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  • 外键的变种,数据的增删改和单表查询

    1.如何找出两张表之间的关系

      先站在左表的角度去找 , 是否左表的多条记录可以对应右表的一条记录,如果是,则证明左表的一个字段foreign key 右表一个字段(通常是id)

      再站在右表的角度去找 , 是否右表的多条记录可以对应左表的一条记录,如果是,则证明右表的一个字段foreign key 左表一个字段(通常是id)

      总结:

        多对一:

        如果只有步骤1成立,则是左表多对一右表 , 如果只有步骤2成立,则是右表多对一左表

        多对多:

        如果步骤1和2同时成立,则证明这两张表时一个双向的多对一,即多对多,需要定义一个这两张表的关系表来专门存放二者的关系

        一对一:

        如果1和2都不成立,而是左表的一条记录唯一对应右表的一条记录,反之亦然。这种情况很简单,就是在左表foreign key右表的基础上,将左表的外键字段设置成unique即可

    2.表的三种关系

      一对多(或者多对一):

      关联方式: foreign key

    create table press(
        id int primary key auto_increment,
        name varchar(20)
    );
    create table book(
        id int primary key auto_increment,
        name varchar(20),
        press_id int not null,
            constraint fk_book_press foreign key(press_id) references  press(id)
          on delete cascade
        on update cascade
    );
    # 先往被关联表中插入记录
    insert into press(name) values
    ('北京工业地雷出版社'),
    ('人民音乐不好听出版社'),
    ('知识产权没有用出版社')
    ;
    # 再往关联表中插入记录
    insert into book (name,press_id) alues
    ('九阳神功',1),
    ('九阴真经',2),
    ('九阴白骨爪',2),
    ('独孤九剑',3),
    ('降龙十巴掌',2),
    ('葵花宝典',3)
    ;
    查询结果:
        select * from book;
        select * from press;

      多对多:

      关联方式: foreign key +一张新的表

    
    
    create table book(
                     id int primary key auto_increment,
                     name varchar(20)
                    
                    );
                    create table author(
                        id int primary key auto_increment,
                        name varchar(20)
                    );
                    
                    create table autho_book(
                        id int primary key auto_increment,
                        book_id int not null,
                        author_id int not null,
                        constraint fk_book foreign key(book_id) references book(id)
                        on delete cascade
                        on update cascade,
                        constraint fk_author foreign key(author_id) references author(id)
                        on delete cascade
                        on update cascade                
                    );
    insert into author(name) values('egon'),('alex'),('wusir'),('yuanhao');
    insert into book(name) values
                    ('九阳神功'),
                    ('九阴真经'),
                    ('九阴白骨爪'),
                    ('独孤九剑'),
                    ('降龙十巴掌'),
                    ('葵花宝典');
    insert into autho_book(author_id,book_id) values
                    (1,1),
                    (1,2),
                    (1,3),
                    (1,4),
                    (1,5),
                    (1,6),
                    (2,1),
                    (2,6),
                    (3,4),
                    (3,5),
                    (3,6),
                    (4,1)
                    ;
    
    

      一对一;

      关联方式: foreign key +unique

    
    
    #例如: 一个用户只能注册一个博客
    
    #两张表: 用户表 (user)和 博客表(blog)
    # 创建用户表
    create table user(
        id int primary key auto_increment,
        name varchar(20)
    );
    # 创建博客表
    create table blog(
        id int primary key auto_increment,
        url varchar(100),
        user_id int unique,
        constraint fk_user foreign key(user_id) references user(id)
        on delete cascade
        on update cascade
    );
    #插入用户表中的记录
    insert into user(name) values
    ('alex'),
    ('wusir'),
    ('egon'),
    ('xiaoma')
    ;
    # 插入博客表的记录
    insert into blog(url,user_id) values
    ('http://www.cnblog/alex',1),
    ('http://www.cnblog/wusir',2),
    ('http://www.cnblog/egon',3),
    ('http://www.cnblog/xiaoma',4)
    ;
    # 查询wusir的博客地址
    select url from blog where user_id=2;
    
    

    二.数据的增删改

    在mysql管理软件中,可以通过sql语句中的DML语言来实现数据的操作,包括

      1.使用insert 实现数据的插入

      2.update 实现数据的更新

      3.使用delete 实现数据的删除

      4.使用select 查询数据

    插入数据  INSERT

      1.查完整的数据(顺序插入)

        语法一:

        inert into 表名(字段1,字段2, 字段3,..) values(值1,值2,值3,...);

        语法二:

        insert into 表名 values (值1,值2, 值3,...);

      2.指定字段插入数据

        语法:

        inert into 表名(字段1,字段2, 字段3,..) values(值1,值2,值3,...);

