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  • 【Luogu】P3288方伯伯运椰子(消圈定理)

      题目链接

      分数规划题,详见luogu题解

    #include<cstdio>
    #include<cstring>
    #include<cctype>
    #include<algorithm>
    #include<cstdlib>
    #include<cmath>
    #define maxn 100010
    #define eps 1e-9
    using namespace std;
    inline long long read(){
        long long num=0,f=1;
        char ch=getchar();
        while(!isdigit(ch)){
            if(ch=='-')    f=-1;
            ch=getchar();
        }
        while(isdigit(ch)){
            num=num*10+ch-'0';
            ch=getchar();
        }
        return num*f;
    }
    
    struct Edge{
        int next,to;double val;
    }edge[maxn*2];
    int head[maxn],num;
    inline void add(int from,int to,double val){
        edge[++num]=(Edge){head[from],to,val};
        head[from]=num;
    }
    
    bool vis[maxn];
    double dis[maxn];
    
    bool spfa(int x,double mid){
        vis[x]=1;
        for(int i=head[x];i;i=edge[i].next){
            int to=edge[i].to;
            if(dis[to]<=dis[x]+edge[i].val+mid)    continue;
            dis[to]=dis[x]+edge[i].val+mid;
            if(vis[to])    return 1;
            if(spfa(to,mid))    return 1;
        }
        vis[x]=0;
        return 0;
    }
    int n,m;
    bool check(double mid){
        memset(dis,0,sizeof(dis));
        memset(vis,0,sizeof(vis));
        for(int i=1;i<=n;++i)
            if(spfa(i,mid))    return 1;
        return 0;
    }
    
    int main(){
        n=read()+2,m=read();
        for(int i=1;i<=m;++i){
            int from=read(),to=read(),a=read(),b=read(),c=read(),d=read();
            if(c!=0)    add(to,from,a-d);
            add(from,to,b+d);
        }
        double l=0,r=0x7fffffff,ans=0;
        while(fabs(r-l)>eps){
            double mid=(l+r)/2.0;
            if(check(mid)){
                ans=mid;
                l=mid;
            }
            else r=mid;
        }
        printf("%.2lf",ans);
        return 0;
    }
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  • 原文地址:https://www.cnblogs.com/cellular-automaton/p/8983634.html
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