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  • c语言---枚举

    当一个变量只有几种可能的取值时,则可以定义为枚举类型的变量。

    一:枚举类型的输出

    #include<stdio.h>
    
    enum month {ill,Jan,Feb,Mar,Apr,May,Jun
    };
    int main(){
        int i;
        enum month m;
        for(i=0;i<6;i++){
        printf("
    please input month name:");
        scanf("%d",&m);
        switch(m){
            case ill:
                printf("illegal month
    ");
                break;
            case Jan:
                printf("January
    ");
                break;
            case Feb:
                printf("February
    ");
                break;
            case Mar:
                printf("March
    ");
                break;
            case Apr:
                printf("April
    ");
                break;
            case May:
                printf("May");
                break;
            case Jun:
                printf("June
    ");
                break;
        }    
    }
        
        return 0;
    }

    二:枚举元素的输出

    #include<stdio.h>
    int main(){
        enum language{Basic,Fortran,C
        };
        enum language used;
        used=Fortran;
        if(used==Basic){
            printf("It is Basic
    ");
        }
        else if(used==Fortran){
            printf("It is Fortran
    ");
        }
        else{
            printf("It is C
    ");
        }
        printf("used=%d
    ",used);
        printf("Basic=%d
    Fortran=%d
    C=%d",Basic,Fortran,C);
        return 0;
    }

    实例:假定周一至周五每小时工资3元,每周六工资每小时4元,每周日工资每小时5元,输入一周每天的工作时数,计算周工资数。

    #include<stdio.h>
    
    int main(){
        enum weekday{sun,mon,tue,wed,thu,fri,sat
    };
        enum weekday workday;
        int pay,hour,total;
        total=0;
        printf("请输入周日到周六的工作时间:
    ");
    //进行强制转换 (weekday)(workday+1)
        for(workday=sun;workday<=sat;workday=(weekday)(workday+1)){
            scanf("%d",&hour);
            switch(workday){
                case sun:
                    pay = hour*5;break;
                case sat:
                    pay = hour*4;break;
                default:
                    pay = hour*3;break;    
            }
            total+=pay;
        }
        
        
        printf("total pay is %d",total);
        return 0;
    }
    非学无以广才,非志无以成学。 正是因为今天的不完美,才对未来充满希望。 ----长帆
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  • 原文地址:https://www.cnblogs.com/changfan/p/11666859.html
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