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  • poj 1094 Sorting It All Out

    Description

    An ascending sorted sequence of distinct values is one in which some form of a less-than operator is used to order the elements from smallest to largest. For example, the sorted sequence A, B, C, D implies that A < B, B < C and C < D. in this problem, we will give you a set of relations of the form A < B and ask you to determine whether a sorted order has been specified or not.

    Input

    Input consists of multiple problem instances. Each instance starts with a line containing two positive integers n and m. the first value indicated the number of objects to sort, where 2 <= n <= 26. The objects to be sorted will be the first n characters of the uppercase alphabet. The second value m indicates the number of relations of the form A < B which will be given in this problem instance. Next will be m lines, each containing one such relation consisting of three characters: an uppercase letter, the character "<" and a second uppercase letter. No letter will be outside the range of the first n letters of the alphabet. Values of n = m = 0 indicate end of input.

    Output

    For each problem instance, output consists of one line. This line should be one of the following three: 

    Sorted sequence determined after xxx relations: yyy...y. 
    Sorted sequence cannot be determined. 
    Inconsistency found after xxx relations. 

    where xxx is the number of relations processed at the time either a sorted sequence is determined or an inconsistency is found, whichever comes first, and yyy...y is the sorted, ascending sequence. 

    Sample Input

    4 6
    A<B
    A<C
    B<C
    C<D
    B<D
    A<B
    3 2
    A<B
    B<A
    26 1
    A<Z
    0 0
    

    Sample Output

    Sorted sequence determined after 4 relations: ABCD.
    Inconsistency found after 2 relations.
    Sorted sequence cannot be determined.

    这是一道有点复杂的拓扑排序的题目
    由于一开始只是考虑第一次有没有多个点入站,所以WA了几次,后来才知道是每次都应该考虑一下,于是才AC的
    #include<map>
    #include<set>
    #include<stack>
    #include<queue>
    #include<cmath>
    #include<vector>
    #include<cstdio>
    #include<string>
    #include<cstring>
    #include<cstdlib>
    #include<iostream>
    #include<algorithm>
    #define  inf 0x0f0f0f0f
    
    using namespace std;
    
    int group[27][27],indegree[27],in[27],list[27],n,m;
    vector<int>G[27];
    
    int top_sort()
    {
        int flag=0;
        for (int i=0;i<n;i++) in[i]=indegree[i];
        stack<int>S;
        for (int i=0;i<n;i++)
        {
            if (in[i]==0) S.push(i);
        }
        if (S.size()>1) flag=1;
        int cut=0;
        while(!S.empty())
        {
            if (S.size()>1) flag=1;
            int u=S.top();
            S.pop();
            list[cut++]=u;
            for (int i=0;i<G[u].size();i++)
            {
                int v=G[u][i];
                in[v]--;
                if (in[v]==0) S.push(v);
            }
        }
        if (cut<n) return 1;//maodun
        if (flag==1) return 2;//don't sure
        return 0;//ok
    }
    
    int main()
    {
        int error,ok,x,y;
        char str[5];
        while(scanf("%d%d",&n,&m)!=EOF && n && m)
        {
            memset(group,0,sizeof(group));
            memset(indegree,0,sizeof(indegree));
            for (int i=0;i<=n;i++) G[i].clear();
            error=0; ok=0;
            for (int i=1;i<=m;i++)
            {
                scanf("%s",str);
                x=str[0]-'A';
                y=str[2]-'A';
                if (error==0 && ok==0)
                {
                    if (group[y][x]==1)
                    {
                        error=1;
                        printf("Inconsistency found after %d relations.
    ",i);
                        continue;
                    }
                    if (group[y][x]==0)
                    {
                        if (group[x][y]==0){
                            group[x][y]=1;
                            G[x].push_back(y);
                            indegree[y]++;
                        }
                        int temp=top_sort();
                        if (temp==1)
                        {
                            error=1;
                            printf("Inconsistency found after %d relations.
    ",i);
                        }
                        if (temp==0)
                        {
                            ok=1;
                            printf("Sorted sequence determined after %d relations: ",i);
                            for (int j=0;j<n;j++) printf("%c",list[j]+'A');
                            printf(".
    ");
                        }
                        if (temp==2) continue;
                    }
                }
            }
            if (error==0 && ok==0)
            printf("Sorted sequence cannot be determined.
    ");
        }
        return 0;
    }

    作者 chensunrise

    至少做到我努力了
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  • 原文地址:https://www.cnblogs.com/chensunrise/p/3760431.html
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