AC代码：
import java.util.*;
/**
* @author CC11001100
*/
public class Main {
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
String s = sc.nextLine();
System.out.println(toPinYin(sum(s)));
}
private static int sum(String s){
int res = 0;
for(int i=0; i<s.length(); i++){
res += s.charAt(i) - '0';
}
return res;
}
private static Map<Integer, String> map = new HashMap<>();
static{
map.put(0, "ling");
map.put(1, "yi");
map.put(2, "er");
map.put(3, "san");
map.put(4, "si");
map.put(5, "wu");
map.put(6, "liu");
map.put(7, "qi");
map.put(8, "ba");
map.put(9, "jiu");
}
private static String toPinYin(int n){
if(n<=9) return map.get(n);
else return toPinYin(n/10) + " " + map.get(n % 10);
}
}
或者可以使用数组下标来对应，就不用map了，也是能够随机访问取到：
import java.util.*;
/**
* @author CC11001100
*/
public class Main {
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
String s = sc.nextLine();
System.out.println(toPinYin(sum(s)));
}
private static int sum(String s){
int res = 0;
for(int i=0; i<s.length(); i++){
res += s.charAt(i) - '0';
}
return res;
}
private static String[] mapping = new String[]{"ling", "yi", "er", "san", "si", "wu", "liu", "qi", "ba", "jiu" };
private static String toPinYin(int n){
if(n<=9) return mapping[n];
else return toPinYin(n/10) + " " + mapping[n%10];
}
}
题目来源： https://www.nowcoder.com/pat/2/problem/4068
.