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  • 基础计算几何

    推荐博客 :https://blog.csdn.net/jjj19891128/article/details/22685605

         https://blog.csdn.net/jq_develop/article/details/44981127

    结构体的定义

    struct point
    {
        double x, y;
        point(double _x=0, double _y=0):x(_x), y(_y){}
        
        // 点-点=向量
        point operator-(const point &v){
            return point(x-v.x, y-v.y);
        }
    
    };
    
    int dcmp(double x){
        if (fabs(x)<eps) return 0;
        else return x<0?-1:1;
    }
    bool operator == (const point &a, const point &b){
        return (dcmp(a.x-b.x)==0 && dcmp(a.y-b.y)==0); 
    }
    
    typedef point Vector; // Vector表示向量
    

    //点积
    double Dot(Vector a, Vector b){return a.x*b.x+a.y*b.y;}
    
    //线段的长度
    double Lenth(Vector a){return sqrt(Dot(a, a));}
    
    //向量的夹角(弧度)
    double Angle(Vector a, Vector b){return acos(Dot(a, b)/Lenth(a)/Lenth(b));}
    
    //叉积
    double Cross(Vector a, Vector b){return a.x*b.y-a.y*b.x;}
    
    //三角形有向面积的2倍
    double Area2(point a, point b, point c){return Cross(b-a, c-a);}
    
    //向量旋转,a为逆时针旋转的角度
    // rad是弧度
    point Rotate(Vector a, double rad){
        return point(a.x*cos(rad)-a.y*sin(rad), a.x*sin(rad)+a.y*cos(rad));
    }
    
    //计算向量的单位法线
    point Normal(Vector a){
        double L = Lenth(a);
        return point(-a.y/L, a.x/L);
    }
    

     直线

    // 两条直线的交点
    // 两条直线为 p+tv, q+tw,其中p, q为两直线上的一点, v,w是直线所在方向的向量,
    // 交点在第一条直线的参数为t1, 第二条直线的参数为t2
    // t1 = (cross(w,u)/cross(v,w));  t2 = (cross(v,u)/cross(v,w));
    // 调用前要确保两直线有唯一交点,当且仅当两直线不共线
    point Getline(point p, Vector v, point q, Vector w){
        point u = p-q;
        double t = Cross(w, u)/Cross(v, w);
        return point(p.x+v.x*t, p.y+v.y*t);
    }
    
    //点到直线的距离
    double Dis(point p, point a, point b){
        Vector v1 = b-a, v2 = p-a;
        return fabs(Cross(v1, v2)/Lenth(v1));
    }
    
    //点到线段的距离
    //点p在直线的投影可能在直线上,也可能不在直线上
    double Dis2(point p, point a, point b){
        if (a==b) return Lenth(p-a);
        Vector v1=b-a, v2 = p-a, v3=p-b;
        if (dcmp(Dot(v1, v2))<0) return Lenth(v2); // 注意大小于号
        if (dcmp(Dot(v1, v3))>0) return Lenth(v3);
        else return fabs(Cross(v1, v2)/Lenth(v1));
    }
    
    //点在线段上的投影
    point Getline2(point p, point a, point b){
        Vector v = b-a;
        double f = Dot(v, p-a)/Dot(v, v);
        return point(a.x+v.x*f, a.y+v.y*f);
    }
    
    //线段相交判定(交点不在端点的位置,且两直线仅有唯一交点)
    bool Inter(point a1, point a2, point b1, point b2){
        double c1 = Cross(a2-a1, b1-a1), c2 = Cross(a2-a1, b2-a1),
               c3 = Cross(b2-b1, a1-b1), c4 = Cross(b2-b1, a2-b1);
        return dcmp(c1)*dcmp(c2)<0 && dcmp(c3)*dcmp(c4)<0;
    }
    
    //线段相交判定,交点可以在一条直线端点位置(交点不在两直线端点得位置)
    //若将末尾的 < 0改成 <= 0,则表示的意义是点恰好在直线的一个端点的位置处  !!!
    bool OneInter(point p, point a1, point a2){
        return dcmp(Cross(a1-p, a2-p))==0 && dcmp(Dot(a1-p, a2-p))<0;
    }
    // 视题目要求是否特判两直线有端点重合的情况
    

    多边形

    //多边形面积(有方向)
    vector<point>ve;
    double ConvexArea(int n){
        double area = 0;
        for(int i = 1; i < n-1; i++){
            area += Cross(ve[i]-ve[0], ve[i+1]-ve[0]);
        }
        return area/2;
    }
    
    //判断点是否在多边形内部
    //射线法,从所要判断的点引一条射线,判断与多边形的交点是入点还是出点,+1、-1
    int Ispointinpolygon(point po){
        int wn = 0;
        p[n] = p[0];
        for(int i = 0; i < n; i++){
            if (OneInter(po, p[i], p[i+1]) || po==p[i]) return -1; //边界
            int k = dcmp(Cross(p[i+1]-p[i], po-p[i]));
            int d1 = dcmp(p[i].y-po.y);
            int d2 = dcmp(p[i+1].y-po.y);
            if (k>0 && d1 <= 0 && d2>0) wn++; 
            if (k<0 && d2 <= 0 && d1>0) wn--; 
        }
        if (wn != 0) return 1; //内部
        return 0; //外部
    }
    

