zoukankan      html  css  js  c++  java
  • 数据库之十四:习题练习

    是网上早的题目,答案大部分是我自己写的,部分是别人的答案

    insert into Student values('01' , '赵雷' , '1990-01-01' , '');
    insert into Student values('02' , '钱电' , '1990-12-21' , '');
    insert into Student values('03' , '孙风' , '1990-05-20' , '');
    insert into Student values('04' , '李云' , '1990-08-06' , '');
    insert into Student values('05' , '周梅' , '1991-12-01' , '');
    insert into Student values('06' , '吴兰' , '1992-03-01' , '');
    insert into Student values('07' , '郑竹' , '1989-07-01' , '');
    insert into Student values('08' , '王菊' , '1990-01-20' , '');
    insert into Course values('01' , '语文' , '02');
    insert into Course values('02' , '数学' , '01');
    insert into Course values('03' , '英语' , '03');
    insert into Teacher values('01' , '张三');
    insert into Teacher values('02' , '李四');
    insert into Teacher values('03' , '王五');
    insert into SC values('01' , '01' , 80);
    insert into SC values('01' , '02' , 90);
    insert into SC values('01' , '03' , 99);
    insert into SC values('02' , '01' , 70);
    insert into SC values('02' , '02' , 60);
    insert into SC values('02' , '03' , 80);
    insert into SC values('03' , '01' , 80);
    insert into SC values('03' , '02' , 80);
    insert into SC values('03' , '03' , 80);
    insert into SC values('04' , '01' , 50);
    insert into SC values('04' , '02' , 30);
    insert into SC values('04' , '03' , 20);
    insert into SC values('05' , '01' , 76);
    insert into SC values('05' , '02' , 87);
    insert into SC values('06' , '01' , 31);
    insert into SC values('06' , '03' , 34);
    insert into SC values('07' , '02' , 89);
    insert into SC values('07' , '03' , 98);
    1.学生表
    Student(SID,Sname,Sage,Ssex) --SID 学生编号,Sname 学生姓名,Sage 出生年月,Ssex 学生性别
    2.课程表
    Course(CID,Cname,TID) --CID --课程编号,Cname 课程名称,TID 教师编号
    3.教师表
    Teacher(TID,Tname) --TID 教师编号,Tname 教师姓名
    4.成绩表
    SC(SID,CID,score) --SID 学生编号,CID 课程编号,score 分数

    查询选修了全部课程的学生信息
    (某学生不存在一门课没有选修)

    select a.* 
    from student a,sc b where a.sid=b.sid group by a.sid,a.sname,a.sage,a.ssex having count(*)=(select count(*) from course)

    检索至少选修两门课程的学生学号

    select sid from sc 
    group by sid
    having count(*)>=2

    统计每门课程的学生选修人数(超过5人的课程才统计)。
    要求输出课程号和选修人数,查询结果按人数降序排列,若人数相同,按课程号升序排列 

    select cid,count(*)
    from sc 
    group by cid
    having count(*)>5
    order by count(*) desc,cid asc

    查询每门功成绩最好的前两名

    select * from (select sid,cid,rank() over(partition by cid order by score desc) r from sc 
    )where r<3

    查询不同课程成绩相同的学生的学生编号、课程编号、学生成绩

    select distinct a.* from sc a, sc b
    where a.sid=b.sid
    and a.cid<>b.cid
    and a.score=b.score

    查询选修"张三"老师所授课程的学生中,成绩最高的学生信息及其成绩

    select a.*,b.score from student a,sc b,course c,teacher d
    where a.sid=b.sid
    and b.cid=c.cid
    and c.tid=d.tid
    and d.tname='张三'
    and score=(select max(e.score) from sc e where e.cid=b.cid)


    求每门课程的学生人数

    select b.cname,count(*) from sc a,course b
    where a.cid=b.cid
    group by b.cname


    查询课程编号为01且课程成绩在80分以上的学生的学号和姓名

    select *
    --a.sid,a.sname
    from student a,sc b
    where a.sid=b.sid 
    and b.cid='01' 
    and b.score>80

    查询不及格的课程

    select a.sname,c.cname,b.score from student a,sc b,course c
    where a.sid=b.sid 
    and b.cid = c.cid
    and b.score<60

    查询任何一门课程成绩在70分以上的姓名、课程名称和分数

    select a.sname,c.cname,b.score from student a,sc b,course c
    where a.sid=b.sid 
    and b.cid = c.cid
    and b.score>70

