Given a binary tree, determine if it is a valid binary search tree (BST).
Assume a BST is defined as follows:
- The left subtree of a node contains only nodes with keys less than the node's key.
- The right subtree of a node contains only nodes with keys greater than the node's key.
- Both the left and right subtrees must also be binary search trees.
/**
* Definition for a binary tree node.
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode() : val(0), left(nullptr), right(nullptr) {}
* TreeNode(int x) : val(x), left(nullptr), right(nullptr) {}
* TreeNode(int x, TreeNode *left, TreeNode *right) : val(x), left(left), right(right) {}
* };
*/
time O(n) space O(1)
class Solution {
public:
int* last = NULL;
bool isValidBST(TreeNode* root) {
if (root){
if(!isValidBST(root->left)) return false;
if (last && *last>=root->val) return false;
last = &root->val;
if(!isValidBST(root->right)) return false;
return true;
}else return true;
};
};