codeforces 368B

B. Sereja and Suffixes

time limit per test

1 second

memory limit per test

256 megabytes

input

standard input

output

standard output

Sereja has an array a, consisting of n integers a1, a2, ..., an. The boy cannot sit and do nothing, he decided to study an array. Sereja took a piece of paper and wrote out m integers l1, l2, ..., lm (1 ≤ li ≤ n). For each number li he wants to know how many distinct numbers are staying on the positions li, li + 1, ..., n. Formally, he want to find the number of distinct numbers among ali, ali + 1, ..., an.?

Sereja wrote out the necessary array elements but the array was so large and the boy was so pressed for time. Help him, find the answer for the described question for each li.

Input

The first line contains two integers n and m (1 ≤ n, m ≤ 105). The second line contains n integers a1, a2, ..., an (1 ≤ ai ≤ 105) — the array elements.

Next m lines contain integers l1, l2, ..., lm. The i-th line contains integer li (1 ≤ li ≤ n).

Output

Print m lines — on the i-th line print the answer to the number li.

Examples

input

10 10
1 2 3 4 1 2 3 4 100000 99999
1
2
3
4
5
6
7
8
9
10

output

6
6
6
6
6
5
4
3
2
1

 题目的意思为第一行输入n和m，第二行输入n个数，然后输入m行数字，依次输出每个数字对应的n个数中不重复的数字的个数。

#include<iostream>
#include<map>
#define MAXN 100005
using namespace std;
map<int, int> mp;
int main()
{
    int n, m, num;
    cin >> n >> m;
    int number[MAXN],l[MAXN];
    memset(l, 0, sizeof(l));
    for (int i = 0;i < n;i++)
        cin >> number[i];
    for (int i = n - 1;i >= 0;i--)
    {
        mp[number[i]]++;
        if (mp[number[i]] == 1)
            l[i] = l[i + 1] + 1;
        else
            l[i] = l[i + 1];
    }
    for (int i = 0;i < m;i++)
    {
        cin >> num;
        cout << l[num-1] << endl;
    }
    return 0;
}