    查询所有学生的课程及分数情况

    select a.sname,c.cname,b.score from student a,sc b,course c
    where a.sid=b.sid
    and b.cid=c.cid

    查询课程名称为"数学",且分数低于60的学生姓名和分数

    select a.sname,b.score from student a,sc b,course c
    where a.sid=b.sid
    and b.cid=c.cid
    and c.cname='数学'
    and b.score<60

    查询平均成绩大于等于85的所有学生的学号、姓名和平均成绩

    SELECT A.SID,A.SNAME,ROUND(AVG(SCORE),2) R FROM STUDENT A,SC B
    WHERE A.SID=B.SID
    GROUP BY A.SID,A.SNAME
    HAVING AVG(SCORE)>=85
    ORDER BY R DESC

    查询每门课程的平均成绩,结果按平均成绩降序排列,平均成绩相同时,按课程编号升序排列

    select cid,round(avg(score),2) R from sc
    group by cid
    ORDER BY R DESC,CID ASC


    查询1990年出生的学生名单(注:Student表中Sage列的类型是datetime)

    select * from student 
    where substr(sage,1,4)='1990'

    查询同名同性学生名单,并统计同名人数

    select sname,ssex,count(*) from Student
    group by sname,ssex
    having count(*)>1

    查询名字中含有"风"字的学生信息

    select * from student 
    where sname like '%风%'

    查询男生、女生人数

    select sum(case when ssex='' then 1 else 0 end),sum(case when ssex='' then 1 else 0 end)
    from Student

    查询出只有两门课程的全部学生的学号和姓名

    select a.sid,a.sname from student a,sc b
    where a.sid=b.sid
    group by a.sid,a.sname
    having count(*)=2

    查询每门课程被选修的学生数

    select cid,count(*) from sc 
    group by cid

    查询各科成绩前三名的记录

    select * from (
    select cid,score,
    rank() 
    over(partition by cid order by score desc) r 
    from sc)
    where r<4

    查询学生平均成绩及其名次

    select sid,round(avg(score),2),dense_rank() over( order by round(avg(score),2) desc)from SC
    group by sid


    统计各科成绩各分数段人数:课程编号,课程名称, 100-85 , 85-70 , 70-60 , 0-60 及所占百分比 to_char(,'FM9999999999999999.00') as amount

    SELECT a.cid,b.cname,
    sum(case when a.score>=85 and a.score<100 then 1 else 0 end ) as "100-85",to_char(sum(case when a.score>=85 and a.score<100 then 1 else 0 end )/count(*),'FM9999999999999999.00'),
    sum(case when a.score>=70 and a.score<85 then 1 else 0 end ) as "85-70",to_char(sum(case when a.score>=70 and a.score<85 then 1 else 0 end )/count(*),'FM9999999999999999.00'),
    sum(case when a.score>=60 and a.score<70 then 1 else 0 end ) as "70-60",to_char(sum(case when a.score>=60 and a.score<70 then 1 else 0 end )/count(*),'FM9999999999999999.00'),
    sum(case when a.score>=0 and a.score<60 then 1 else 0 end ) as "0-60",to_char(sum(case when a.score>=0 and a.score<60 then 1 else 0 end )/count(*),'FM9999999999999999.00') from sc a,course b
    where a.cid=b.cid
    group by a.cid,b.cname


    查询所有课程的成绩第2名到第3名的学生信息及该课程成绩

    select a.*,b.cid,b.score 
    from student a,(select cid,sid,score,dense_rank() over(partition by cid order by score DESC) R
    from SC) b
    where a.sid=b.sid
    and R>=2 
    AND R<=3

    查询不同老师所教不同课程平均分从高到低显示

    select tname,a.cid,avg(score) avge
    from teacher c,course a,sc b
    where a.cid=b.cid
    and c.tid=a.tid
    group by tname,a.cid
    order by avge desc

    查询学生的总成绩并进行排名

    select sid,sum(score) as r from sc 
    group by sid 
    order by r desc

    按各科成绩进行排序,并显示排名

    select cid,sid,score,
    dense_rank() over(partition by cid order by score) 
    from sc
    order by cid,score


