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  • 牛客网编程练习之PAT乙级(Basic Level):1034 写出这个数

    题目描述

    AC代码:

    import java.util.*;
    
    /**
     * @author CC11001100
     */
    public class Main {
    
    	public static void main(String[] args) {
    
    		Scanner sc = new Scanner(System.in);
    		String s = sc.nextLine();
    		System.out.println(toPinYin(sum(s)));
    
    	}
    
    	private static int sum(String s){
    		int res = 0;
    		for(int i=0; i<s.length(); i++){
    			res += s.charAt(i) - '0';
    		}
    		return res;
    	}
    
    	private static Map<Integer, String> map = new HashMap<>();
    
    	static{
    		map.put(0, "ling");
    		map.put(1, "yi");
    		map.put(2, "er");
    		map.put(3, "san");
    		map.put(4, "si");
    		map.put(5, "wu");
    		map.put(6, "liu");
    		map.put(7, "qi");
    		map.put(8, "ba");
    		map.put(9, "jiu");
    	}
    
    	private static String toPinYin(int n){
    		if(n<=9) return map.get(n);
    		else return toPinYin(n/10) + " " + map.get(n % 10);
    	}
    
    }

    或者可以使用数组下标来对应,就不用map了,也是能够随机访问取到:

    import java.util.*;
    
    /**
     * @author CC11001100
     */
    public class Main {
    
    	public static void main(String[] args) {
    
    		Scanner sc = new Scanner(System.in);
    		String s = sc.nextLine();
    		System.out.println(toPinYin(sum(s)));
    
    	}
    
    	private static int sum(String s){
    		int res = 0;
    		for(int i=0; i<s.length(); i++){
    			res += s.charAt(i) - '0';
    		}
    		return res;
    	}
    
    	private static String[] mapping = new String[]{"ling", "yi", "er", "san", "si", "wu", "liu", "qi", "ba", "jiu" };
    
    	private static String toPinYin(int n){
    		if(n<=9) return mapping[n];
    		else return toPinYin(n/10) + " " + mapping[n%10];
    	}
    
    }
    

    题目来源: https://www.nowcoder.com/pat/2/problem/4068

    .

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  • 原文地址:https://www.cnblogs.com/cc11001100/p/8019444.html
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