      3.插入多条记录

        语法:

        INSERT INTO 表名 VALUES
              (值1,值2,值3…值n),
              (值1,值2,值3…值n),
              (值1,值2,值3…值n);
      4.插入查询结果
        语法:
        insert into 表名(字段1,字段2,字段3,...)
            select (字段1,字段2,字段3,...) from 表2
            whert ..;
    数据更新 UPDATE
      语法:
      update 表名 set
        字段1=值1,
        字段2=值2,
        where condition;
    示例:
      update mysql.user set password=password("123")
          where user="root" and host="localhost";
    删除数据 delete
      语法:
    delete from 表名
      where conition;
    示例:
      delete from mysql.user
        where password="";
    三.单表查询
      语法:
      1.单表查询的语法
       SELECT 字段1,字段2... FROM 表名
                WHERE 条件
                GROUP BY field
                HAVING 筛选
                ORDER BY field
                LIMIT 限制条数
      2.关键字的执行优先级
        from , where , group by ,having , select , distinct , order by ,limit

        1.找到表:from

        2.拿着where指定的约束条件,去文件/表中取出一条条记录

        3.将取出的一条条记录进行分组group by,如果没有group by,则整体作为一组

        4.将分组的结果进行having过滤

        5.执行select

        6.去重

        7.将结果按条件排序:order by

        8.限制结果的显示条数

    创建员工表,表的字段和数据类型
    company.employee
        员工id          id                          int                  
        姓名            name                        varchar                                                             
        性别            sex                         enum                                                                  
        年龄            age                         int
        入职日期         hire_date                   date
        岗位            post                        varchar
        职位描述         post_comment             varchar
        薪水            salary                    double
        办公室           office                     int
        部门编号         depart_id                   int
    
    
    #创建表,设置字段的约束条件
    create table employee(
        id int primary key auto_increment,
        name  varchar(20) not null,
        sex enum('male','female') not null default 'male', #大部分是男的
        age int(3) unsigned not null default 28,
        hire_date date not null,
        post varchar(50),
        post_comment varchar(100),
        salary  double(15,2),
        office int,#一个部门一个屋
        depart_id int
    );
    # 查看表结构
    mysql> desc employee;
    +--------------+-----------------------+------+-----+---------+----------------+
    | Field                | Type                              | Null | Key     | Default | Extra          |
    +--------------+-----------------------+------+-----+---------+----------------+
    | id                      | int(11)                            | NO   | PRI     | NULL    | auto_increment |
    | emp_name             | varchar(20)                   | NO   |             | NULL    |                |
    | sex                  | enum('male','female')   | NO   |             | male    |                |
    | age                  | int(3) unsigned               | NO   |             | 28         |                |
    | hire_date        | date                              | NO   |             | NULL    |                |
    | post                 | varchar(50)                   | YES  |         | NULL    |                |
    | post_comment     | varchar(100)                  | YES  |         | NULL    |                |
    | salart               | double(15,2)                  | YES  |         | NULL    |                |
    | office              | int(11)                           | YES  |         | NULL    |                |
    | depart_id        | int(11)                           | YES  |         | NULL    |                |
    +--------------+-----------------------+------+-----+---------+----------------+
    10 rows in set (0.08 sec)
    
    #插入记录
    #三个部门:教学,销售,运营
    insert into employee(name ,sex,age,hire_date,post,salary,office,depart_id) values
    ('egon','male',18,'20170301','老男孩驻沙河办事处外交大使',7300.33,401,1), #以下是教学部
    ('alex','male',78,'20150302','teacher',1000000.31,401,1),
    ('wupeiqi','male',81,'20130305','teacher',8300,401,1),
    ('yuanhao','male',73,'20140701','teacher',3500,401,1),
    ('liwenzhou','male',28,'20121101','teacher',2100,401,1),
    ('jingliyang','female',18,'20110211','teacher',9000,401,1),
    ('jinxin','male',18,'19000301','teacher',30000,401,1),
    ('xiaomage','male',48,'20101111','teacher',10000,401,1),
    
    ('歪歪','female',48,'20150311','sale',3000.13,402,2),#以下是销售部门
    ('丫丫','female',38,'20101101','sale',2000.35,402,2),
    ('丁丁','female',18,'20110312','sale',1000.37,402,2),
    ('星星','female',18,'20160513','sale',3000.29,402,2),
    ('格格','female',28,'20170127','sale',4000.33,402,2),
    