    查询各科成绩最高分、最低分和平均分:以如下形式显示:课程ID,课程name,
    最高分,最低分,平均分,及格率,中等率,优良率,优秀率
    --及格为>=60,中等为:70-80,优良为:80-90,优秀为:>=90

    select A.cid,A.cname,max(b.score),min(b.score),avg(b.score),
    sum(case when b.score>=60 then 1 else 0 end )/count(*) ,
    sum(case when b.score>=70 and b.score<80 then 1 else 0 end)/count(*),
    sum(case when b.score>=80 and b.score<90 then 1 else 0 end)/count(*),
    sum(case when b.score>=90 then 1 else 0 end)/count(*)
    from course a,sc b 
    where a.cid=b.cid
    GROUP BY a.cid,a.cname;

    按平均成绩从高到低显示所有学生的所有课程的成绩以及平均成绩

    select a.SID  学生编号,a.Sname 学生姓名,
    max(case c.Cname when '语文' then b.score else null end) 语文,
    max(case c.Cname when '数学' then b.score else null end) 数学,
    max(case c.Cname when '英语' then b.score else null end) 英语,
    cast(avg(b.score) as decimal(18,2)) 平均分
    from Student a
    left join SC b on a.SID = b.SID
    left join Course c on b.CID = c.CID
    group by a.SID , a.Sname
    order by 平均分

    检索"01"课程分数小于60,按分数降序排列的学生信息

    select a.*,b.score from student a,sc b
    where b.cid='01'
    and score<60
    order by score desc

    查询两门及其以上不及格课程的同学的学号,姓名及其平均成绩

    select a.sid,a.sname,avg(b.score) from student a,sc b
    where exists 
    (select c.sid,count(*) from sc c where a.sid=c.sid
    group by c.sid) 
    group by a.sid,a.sname


    查询至少有一门课与学号为"01"的同学所学相同的同学的信息
    (没有一门课与学号01同学所学相同的同学信息)

    select distinct a.* from student a,sc b 
    where a.sid=b.sid
    and a.sid<>'01' 
    and exists (
    select * from SC c 
    where c.sid='01' 
    and b.cid=c.cid )

    查询没有学全所有课程的同学的信息

    select sid,count(cid) from sc
    group by sid
    having count(cid)<(select count(cid) from course)

    查询学过编号为"01"但是没有学过编号为"02"的课程的同学的信息

    select distinct a.* from student a,sc b,sc c
    where a.sid=b.sid
    and b.cid='01'
    and not exists (select * from sc c where a.sid=c.sid and c.cid='02')


    查询学过编号为"01"并且也学过编号为"02"的课程的同学的信息

    select distinct a.* from student a,sc b,sc c
    where a.sid=b.sid
    and a.sid=c.sid
    and b.cid='01'
    and c.cid='02'


    ***查询没学过"张三"老师授课的同学的信息***可以尝试使用exist去写

    select e.*
    from student e
    where e.sid not in (select distinct a.sid
    from student a,sc b,course c,teacher d
    where a.sid=b.sid
    and b.cid=c.cid
    and c.tid=d.tid
    and tname='张三' )


    查询学过"张三"老师授课的同学的信息

    select distinct a.sid,a.sname,a.sage,a.ssex
    from student a,sc b,course c,teacher d
    where a.sid=b.sid
    and b.cid=c.cid
    and c.tid=d.tid
    and tname='张三'

    查询"01"课程比"02"课程成绩高的学生的信息及课程分数

    select a.sid,a.sname,a.sage,a.ssex,b.score "01分数",c.score "02分数"
    from student a,sc b,sc c
    where b.cid='01'
    and c.cid='02'
    and a.sid=b.sid
    and a.sid=c.sid
    and b.score>c.score

    查询平均成绩大于等于60分的同学的学生编号和学生姓名和平均成绩

    select a.sid,a.sname,avg(b.score) "平均成绩"
    from student a,sc b
    where a.sid=b.sid
    group by a.sid,a.sname
    having avg(b.score)>=60


    查询所有同学的学生编号、学生姓名、选课总数、所有课程的总成绩

    select a.sid,a.sname,count(a.sid),sum(b.score)
    from student a,sc b
    where a.sid=b.sid
    group by a.sid,a.sname

    查询"李"姓老师的数量

    select count(*) from Teacher
    where Tname like '李%'
    尽管很渺小,但终究会变得伟大
  • 相关阅读:
    sql server日志已满报错
    图片基础信息
    android小细节
    内存泄露分析
    一个非常快的android模拟器
    activity退出
    ListView中内容的动画效果
    视频相关android软件
    Android Screen Monitor抓取真机屏幕
    ListView中使用type需要注意的东西
  • 原文地址:https://www.cnblogs.com/chenbao1012/p/11846680.html
Copyright © 2011-2022 走看看