    //过三点求圆心坐标
    point yuanxin(point a, point b, point c){
        double a1 = b.x-a.x, b1 = b.y-a.y, c1 = (a1*a1+b1*b1)/2;
        double a1 = c.x-a.x, b2 = c.y-a.y, c2 = (a2*a2+b2*b2)/2;
        double d = a1*b2-a2*b1;
        
        return point(a.x+(c1*b2-c2*b1)/d, a.y+(a1*c2-a2*c1)/d);
    }
    
    //两个圆公共部分面积
    double Area_yuan(point c1, double r1, point c2, double r2){
        double d = Lenth(c1, c2);
        if (r1+r2 < d+eps) return 0;
        if (d < fabs(r1-r2)+eps){
            double r = min(r1, r2);
            return pi*r*r;
        }
        double x = (d*d+r1*r1-r2*r2)/(2*d);
        double t1 = acos(x/r1);
        double t2 = acos((d-x)/r2);
        return r1*r1*t1+r2*r2*t2-d*r1*sin(t1);
    }
    

    整体一起

    const double eps = 1e-10;
    const double pi = acos(-1.0);
    
    struct point
    {
        double x, y;
        point(double _x=0, double _y=0):x(_x), y(_y){}
        
        // 点-点=向量
        point operator-(const point &v){
            return point(x-v.x, y-v.y);
        }
    
    };
    
    int dcmp(double x){
        if (fabs(x)<eps) return 0;
        else return x<0?-1:1;
    }
    bool operator == (const point &a, const point &b){
        return (dcmp(a.x-b.x)==0 && dcmp(a.y-b.y)==0); 
    }
    
    typedef point Vector; // Vector表示向量
    
    //点积
    double Dot(Vector a, Vector b){return a.x*b.x+a.y*b.y;}
    
    //线段的长度
    double Lenth(Vector a){return sqrt(Dot(a, a));}
    
    //向量的夹角(弧度)
    double Angle(Vector a, Vector b){return acos(Dot(a, b)/Lenth(a)/Lenth(b));}
    
    //叉积
    double Cross(Vector a, Vector b){return a.x*b.y-a.y*b.x;}
    
    //三角形有向面积的2倍
    double Area2(point a, point b, point c){return Cross(b-a, c-a);}
    
    //向量旋转,a为逆时针旋转的角度
    // rad是弧度
    point Rotate(Vector a, double rad){
        return point(a.x*cos(rad)-a.y*sin(rad), a.x*sin(rad)+a.y*cos(rad));
    }
    
    //计算向量的单位法线
    point Normal(Vector a){
        double L = Lenth(a);
        return point(-a.y/L, a.x/L);
    }
    
    // 两条直线的交点
    // 两条直线为 p+tv, q+tw,其中p, q为两直线上的一点, v,w是直线所在方向的向量,
    // 交点在第一条直线的参数为t1, 第二条直线的参数为t2
    // t1 = (cross(w,u)/cross(v,w));  t2 = (cross(v,u)/cross(v,w));
    // 调用前要确保两直线有唯一交点,当且仅当两直线不共线
    point Getline(point p, Vector v, point q, Vector w){
        point u = p-q;
        double t = Cross(w, u)/Cross(v, w);
        return point(p.x+v.x*t, p.y+v.y*t);
    }
    
    //点到直线的距离
    double Dis(point p, point a, point b){
        Vector v1 = b-a, v2 = p-a;
        return fabs(Cross(v1, v2)/Lenth(v1));
    }
    
    //点到线段的距离
    //点p在直线的投影可能在直线上,也可能不在直线上
    double Dis2(point p, point a, point b){
        if (a==b) return Lenth(p-a);
        Vector v1=b-a, v2 = p-a, v3=p-b;
        if (dcmp(Dot(v1, v2))<0) return Lenth(v2); // 注意大小于号
        if (dcmp(Dot(v1, v3))>0) return Lenth(v3);
        else return fabs(Cross(v1, v2)/Lenth(v1));
    }
    
    //点在线段上的投影
    point Getline2(point p, point a, point b){
        Vector v = b-a;
        double f = Dot(v, p-a)/Dot(v, v);
        return point(a.x+v.x*f, a.y+v.y*f);
    }
    
    //线段相交判定(交点不在端点的位置,且两直线仅有唯一交点)
    bool Inter(point a1, point a2, point b1, point b2){
        double c1 = Cross(a2-a1, b1-a1), c2 = Cross(a2-a1, b2-a1),
               c3 = Cross(b2-b1, a1-b1), c4 = Cross(b2-b1, a2-b1);
        return dcmp(c1)*dcmp(c2)<0 && dcmp(c3)*dcmp(c4)<0;
    }
    //线段相交判定,交点可以在一条直线端点位置(交点不在两直线端点得位置)
    bool OneInter(point p, point a1, point a2){
        return dcmp(Cross(a1-p, a2-p))==0 && dcmp(Dot(a1-p, a2-p))<0;
    }
    // 视题目要求是否特判两直线有端点重合的情况
    
    //多边形面积(有方向)
    vector<point>ve;
    double ConvexArea(int n){
        double area = 0;
        for(int i = 1; i < n-1; i++){
            area += Cross(ve[i]-ve[0], ve[i+1]-ve[0]);
        }
        return area/2;
    }
    
    //判断点是否在多边形内部
    //射线法,从所要判断的点引一条射线,判断与多边形的交点是入点还是出点,+1、-1
    int Ispointinpolygon(point po){
        int wn = 0;
        p[n] = p[0];
        for(int i = 0; i < n; i++){
            if (OneInter(po, p[i], p[i+1]) || po==p[i]) return -1; //边界
            int k = dcmp(Cross(p[i+1]-p[i], po-p[i]));
            int d1 = dcmp(p[i].y-po.y);
            int d2 = dcmp(p[i+1].y-po.y);
            if (k>0 && d1 <= 0 && d2>0) wn++; //内部
            if (k<0 && d2 <= 0 && d1>0) wn--; //外部
        }
        return wn != 0;
    }
    

