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  • django 后端JsonResponse返回json数据给前端完美接收并将数据写入前端页面做展示

    1.后端代码编写

    from django.http import JsonResponse
    
    res = {"code": 0, "message": result_list}
    return JsonResponse(res)

    2.前端代码编写

    <h4 style="margin: 10px;color: blue;font-weight: bold">命令执行结果:</h4>
    <ul id="list">
    </ul>

    3.ajax代码编写

    $.ajax({
        url: url,
        type: "POST",
        traditional:true,  //加上此项可以传数组
        data: {
            "cmd": cmd,
            "host_ip_list": host_ip_list,
            "host_port": host_port,
            "auth_type": auth_type,
            "login_user": login_user,
            "password": password,
        },
        success: function (data) {
            $("#list").html('');
            console.log(data.message);
            var message_list = data.message;
            for (let i = 0; i < message_list.length; i++) {
                console.log(message_list[i]);
                var server_ip = message_list[i].server_ip;
                var status = message_list[i].status;
                var result = message_list[i].result;
                $("#list").html($("#list").html() + "<br>" + " server_ip: " + server_ip + "<br/>");
                $("#list").html($("#list").html() + "<br>" + " status: " + status + "<br/>");
                $("#list").html($("#list").html() + "<br>" + " result: " + result + "<br/>");
                $("#list").html($("#list").html() + "<HR>" + "<br/>");
            };
        }
    });

    4.页面显示

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  • 原文地址:https://www.cnblogs.com/chenjw-note/p/12849777.html
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