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  • 获取两个日期之间的每一天

    我只把我现在用的方法列出来:

    1.建立一个辅助表,里面只有一列,内容为0-100W个数

    CREATE TABLE Nums(n INT NOT NULL PRIMARY KEY);
    insert into Nums values (0)
    DECLARE @max AS INT,@rc AS INT;
    SET @max = 1000000;
    SET @rc=1;
    INSERT INTO Nums VALUES (1);
    WHILE @rc * 2 <=@max
      BEGIN
          INSERT INTO Nums SELECT n+@rc FROM Nums;
          SET @rc=@rc * 2;
      END
      
    INSERT INTO Nums SELECT n +@rc FROM Nums WHERE n+@rc<=@max ;  

    二.开始计算两个日期之间的各个天数

    DECLARE @StartDate DATETIME,@EndDate DATETIME
    SET @StartDate='2008-02-21';
    SET @EndDate ='2013-05-12';
    
    --SELECT @StartDate + n FROM (SELECT DATEDIFF(DAY,@StartDate,@enddate) dday) num ,dbo.Nums_Assist WHERE 
    --num.dday>=dbo.Nums_Assist.n
    
    SELECT DATEADD(DAY,n,@startdate)  FROM (SELECT DATEDIFF(DAY,@StartDate,@enddate) dday) num ,dbo.Nums WHERE 
    num.dday>=dbo.Nums.n

    两种方式都可以使用

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  • 原文地址:https://www.cnblogs.com/cgdou/p/2857314.html
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