    jls 的几何板子

    #define mp make_pair
    #define fi first
    #define se second
    #define pb push_back
    typedef double db;
    const db eps=1e-6;
    const db pi=acos(-1);
    int sign(db k){
        if (k>eps) return 1; else if (k<-eps) return -1; return 0;
    }
    int cmp(db k1,db k2){return sign(k1-k2);}
    int inmid(db k1,db k2,db k3){return sign(k1-k3)*sign(k2-k3)<=0;}// k3 在 [k1,k2] 内 
    struct point{
        db x,y;
        point operator + (const point &k1) const{return (point){k1.x+x,k1.y+y};}
        point operator - (const point &k1) const{return (point){x-k1.x,y-k1.y};}
        point operator * (db k1) const{return (point){x*k1,y*k1};}
        point operator / (db k1) const{return (point){x/k1,y/k1};}
        int operator == (const point &k1) const{return cmp(x,k1.x)==0&&cmp(y,k1.y)==0;}
        // 逆时针旋转 
        point turn(db k1){return (point){x*cos(k1)-y*sin(k1),x*sin(k1)+y*cos(k1)};}
        point turn90(){return (point){-y,x};}
        bool operator < (const point k1) const{
            int a=cmp(x,k1.x);
            if (a==-1) return 1; else if (a==1) return 0; else return cmp(y,k1.y)==-1;
        }
        db abs(){return sqrt(x*x+y*y);}
        db abs2(){return x*x+y*y;}
        db dis(point k1){return ((*this)-k1).abs();}
        point unit(){db w=abs(); return (point){x/w,y/w};}
        void scan(){double k1,k2; scanf("%lf%lf",&k1,&k2); x=k1; y=k2;}
        void print(){printf("%.11lf %.11lf
    ",x,y);}
        db getw(){return atan2(y,x);} 
        point getdel(){if (sign(x)==-1||(sign(x)==0&&sign(y)==-1)) return (*this)*(-1); else return (*this);}
    	int getP() const{return sign(y)==1||(sign(y)==0&&sign(x)==-1);}
    };
    int inmid(point k1,point k2,point k3){return inmid(k1.x,k2.x,k3.x)&&inmid(k1.y,k2.y,k3.y);}
    db cross(point k1,point k2){return k1.x*k2.y-k1.y*k2.x;}
    db dot(point k1,point k2){return k1.x*k2.x+k1.y*k2.y;}
    db rad(point k1,point k2){return atan2(cross(k1,k2),dot(k1,k2));}
    // -pi -> pi
    int compareangle (point k1,point k2){
        return k1.getP()<k2.getP()||(k1.getP()==k2.getP()&&sign(cross(k1,k2))>0);
    }
    point proj(point k1,point k2,point q){ // q 到直线 k1,k2 的投影 
        point k=k2-k1; return k1+k*(dot(q-k1,k)/k.abs2());
    }
    point reflect(point k1,point k2,point q){return proj(k1,k2,q)*2-q;}
    int clockwise(point k1,point k2,point k3){// k1 k2 k3 逆时针 1 顺时针 -1 否则 0  
        return sign(cross(k2-k1,k3-k1));
    }
    int checkLL(point k1,point k2,point k3,point k4){// 求直线 (L) 线段 (S)k1,k2 和 k3,k4 的交点 
        return cmp(cross(k3-k1,k4-k1),cross(k3-k2,k4-k2))!=0;
    }
    point getLL(point k1,point k2,point k3,point k4){
        db w1=cross(k1-k3,k4-k3),w2=cross(k4-k3,k2-k3); return (k1*w2+k2*w1)/(w1+w2);
    }
    int intersect(db l1,db r1,db l2,db r2){
        if (l1>r1) swap(l1,r1); if (l2>r2) swap(l2,r2); return cmp(r1,l2)!=-1&&cmp(r2,l1)!=-1;
    }
    int checkSS(point k1,point k2,point k3,point k4){
        return intersect(k1.x,k2.x,k3.x,k4.x)&&intersect(k1.y,k2.y,k3.y,k4.y)&&
        sign(cross(k3-k1,k4-k1))*sign(cross(k3-k2,k4-k2))<=0&&
        sign(cross(k1-k3,k2-k3))*sign(cross(k1-k4,k2-k4))<=0;
    }
    db disSP(point k1,point k2,point q){
        point k3=proj(k1,k2,q);
        if (inmid(k1,k2,k3)) return q.dis(k3); else return min(q.dis(k1),q.dis(k2));
    }
    db disSS(point k1,point k2,point k3,point k4){
        if (checkSS(k1,k2,k3,k4)) return 0;
        else return min(min(disSP(k1,k2,k3),disSP(k1,k2,k4)),min(disSP(k3,k4,k1),disSP(k3,k4,k2)));
    }
    int onS(point k1,point k2,point q){return inmid(k1,k2,q)&&sign(cross(k1-q,k2-k1))==0;}
    struct circle{
        point o; db r;
        void scan(){o.scan(); scanf("%lf",&r);}
        int inside(point k){return cmp(r,o.dis(k));}
    };
    struct line{
        // p[0]->p[1]
        point p[2];
        line(point k1,point k2){p[0]=k1; p[1]=k2;}
        point& operator [] (int k){return p[k];}
        int include(point k){return sign(cross(p[1]-p[0],k-p[0]))>0;}
        point dir(){return p[1]-p[0];}
        line push(){ // 向外 ( 左手边 ) 平移 eps 
            const db eps = 1e-6;
            point delta=(p[1]-p[0]).turn90().unit()*eps;
