python-requests正则

以抓取豆瓣分页为例
from re import S

import requests
from setuptools import findall  # S多行匹配 M单行匹配
from urllib3 import response


def get_all_movies():
    page = 10
    # 请求头
    header = {
        'user-agent': 'Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/85.0.4183.121 Safari/537.36'
    }
    for n in range(page):
        url = f'https://movie.douban.com/top250?start={n * 25}&filter='
        response = requests.get(url, headers=header)
        print(response.text)
        print(f'==============第{n + 1}页=============')
        if response.status_code == 200:
            analysis_data(response.text)
        else:
            print(f'爬取失败')