leetcode 7.反转整数

给定一个 32 位有符号整数，将整数中的数字进行反转。

class Solution:
    def reverse(self, x):
        """
        :type x: int
        :rtype: int
        """
        bool = False
        if x < 0:
            bool = True
        if bool:
            num = int("-"+str(x)[1:][::-1])
        else:
            num = int(str(x)[::-1])
        
        if -2 ** 31 <= num <= 2 ** 31 - 1:
            return num
        else:
            return 0