            return {p[0]-delta,p[1]-delta};
        }
    };
    point getLL(line k1,line k2){return getLL(k1[0],k1[1],k2[0],k2[1]);}
    int parallel(line k1,line k2){return sign(cross(k1.dir(),k2.dir()))==0;}
    int sameDir(line k1,line k2){return parallel(k1,k2)&&sign(dot(k1.dir(),k2.dir()))==1;}
    int operator < (line k1,line k2){
        if (sameDir(k1,k2)) return k2.include(k1[0]); 
        return compareangle(k1.dir(),k2.dir());
    }
    int checkpos(line k1,line k2,line k3){return k3.include(getLL(k1,k2));}
    vector<line> getHL(vector<line> &L){ // 求半平面交 , 半平面是逆时针方向 , 输出按照逆时针
        sort(L.begin(),L.end()); deque<line> q;
        for (int i=0;i<(int)L.size();i++){
            if (i&&sameDir(L[i],L[i-1])) continue;
            while (q.size()>1&&!checkpos(q[q.size()-2],q[q.size()-1],L[i])) q.pop_back();
            while (q.size()>1&&!checkpos(q[1],q[0],L[i])) q.pop_front();
            q.push_back(L[i]);
        }
        while (q.size()>2&&!checkpos(q[q.size()-2],q[q.size()-1],q[0])) q.pop_back();
        while (q.size()>2&&!checkpos(q[1],q[0],q[q.size()-1])) q.pop_front();
        vector<line>ans; for (int i=0;i<q.size();i++) ans.push_back(q[i]);
        return ans;
    }
    db closepoint(vector<point>&A,int l,int r){ // 最近点对 , 先要按照 x 坐标排序 
        if (r-l<=5){
            db ans=1e20;
            for (int i=l;i<=r;i++) for (int j=i+1;j<=r;j++) ans=min(ans,A[i].dis(A[j]));
            return ans;
        }
        int mid=l+r>>1; db ans=min(closepoint(A,l,mid),closepoint(A,mid+1,r));
        vector<point>B; for (int i=l;i<=r;i++) if (abs(A[i].x-A[mid].x)<=ans) B.push_back(A[i]);
        sort(B.begin(),B.end(),[](point k1,point k2){return k1.y<k2.y;});
        for (int i=0;i<B.size();i++) for (int j=i+1;j<B.size()&&B[j].y-B[i].y<ans;j++) ans=min(ans,B[i].dis(B[j]));
        return ans;
    }
    int checkposCC(circle k1,circle k2){// 返回两个圆的公切线数量
        if (cmp(k1.r,k2.r)==-1) swap(k1,k2);
        db dis=k1.o.dis(k2.o);  int w1=cmp(dis,k1.r+k2.r),w2=cmp(dis,k1.r-k2.r);
        if (w1>0) return 4; else if (w1==0) return 3; else if (w2>0) return 2; 
        else if (w2==0) return 1; else return 0;
    }
    vector<point> getCL(circle k1,point k2,point k3){ // 沿着 k2->k3 方向给出 , 相切给出两个 
        point k=proj(k2,k3,k1.o); db d=k1.r*k1.r-(k-k1.o).abs2();
        if (sign(d)==-1) return {};
        point del=(k3-k2).unit()*sqrt(max((db)0.0,d)); return {k-del,k+del};
    }
    vector<point> getCC(circle k1,circle k2){// 沿圆 k1 逆时针给出 , 相切给出两个 
        int pd=checkposCC(k1,k2); if (pd==0||pd==4) return {};
        db a=(k2.o-k1.o).abs2(),cosA=(k1.r*k1.r+a-k2.r*k2.r)/(2*k1.r*sqrt(max(a,(db)0.0)));
        db b=k1.r*cosA,c=sqrt(max((db)0.0,k1.r*k1.r-b*b));
        point k=(k2.o-k1.o).unit(),m=k1.o+k*b,del=k.turn90()*c;
        return {m-del,m+del};
    } 
    vector<point> TangentCP(circle k1,point k2){// 沿圆 k1 逆时针给出 
        db a=(k2-k1.o).abs(),b=k1.r*k1.r/a,c=sqrt(max((db)0.0,k1.r*k1.r-b*b));
        point k=(k2-k1.o).unit(),m=k1.o+k*b,del=k.turn90()*c;
        return {m-del,m+del};
    } 
    vector<line> TangentoutCC(circle k1,circle k2){
        int pd=checkposCC(k1,k2); if (pd==0) return {}; 
        if (pd==1){point k=getCC(k1,k2)[0]; return {(line){k,k}};}
        if (cmp(k1.r,k2.r)==0){
            point del=(k2.o-k1.o).unit().turn90().getdel();
            return {(line){k1.o-del*k1.r,k2.o-del*k2.r},(line){k1.o+del*k1.r,k2.o+del*k2.r}};
        } else {
            point p=(k2.o*k1.r-k1.o*k2.r)/(k1.r-k2.r);
            vector<point>A=TangentCP(k1,p),B=TangentCP(k2,p);
            vector<line>ans; for (int i=0;i<A.size();i++) ans.push_back((line){A[i],B[i]}); 
            return ans;
        }
    }
    vector<line> TangentinCC(circle k1,circle k2){
        int pd=checkposCC(k1,k2); if (pd<=2) return {};
        if (pd==3){point k=getCC(k1,k2)[0]; return {(line){k,k}};} 
        point p=(k2.o*k1.r+k1.o*k2.r)/(k1.r+k2.r);
        vector<point>A=TangentCP(k1,p),B=TangentCP(k2,p);
        vector<line>ans; for (int i=0;i<A.size();i++) ans.push_back((line){A[i],B[i]}); 
        return ans;
    }
    vector<line> TangentCC(circle k1,circle k2){
        int flag=0; if (k1.r<k2.r) swap(k1,k2),flag=1;