    ('张野','male',28,'20160311','operation',10000.13,403,3), #以下是运营部门
    ('程咬金','male',18,'19970312','operation',20000,403,3),
    ('程咬银','female',18,'20130311','operation',19000,403,3),
    ('程咬铜','male',18,'20150411','operation',18000,403,3),
    ('程咬铁','female',18,'20140512','operation',17000,403,3)
    ;

    where  约束

    where子句中可以使用
    1.比较运算符:>、<、>=、<=、!=
    2.between 80 and 100 :值在80到100之间
    3.in(80,90,100)值是10或20或30
    4.like 'xiaomagepattern': pattern可以是%或者_。%小时任意多字符,_表示一个字符
    5.逻辑运算符:在多个条件直接可以使用逻辑运算符 and or 
    验证结果:
    #1 :单条件查询
    mysql> select id,emp_name from employee where id > 5;
    +----+------------+
    | id | emp_name   |
    +----+------------+
    |  6 | jingliyang |
    |  7 | jinxin     |
    |  8 | xiaomage   |
    |  9 | 歪歪       |
    | 10 | 丫丫       |
    | 11 | 丁丁       |
    | 12 | 星星       |
    | 13 | 格格       |
    | 14 | 张野       |
    | 15 | 程咬金     |
    | 16 | 程咬银     |
    | 17 | 程咬铜     |
    | 18 | 程咬铁     |
    
    #2 多条件查询
    mysql> select emp_name from employee where post='teacher' and salary>10000;
    +----------+
    | emp_name |
    +----------+
    | alex         |
    | jinxin     |
    +----------+
    
    #3.关键字BETWEEN AND
     SELECT name,salary FROM employee 
            WHERE salary BETWEEN 10000 AND 20000;
    
     SELECT name,salary FROM employee 
            WHERE salary NOT BETWEEN 10000 AND 20000;
    
    #注意''是空字符串,不是null
     SELECT name,post_comment FROM employee WHERE post_comment='';
     ps:
            执行
            update employee set post_comment='' where id=2;
            再用上条查看,就会有结果了
    #5:关键字IN集合查询
    mysql>  SELECT name,salary FROM employee WHERE salary=3000 OR salary=3500 OR salary=4000 OR salary=9000 ;
    +------------+---------+
    | name       | salary  |
    +------------+---------+
    | yuanhao    | 3500.00 |
    | jingliyang | 9000.00 |
    +------------+---------+
    rows in set (0.00 sec)
    
    mysql>  SELECT name,salary FROM employee  WHERE salary IN (3000,3500,4000,9000) ;
    +------------+---------+
    | name       | salary  |
    +------------+---------+
    | yuanhao    | 3500.00 |
    | jingliyang | 9000.00 |
    +------------+---------+
    mysql>  SELECT name,salary FROM employee  WHERE salary NOT IN (3000,3500,4000,9000) ;
    +-----------+------------+
    | name      | salary     |
    +-----------+------------+
    | egon      |    7300.33 |
    | alex      | 1000000.31 |
    | wupeiqi   |    8300.00 |
    | liwenzhou |    2100.00 |
    | jinxin    |   30000.00 |
    | xiaomage  |   10000.00 |
    | 歪歪      |    3000.13 |
    | 丫丫      |    2000.35 |
    | 丁丁      |    1000.37 |
    | 星星      |    3000.29 |
    | 格格      |    4000.33 |
    | 张野      |   10000.13 |
    | 程咬金    |   20000.00 |
    | 程咬银    |   19000.00 |
    | 程咬铜    |   18000.00 |
    | 程咬铁    |   17000.00 |
    +-----------+------------+
    rows in set (0.00 sec)
    
    #6:关键字LIKE模糊查询
    通配符’%’
    mysql> SELECT * FROM employee WHERE name LIKE 'jin%';
    +----+------------+--------+-----+------------+---------+--------------+----------+--------+-----------+
    | id | name       | sex    | age | hire_date  | post    | post_comment | salary   | office | depart_id |
    +----+------------+--------+-----+------------+---------+--------------+----------+--------+-----------+
    |  6 | jingliyang | female |  18 | 2011-02-11 | teacher | NULL         |  9000.00 |    401 |         1 |
    |  7 | jinxin     | male   |  18 | 1900-03-01 | teacher | NULL         | 30000.00 |    401 |         1 |
    +----+------------+--------+-----+------------+---------+--------------+----------+--------+-----------+
    rows in set (0.00 sec)
    
    
    通配符'_'
    
    mysql> SELECT  age FROM employee WHERE name LIKE 'ale_';
    +-----+
    | age |
    +-----+
    |  78 |
    +-----+
    row in set (0.00 sec)
    
    练习:
    1. 查看岗位是teacher的员工姓名、年龄
    2. 查看岗位是teacher且年龄大于30岁的员工姓名、年龄
    3. 查看岗位是teacher且薪资在9000-1000范围内的员工姓名、年龄、薪资
    4. 查看岗位描述不为NULL的员工信息
    5. 查看岗位是teacher且薪资是10000或9000或30000的员工姓名、年龄、薪资
    6. 查看岗位是teacher且薪资不是10000或9000或30000的员工姓名、年龄、薪资
    7. 查看岗位是teacher且名字是jin开头的员工姓名、年薪
    
    #对应的sql语句
    select name,age from employee where post = 'teacher';
    select name,age from employee where post='teacher' and age > 30; 
    select name,age,salary from employee where post='teacher' and salary between 9000 and 10000;
    select * from employee where post_comment is not null;
    select name,age,salary from employee where post='teacher' and salary in (10000,9000,30000);
    select name,age,salary from employee where post='teacher' and salary not in (10000,9000,30000);
    select name,salary*12 from employee where post='teacher' and name like 'jin%';
    View Code
    group by 分组查询
    1、首先明确一点:分组发生在where之后,即分组是基于where之后得到的记录而进行的
    2、分组指的是:将所有记录按照某个相同字段进行归类,比如针对员工信息表的职位分组,或者按照性别进行分组等
    3、为何要分组呢?
        取每个部门的最高工资
        取每个部门的员工数
        取男人数和女人数
    小窍门:‘每’这个字后面的字段,就是我们分组的依据
    4、大前提:
        可以按照任意字段分组,但是分组完毕后,比如group by post,只能查看post字段,如果想查看组内信息,需要借助于聚合函数
    当执行以下sql语句的时候,是以post字段查询了组中的第一条数据,没有任何意义,因为我们现在想查出当前组的多条记录。
    
    
    mysql> select * from employee group by post;
    +----+--------+--------+-----+------------+-----------------------------------------+--------------+------------+--------+-----------+
    | id | name   | sex    | age | hire_date  | post                                    | post_comment | salary     | office | depart_id |
    +----+--------+--------+-----+------------+-----------------------------------------+--------------+------------+--------+-----------+
    | 14 | 张野   | male   |  28 | 2016-03-11 | operation                               | NULL         |   10000.13 |    403 |         3 |
    |  9 | 歪歪   | female |  48 | 2015-03-11 | sale                                    | NULL         |    3000.13 |    402 |         2 |
    |  2 | alex   | male   |  78 | 2015-03-02 | teacher                                 |              | 1000000.31 |    401 |         1 |
    |  1 | egon   | male   |  18 | 2017-03-01 | 老男孩驻沙河办事处外交大使              | NULL         |    7300.33 |    401 |         1 |
    +----+--------+--------+-----+------------+-----------------------------------------+--------------+------------+--------+-----------+
    rows in set (0.00 sec)
    
    #由于没有设置ONLY_FULL_GROUP_BY,于是也可以有结果,默认都是组内的第一条记录,但其实这是没有意义的
    如果想分组,则必须要设置全局的sql的模式为ONLY_FULL_GROUP_BY
    mysql> set global sql_mode='ONLY_FULL_GROUP_BY';
    Query OK, 0 rows affected (0.00 sec)
    
    #查看MySQL 5.7默认的sql_mode如下:
    mysql> select @@global.sql_mode;
    +--------------------+
    | @@global.sql_mode  |
    +--------------------+
    | ONLY_FULL_GROUP_BY |
    +--------------------+
    row in set (0.00 sec)
    
    mysql> exit;#设置成功后,一定要退出,然后重新登录方可生效
    Bye
    继续验证通过group by分组之后,只能查看当前字段,如果想查看组内信息,需要借助于聚合函数
    mysql> select * from emp group by post;# 报错
    ERROR 1054 (42S22): Unknown column 'post' in 'group statement'
    
    
    
    mysql>  select post from employee group by post;
    +-----------------------------------------+
    | post                                    |
    +-----------------------------------------+
    | operation                               |
    | sale                                    |
    | teacher                                 |
    | 老男孩驻沙河办事处外交大使              |
    +-----------------------------------------+
    rows in set (0.00 sec)

    聚合函数

    max()求最大值
    min()求最小值
    avg()求平均值
    sum() 求和
    count() 求总个数
    
    #强调:聚合函数聚合的是组的内容,若是没有分组,则默认一组
    # 每个部门有多少个员工
    select post,count(id) from employee group by post;
    # 每个部门的最高薪水
    select post,max(salary) from employee group by post;
    # 每个部门的最低薪水
    select post,min(salary) from employee group by post;
    # 每个部门的平均薪水
    select post,avg(salary) from employee group by post;
    # 每个部门的所有薪水
    select post,sum(age) from employee group by post;

    HAVING 过滤

      having和where的区别:  

      执行优先级从高到低:where > group by > having 
        1. Where 发生在分组group by之前,因而Where中可以有任意字段,但是绝对不能使用聚合函数。
        2. