20181019

# index = 0
# while index< len(s):
#     print(s[index])
#     index += 1
# for 循环 把一个"可迭代对象"中的每一个元素拿出来赋值给前面的"变量"
'''for 变量in 可迭代对象:
      循环体'''
# for c in s :
#     print(c)
# 作业明日默写内容
# s = "，今天周五了.深圳有什么爱玩的呢? 我爱学习,我爱工作,我爱代码 "
# for c in s:
#     if c == "爱":
#         break
#     print(c)
# else:
#     print("收尾")
# s = input("ABCDabcd深圳爱编程公司")
# index = 0
# while index< len(s):
#     print(s[index])
#     index += 1
# s ="迷途经累劫，悟则刹那间。"
# index = 0
# while index< len(s):
#     print(s[index])
#     index += 1
# s = "迷途经累劫，悟则刹那间"
# index = 0
# while index< len(s):
#     print(s[index])
#     index += 1
# 作业1)移除 name 变量对应的值两边的空格,并输出处理结果
# name = " aleX leNb "
# ret = name.strip( )
# print(ret)
# 2)移除name变量左边的"al"并输出处理结果
# name = "aleX leNb"
# print(name.strip("al"))
# 3)移除name变量右⾯的"Nb",并输出处理结果#
# name = "aleX leNb"
# print(name.strip("Nb"))
# 4)移除name变量开头的a"与最后的"b",并输出处理结果
# name = "aleX leNb"
# print(name.strip("ab"))
# 5)判断 name 变量是否以 "al" 开头,并输出结果
# name = "aleX leNb"
# ret1 = name.startswith("al")
# print(ret1)
# 6)判断name变量是否以"Nb"结尾,并输出结果
# name = "aleX leNb"
# ret2 = name.endswith("Nb")
# print(ret2)
# 7)将 name 变量对应的值中的 所有的"l" 替换为 "p",并输出结果
# name = "aleX leNb"
# ret = name.replace('l','p')
# print(ret)
# s8 = "sylar_alex_taibai_wusir_eggon"
# ret = s8.replace('alex','金角大王')
# print(ret)
# 8)将name变量对应的值中的第⼀个"l"替换成"p",并输出结果
# name = "aleX leNb"
# ret = name.replace('l','p',1)
# print(ret)
# 9)将 name 变量对应的值根据 所有的"l" 分割,并输出结果。
# name = "aleX leNb"
# lst = name.split("l")
# print(lst)
# 10)将name变量对应的值根据第⼀个"l"分割,并输出结果。
# name = "aleX leNb"
# lst = name.split("l",1)
# print(lst)
# 11)将 name 变量对应的值变⼤写,并输出结果
# name = "aleX leNb"
# ret = name.upper()
# print(ret)
# 12)将 name 变量对应的值变⼩写,并输出结果
# name = "aleX leNb"
# ret = name.lower()
# print(ret)
# 13)将name变量对应的值⾸字⺟"a"⼤写,并输出结果
# name = "aleX leNb"
# ret = name.capitalize()
# print(ret) N 变小写了？
# 14)判断name变量对应的值字⺟"l"出现⼏次，并输出结果
# name = "aleX leNb"
# ret = name.count("l")
# print(ret)
# 15)如果判断name变量对应的值前四位"l"出现⼏次,并输出结果
# name = "aleX leNb"
# ret = name[0:1].count("l")
# print(ret)
# 16)从name变量对应的值中找到"N"对应的索引(如果找不到则报错)，并输出结果
# name = "aleX leNb"
# ret = name.index("N")
# print(ret)
# 17)从name变量对应的值中找到"N"对应的索引(如果找不到则返回-1)输出结果
# name = "aleX leNb"
# ret = name.find("N")
# print(ret)
# 18)从name变量对应的值中找到"X le"对应的索引,并输出结果
# name = "aleX leNb"
# ret = name.find("X le")
# print(ret)
# 19)请输出 name 变量对应的值的第 2 个字符?
# name = "aleX leNb"
# print(name[2])
# 20)请输出 name 变量对应的值的前 3 个字符?
# name = "aleX leNb"
# print(name[:3])
# 21)请输出 name 变量对应的值的后 2 个字符?
# name = "aleX leNb"
# print(name[-2:])
# 22)请输出 name 变量对应的值中 "e" 所在索引位置?
# name = "aleX leNb"
# ret = name.find("e")
# print(ret)
# 2.有字符串s = "123a4b5c"
# 1)通过对s切⽚形成新的字符串s1,s1 = "123"
# s = "123a4b5c"
# print(s[:3])
# 2)通过对s切⽚形成新的字符串s2,s2 = "a4b"
# s = "123a4b5c"
# print(s[3:6])
# 3)通过对s切⽚形成新的字符串s3,s3 = "1345"
# s = "123a4b5c"
# print(s[::2])
# 4)通过对s切⽚形成字符串s4,s4 = "2ab"
# s = "123a4b5c"
# print(s[1:6:2])
# 5)通过对s切⽚形成字符串s5,s5 = "c"
# s = "123a4b5c"
# print(s[-1])
# 6)通过对s切⽚形成字符串s6,s6 = "ba2"
# s = "123a4b5c"
# print(s[-3:-8:-2])
# 3.使⽤while和for循环分别打印字符串s="asdfer"中每个元素。
# s="asdfer"
# index = 0
# while index< len(s):
#     print(s[index])
#     index += 1

# '''for 循环 把一个"可迭代对象"中的每一个元素拿出来赋值给前面的"变量"
# '''for 变量in 可迭代对象:
#       循环体'''
# for c in s :
#     print(c)
# s = "asdfer "
# for c in s:
#     print(c)
# 4.使⽤for循环对s="asdfer"进⾏循环，但是每次打印的内容都是"asdfer"。
# s = "asdfer "
# for i in s:
#     print(s)
# 5.使⽤for循环对s="abcdefg"进⾏循环，每次打印的内容是每个字符加上sb，例如：asb, bsb，csb,...gsb。
# s = "asdfer "
# for i in s:
#     i= i+"sb"
#     print(i)
# 6.使⽤for循环对s="321"进⾏循环，打印的内容依次是："倒计时3秒"，"倒计时2秒"，"倒计时1秒"，"出发！"。
# s = "321"
# for i in s:
#     i="倒计时{}秒".format(i)
#     print(i )
# print("出发")
'''7，实现⼀个整数加法计算器(两个数相加)：
如：content = input("请输⼊内容:") ⽤户输⼊：5+9或5+ 9或5 + 9，然后进
⾏分割再进⾏计算。'''
# content=input("请输入内容：")
# content = input("请输入数字").strip()
# s = content.split("+")
# print(int(s[0])+int(s[0]))