        vector<line>A=TangentoutCC(k1,k2),B=TangentinCC(k1,k2);
        for (line k:B) A.push_back(k); 
        if (flag) for (line &k:A) swap(k[0],k[1]);
        return A;
    }
    db getarea(circle k1,point k2,point k3){
        // 圆 k1 与三角形 k2 k3 k1.o 的有向面积交
        point k=k1.o; k1.o=k1.o-k; k2=k2-k; k3=k3-k;
        int pd1=k1.inside(k2),pd2=k1.inside(k3); 
        vector<point>A=getCL(k1,k2,k3);
        if (pd1>=0){
            if (pd2>=0) return cross(k2,k3)/2;
            return k1.r*k1.r*rad(A[1],k3)/2+cross(k2,A[1])/2;
        } else if (pd2>=0){ 
            return k1.r*k1.r*rad(k2,A[0])/2+cross(A[0],k3)/2;
        }else {
            int pd=cmp(k1.r,disSP(k2,k3,k1.o));
            if (pd<=0) return k1.r*k1.r*rad(k2,k3)/2;
            return cross(A[0],A[1])/2+k1.r*k1.r*(rad(k2,A[0])+rad(A[1],k3))/2;
        }
    }
    circle getcircle(point k1,point k2,point k3){
        db a1=k2.x-k1.x,b1=k2.y-k1.y,c1=(a1*a1+b1*b1)/2;
        db a2=k3.x-k1.x,b2=k3.y-k1.y,c2=(a2*a2+b2*b2)/2;
        db d=a1*b2-a2*b1;
        point o=(point){k1.x+(c1*b2-c2*b1)/d,k1.y+(a1*c2-a2*c1)/d};
        return (circle){o,k1.dis(o)};
    }
    circle getScircle(vector<point> A){
        random_shuffle(A.begin(),A.end());
        circle ans=(circle){A[0],0};
        for (int i=1;i<A.size();i++)
            if (ans.inside(A[i])==-1){
                ans=(circle){A[i],0};
                for (int j=0;j<i;j++)
                    if (ans.inside(A[j])==-1){
                        ans.o=(A[i]+A[j])/2; ans.r=ans.o.dis(A[i]);
                        for (int k=0;k<j;k++)
                            if (ans.inside(A[k])==-1)
                                ans=getcircle(A[i],A[j],A[k]);
                    }
            }
        return ans;
    }
    db area(vector<point> A){ // 多边形用 vector<point> 表示 , 逆时针 
        db ans=0;
        for (int i=0;i<A.size();i++) ans+=cross(A[i],A[(i+1)%A.size()]);
        return ans/2;
    }
    int checkconvex(vector<point>A){
        int n=A.size(); A.push_back(A[0]); A.push_back(A[1]);
        for (int i=0;i<n;i++) if (sign(cross(A[i+1]-A[i],A[i+2]-A[i]))==-1) return 0;
        return 1;
    }
    int contain(vector<point>A,point q){ // 2 内部 1 边界 0 外部
        int pd=0; A.push_back(A[0]);
        for (int i=1;i<A.size();i++){
            point u=A[i-1],v=A[i];
            if (onS(u,v,q)) return 1; if (cmp(u.y,v.y)>0) swap(u,v);
            if (cmp(u.y,q.y)>=0||cmp(v.y,q.y)<0) continue;
            if (sign(cross(u-v,q-v))<0) pd^=1;
        }
        return pd<<1;
    }
    vector<point> ConvexHull(vector<point>A,int flag=1){ // flag=0 不严格 flag=1 严格 
        int n=A.size(); vector<point>ans(n*2); 
        sort(A.begin(),A.end()); int now=-1;
        for (int i=0;i<A.size();i++){
            while (now>0&&sign(cross(ans[now]-ans[now-1],A[i]-ans[now-1]))<flag) now--;
            ans[++now]=A[i];
        } int pre=now;
        for (int i=n-2;i>=0;i--){
            while (now>pre&&sign(cross(ans[now]-ans[now-1],A[i]-ans[now-1]))<flag) now--;
            ans[++now]=A[i];
        } ans.resize(now); return ans;
    }
    db convexDiameter(vector<point>A){
        int now=0,n=A.size(); db ans=0;
        for (int i=0;i<A.size();i++){
            now=max(now,i);
            while (1){
                db k1=A[i].dis(A[now%n]),k2=A[i].dis(A[(now+1)%n]);
                ans=max(ans,max(k1,k2)); if (k2>k1) now++; else break;
            }
        }
        return ans;
    }
    vector<point> convexcut(vector<point>A,point k1,point k2){
        // 保留 k1,k2,p 逆时针的所有点
        int n=A.size(); A.push_back(A[0]); vector<point>ans;
        for (int i=0;i<n;i++){
            int w1=clockwise(k1,k2,A[i]),w2=clockwise(k1,k2,A[i+1]);
            if (w1>=0) ans.push_back(A[i]);
            if (w1*w2<0) ans.push_back(getLL(k1,k2,A[i],A[i+1]));
        }
        return ans;
    }
    int checkPoS(vector<point>A,point k1,point k2){
        // 多边形 A 和直线 ( 线段 )k1->k2 严格相交 , 注释部分为线段
        struct ins{
            point m,u,v;
            int operator < (const ins& k) const {return m<k.m;}
        }; vector<ins>B;
        //if (contain(A,k1)==2||contain(A,k2)==2) return 1;
        vector<point>poly=A; A.push_back(A[0]); 
        for (int i=1;i<A.size();i++) if (checkLL(A[i-1],A[i],k1,k2)){
            point m=getLL(A[i-1],A[i],k1,k2); 
            if (inmid(A[i-1],A[i],m)/*&&inmid(k1,k2,m)*/) B.push_back((ins){m,A[i-1],A[i]});
        }
        if (B.size()==0) return 0; sort(B.begin(),B.end()); 
        int now=1; while (now<B.size()&&B[now].m==B[0].m) now++; 
        if (now==B.size()) return 0;
        int flag=contain(poly,(B[0].m+B[now].m)/2);
        if (flag==2) return 1;
        point d=B[now].m-B[0].m;
        for (int i=now;i<B.size();i++){
            if (!(B[i].m==B[i-1].m)&&flag==2) return 1;
            int tag=sign(cross(B[i].v-B[i].u,B[i].m+d-B[i].u));
            if (B[i].m==B[i].u||B[i].m==B[i].v) flag+=tag; else flag+=tag*2;
        }
        //return 0;
        return flag==2;
    }
    int checkinp(point r,point l,point m){
    	if (compareangle(l,r)){return compareangle(l,m)&&compareangle(m,r);}
    	return compareangle(l,m)||compareangle(m,r);
    }
    int checkPosFast(vector<point>A,point k1,point k2){ // 快速检查线段是否和多边形严格相交
    	if (contain(A,k1)==2||contain(A,k2)==2) return 1; if (k1==k2) return 0;
    	A.push_back(A[0]); A.push_back(A[1]);
    	for (int i=1;i+1<A.size();i++)
    		if (checkLL(A[i-1],A[i],k1,k2)){
    			point now=getLL(A[i-1],A[i],k1,k2);
    			if (inmid(A[i-1],A[i],now)==0||inmid(k1,k2,now)==0) continue;
    			if (now==A[i]){
    				if (A[i]==k2) continue;
    				point pre=A[i-1],ne=A[i+1];
    				if (checkinp(pre-now,ne-now,k2-now)) return 1;
    			} else if (now==k1){
    				if (k1==A[i-1]||k1==A[i]) continue;
    				if (checkinp(A[i-1]-k1,A[i]-k1,k2-k1)) return 1;
    			} else if (now==k2||now==A[i-1]) continue;
    			else return 1;
    		}
    	return 0;
    }
    // 拆分凸包成上下凸壳 凸包尽量都随机旋转一个角度来避免出现相同横坐标 
    // 尽量特判只有一个点的情况 凸包逆时针
    void getUDP(vector<point>A,vector<point>&U,vector<point>&D){
        db l=1e100,r=-1e100;
        for (int i=0;i<A.size();i++) l=min(l,A[i].x),r=max(r,A[i].x);
        int wherel,wherer;
        for (int i=0;i<A.size();i++) if (cmp(A[i].x,l)==0) wherel=i;
        for (int i=A.size();i;i--) if (cmp(A[i-1].x,r)==0) wherer=i-1;
        U.clear(); D.clear(); int now=wherel;
        while (1){D.push_back(A[now]); if (now==wherer) break; now++; if (now>=A.size()) now=0;}
        now=wherel;
        while (1){U.push_back(A[now]); if (now==wherer) break; now--; if (now<0) now=A.size()-1;}
    }
    // 需要保证凸包点数大于等于 3,2 内部 ,1 边界 ,0 外部
    int containCoP(const vector<point>&U,const vector<point>&D,point k){
        db lx=U[0].x,rx=U[U.size()-1].x;
        if (k==U[0]||k==U[U.size()-1]) return 1;
        if (cmp(k.x,lx)==-1||cmp(k.x,rx)==1) return 0;
        int where1=lower_bound(U.begin(),U.end(),(point){k.x,-1e100})-U.begin();
        int where2=lower_bound(D.begin(),D.end(),(point){k.x,-1e100})-D.begin();
        int w1=clockwise(U[where1-1],U[where1],k),w2=clockwise(D[where2-1],D[where2],k);
        if (w1==1||w2==-1) return 0; else if (w1==0||w2==0) return 1; return 2;
    }
    // d 是方向 , 输出上方切点和下方切点
    pair<point,point> getTangentCow(const vector<point> &U,const vector<point> &D,point d){
        if (sign(d.x)<0||(sign(d.x)==0&&sign(d.y)<0)) d=d*(-1);
        point whereU,whereD;
        if (sign(d.x)==0) return mp(U[0],U[U.size()-1]);
        int l=0,r=U.size()-1,ans=0;
        while (l<r){int mid=l+r>>1; if (sign(cross(U[mid+1]-U[mid],d))<=0) l=mid+1,ans=mid+1; else r=mid;}
        whereU=U[ans]; l=0,r=D.size()-1,ans=0;
        while (l<r){int mid=l+r>>1; if (sign(cross(D[mid+1]-D[mid],d))>=0) l=mid+1,ans=mid+1; else r=mid;}
        whereD=D[ans]; return mp(whereU,whereD);
    }
    // 先检查 contain, 逆时针给出
    pair<point,point> getTangentCoP(const vector<point>&U,const vector<point>&D,point k){
        db lx=U[0].x,rx=U[U.size()-1].x;
        if (k.x<lx){
            int l=0,r=U.size()-1,ans=U.size()-1;
            while (l<r){int mid=l+r>>1; if (clockwise(k,U[mid],U[mid+1])==1) l=mid+1; else ans=mid,r=mid;}
            point w1=U[ans]; l=0,r=D.size()-1,ans=D.size()-1;
            while (l<r){int mid=l+r>>1; if (clockwise(k,D[mid],D[mid+1])==-1) l=mid+1; else ans=mid,r=mid;}
            point w2=D[ans]; return mp(w1,w2);
        } else if (k.x>rx){
            int l=1,r=U.size(),ans=0;
