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  • 杭电ACM1001

    原题:http://acm.hdu.edu.cn/showproblem.php?pid=1001

     1 #include <stdio.h>
     2 
     3 int main(void)
     4 {
     5     int i,n,sum;
     6     sum = 0;
     7     while(scanf("%d",&n)!=EOF)
     8     {
     9         sum=0;
    10         for (i=0;i<=n;i++)
    11             sum+=i;
    12         printf("%d
    
    ",sum);
    13     }
    14     return 0;
    15 }

    Sum Problem

    Time Limit: 1000/500 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)
    Total Submission(s): 416900    Accepted Submission(s): 105068


    Problem Description
    Hey, welcome to HDOJ(Hangzhou Dianzi University Online Judge).

    In this problem, your task is to calculate SUM(n) = 1 + 2 + 3 + ... + n.
     
    Input
    The input will consist of a series of integers n, one integer per line.
     
    Output
    For each case, output SUM(n) in one line, followed by a blank line. You may assume the result will be in the range of 32-bit signed integer.
     
    Sample Input
    1 100
     
    Sample Output
    1 5050
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  • 原文地址:https://www.cnblogs.com/cccczh/p/5754094.html
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