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  • find-all-anagrams-in-a-string

    https://leetcode.com/problems/find-all-anagrams-in-a-string/

    package com.company;
    
    
    import java.util.ArrayList;
    import java.util.Iterator;
    import java.util.List;
    
    class Solution {
        public List<Integer> findAnagrams(String s, String p) {
            int[] smap = new int[26];
            int[] pmap = new int[26];
            int plen = p.length();
            int slen = s.length();
    
            for (int i=0; i<plen; i++) {
                pmap[p.charAt(i)-'a']++;
            }
    
            List<Integer> lst = new ArrayList<>();
            int count = 0;
            for (int i=0; i<plen&&i<slen; i++) {
                int xx = s.charAt(i) - 'a';
                if (pmap[xx] > 0) {
                    smap[xx]++;
                    if (smap[xx] <= pmap[xx]) {
                        count++;
                    }
                }
            }
            if (count == plen) {
                lst.add(0);
            }
            for (int i=plen; i<slen; i++) {
                int yy = s.charAt(i-plen) - 'a';
                if (smap[yy] > 0) {
                    smap[yy]--;
                    if (smap[yy] < pmap[yy]) {
                        count--;
                    }
                }
                int xx = s.charAt(i) - 'a';
                if (pmap[xx] > 0) {
                    smap[xx]++;
                    if (smap[xx] <= pmap[xx]) {
                        count++;
                    }
                }
                if (count == plen) {
                    lst.add(i-plen+1);
                }
            }
            return lst;
        }
    }
    
    public class Main {
    
        public static void main(String[] args) {
            // write your code here
            System.out.println("Hello");
            Solution solution = new Solution();
    
    
            List<Integer> ret = solution.findAnagrams("abab", "ab");
            System.out.printf("Result is len %d
    ", ret.size());
            Iterator<Integer> iter = ret.iterator();
            while (iter.hasNext()) {
                System.out.printf("%d;", iter.next());
            }
            System.out.println();
    
        }
    }
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  • 原文地址:https://www.cnblogs.com/charlesblc/p/5993111.html
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