            while (l<r){int mid=l+r>>1; if (clockwise(k,U[mid],U[mid-1])==-1) r=mid; else ans=mid,l=mid+1;}
            point w1=U[ans]; l=1,r=D.size(),ans=0;
            while (l<r){int mid=l+r>>1; if (clockwise(k,D[mid],D[mid-1])==1) r=mid; else ans=mid,l=mid+1;}
            point w2=D[ans]; return mp(w2,w1);
        } else {
            int where1=lower_bound(U.begin(),U.end(),(point){k.x,-1e100})-U.begin();
            int where2=lower_bound(D.begin(),D.end(),(point){k.x,-1e100})-D.begin();
            if ((k.x==lx&&k.y>U[0].y)||(where1&&clockwise(U[where1-1],U[where1],k)==1)){
                int l=1,r=where1+1,ans=0;
                while (l<r){int mid=l+r>>1; if (clockwise(k,U[mid],U[mid-1])==1) ans=mid,l=mid+1; else r=mid;}
                point w1=U[ans]; l=where1,r=U.size()-1,ans=U.size()-1;
                while (l<r){int mid=l+r>>1; if (clockwise(k,U[mid],U[mid+1])==1) l=mid+1; else ans=mid,r=mid;}
                point w2=U[ans]; return mp(w2,w1);
            } else {
                int l=1,r=where2+1,ans=0;
                while (l<r){int mid=l+r>>1; if (clockwise(k,D[mid],D[mid-1])==-1) ans=mid,l=mid+1; else r=mid;}
                point w1=D[ans]; l=where2,r=D.size()-1,ans=D.size()-1;
                while (l<r){int mid=l+r>>1; if (clockwise(k,D[mid],D[mid+1])==-1) l=mid+1; else ans=mid,r=mid;}
                point w2=D[ans]; return mp(w1,w2);
            }
        }
    }
    struct P3{
        db x,y,z;
        P3 operator + (P3 k1){return (P3){x+k1.x,y+k1.y,z+k1.z};}
        P3 operator - (P3 k1){return (P3){x-k1.x,y-k1.y,z-k1.z};}
        P3 operator * (db k1){return (P3){x*k1,y*k1,z*k1};}
        P3 operator / (db k1){return (P3){x/k1,y/k1,z/k1};}
        db abs2(){return x*x+y*y+z*z;}
        db abs(){return sqrt(x*x+y*y+z*z);}
        P3 unit(){return (*this)/abs();}
        int operator < (const P3 k1) const{
            if (cmp(x,k1.x)!=0) return x<k1.x;
            if (cmp(y,k1.y)!=0) return y<k1.y;
            return cmp(z,k1.z)==-1;
        }
        int operator == (const P3 k1){
            return cmp(x,k1.x)==0&&cmp(y,k1.y)==0&&cmp(z,k1.z)==0;
        }
        void scan(){
            double k1,k2,k3; scanf("%lf%lf%lf",&k1,&k2,&k3);
            x=k1; y=k2; z=k3;
        }
    };
    P3 cross(P3 k1,P3 k2){return (P3){k1.y*k2.z-k1.z*k2.y,k1.z*k2.x-k1.x*k2.z,k1.x*k2.y-k1.y*k2.x};}
    db dot(P3 k1,P3 k2){return k1.x*k2.x+k1.y*k2.y+k1.z*k2.z;}
    //p=(3,4,5),l=(13,19,21),theta=85 ans=(2.83,4.62,1.77)
    P3 turn3D(db k1,P3 l,P3 p){
        l=l.unit(); P3 ans; db c=cos(k1),s=sin(k1);
        ans.x=p.x*(l.x*l.x*(1-c)+c)+p.y*(l.x*l.y*(1-c)-l.z*s)+p.z*(l.x*l.z*(1-c)+l.y*s);
        ans.y=p.x*(l.x*l.y*(1-c)+l.z*s)+p.y*(l.y*l.y*(1-c)+c)+p.z*(l.y*l.z*(1-c)-l.x*s);
        ans.z=p.x*(l.x*l.z*(1-c)-l.y*s)+p.y*(l.y*l.z*(1-c)+l.x*s)+p.z*(l.x*l.x*(1-c)+c);
        return ans;
    }
    typedef vector<P3> VP;
    typedef vector<VP> VVP;
    db Acos(db x){return acos(max(-(db)1,min(x,(db)1)));}
    // 球面距离 , 圆心原点 , 半径 1
    db Odist(P3 a,P3 b){db r=Acos(dot(a,b)); return r;}
    db r; P3 rnd;
    vector<db> solve(db a,db b,db c){
        db r=sqrt(a*a+b*b),th=atan2(b,a);
        if (cmp(c,-r)==-1) return {0};
        else if (cmp(r,c)<=0) return {1};
        else {
            db tr=pi-Acos(c/r); return {th+pi-tr,th+pi+tr};
        }
    }
    vector<db> jiao(P3 a,P3 b){
        // dot(rd+x*cos(t)+y*sin(t),b) >= cos(r)
        if (cmp(Odist(a,b),2*r)>0) return {0};
        P3 rd=a*cos(r),z=a.unit(),y=cross(z,rnd).unit(),x=cross(y,z).unit();
        vector<db> ret = solve(-(dot(x,b)*sin(r)),-(dot(y,b)*sin(r)),-(cos(r)-dot(rd,b))); 
        return ret;
    }
    db norm(db x,db l=0,db r=2*pi){ // change x into [l,r)
        while (cmp(x,l)==-1) x+=(r-l); while (cmp(x,r)>=0) x-=(r-l);
        return x;
    }
    db disLP(P3 k1,P3 k2,P3 q){
        return (cross(k2-k1,q-k1)).abs()/(k2-k1).abs();
    }
    db disLL(P3 k1,P3 k2,P3 k3,P3 k4){
        P3 dir=cross(k2-k1,k4-k3); if (sign(dir.abs())==0) return disLP(k1,k2,k3);
        return fabs(dot(dir.unit(),k1-k2));
    }
    VP getFL(P3 p,P3 dir,P3 k1,P3 k2){
        db a=dot(k2-p,dir),b=dot(k1-p,dir),d=a-b;
        if (sign(fabs(d))==0) return {};
        return {(k1*a-k2*b)/d};
    }
    VP getFF(P3 p1,P3 dir1,P3 p2,P3 dir2){// 返回一条线
        P3 e=cross(dir1,dir2),v=cross(dir1,e);
        db d=dot(dir2,v); if (sign(abs(d))==0) return {};
        P3 q=p1+v*dot(dir2,p2-p1)/d; return {q,q+e};
    }
    // 3D Covex Hull Template
    db getV(P3 k1,P3 k2,P3 k3,P3 k4){ // get the Volume
        return dot(cross(k2-k1,k3-k1),k4-k1);
    }
    db rand_db(){return 1.0*rand()/RAND_MAX;}
    VP convexHull2D(VP A,P3 dir){
        P3 x={(db)rand(),(db)rand(),(db)rand()}; x=x.unit();
        x=cross(x,dir).unit(); P3 y=cross(x,dir).unit();
        P3 vec=dir.unit()*dot(A[0],dir);
        vector<point>B;
        for (int i=0;i<A.size();i++) B.push_back((point){dot(A[i],x),dot(A[i],y)});
        B=ConvexHull(B); A.clear();
        for (int i=0;i<B.size();i++) A.push_back(x*B[i].x+y*B[i].y+vec);
        return A;
    }
    namespace CH3{
        VVP ret; set<pair<int,int> >e;
        int n; VP p,q;
        void wrap(int a,int b){
            if (e.find({a,b})==e.end()){
                int c=-1;
                for (int i=0;i<n;i++) if (i!=a&&i!=b){
                    if (c==-1||sign(getV(q[c],q[a],q[b],q[i]))>0) c=i;
                }
                if (c!=-1){
                    ret.push_back({p[a],p[b],p[c]});
                    e.insert({a,b}); e.insert({b,c}); e.insert({c,a});
                    wrap(c,b); wrap(a,c);
                }
            }
        }
        VVP ConvexHull3D(VP _p){
            p=q=_p; n=p.size();
            ret.clear(); e.clear();
            for (auto &i:q) i=i+(P3){rand_db()*1e-4,rand_db()*1e-4,rand_db()*1e-4};
            for (int i=1;i<n;i++) if (q[i].x<q[0].x) swap(p[0],p[i]),swap(q[0],q[i]);
            for (int i=2;i<n;i++) if ((q[i].x-q[0].x)*(q[1].y-q[0].y)>(q[i].y-q[0].y)*(q[1].x-q[0].x)) swap(q[1],q[i]),swap(p[1],p[i]);
            wrap(0,1);
            return ret;
        }
    }
    VVP reduceCH(VVP A){
        VVP ret; map<P3,VP> M;
        for (VP nowF:A){
            P3 dir=cross(nowF[1]-nowF[0],nowF[2]-nowF[0]).unit();
            for (P3 k1:nowF) M[dir].pb(k1);
        }
        for (pair<P3,VP> nowF:M) ret.pb(convexHull2D(nowF.se,nowF.fi));
        return ret;
    }
    //  把一个面变成 ( 点 , 法向量 ) 的形式
    pair<P3,P3> getF(VP F){
        return mp(F[0],cross(F[1]-F[0],F[2]-F[0]).unit());
    }
    // 3D Cut 保留 dot(dir,x-p)>=0 的部分
    VVP ConvexCut3D(VVP A,P3 p,P3 dir){
        VVP ret; VP sec;
        for (VP nowF: A){
            int n=nowF.size(); VP ans; int dif=0;
            for (int i=0;i<n;i++){
                int d1=sign(dot(dir,nowF[i]-p));
                int d2=sign(dot(dir,nowF[(i+1)%n]-p));
                if (d1>=0) ans.pb(nowF[i]);
                if (d1*d2<0){
                    P3 q=getFL(p,dir,nowF[i],nowF[(i+1)%n])[0];
                    ans.push_back(q); sec.push_back(q);
                }
                if (d1==0) sec.push_back(nowF[i]); else dif=1;
                dif|=(sign(dot(dir,cross(nowF[(i+1)%n]-nowF[i],nowF[(i+1)%n]-nowF[i])))==-1);
            }
            if (ans.size()>0&&dif) ret.push_back(ans);
        }
        if (sec.size()>0) ret.push_back(convexHull2D(sec,dir));
        return ret;
    }
    db vol(VVP A){
        if (A.size()==0) return 0; P3 p=A[0][0]; db ans=0;
        for (VP nowF:A)
            for (int i=2;i<nowF.size();i++)
                ans+=abs(getV(p,nowF[0],nowF[i-1],nowF[i]));
        return ans/6;
    }
    VVP init(db INF) {
        VVP pss(6,VP(4));
        pss[0][0] = pss[1][0] = pss[2][0] = {-INF, -INF, -INF};
        pss[0][3] = pss[1][1] = pss[5][2] = {-INF, -INF, INF};
        pss[0][1] = pss[2][3] = pss[4][2] = {-INF, INF, -INF};
        pss[0][2] = pss[5][3] = pss[4][1] = {-INF, INF, INF};
        pss[1][3] = pss[2][1] = pss[3][2] = {INF, -INF, -INF};
        pss[1][2] = pss[5][1] = pss[3][3] = {INF, -INF, INF};
        pss[2][2] = pss[4][3] = pss[3][1] = {INF, INF, -INF};
        pss[5][0] = pss[4][0] = pss[3][0] = {INF, INF, INF};
        return pss;
    }
    
    东北日出西边雨 道是无情却有情
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  • 原文地址:https://www.cnblogs.com/ccut-ry/p/8981922.html
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