com/captain1/p/9756952.html
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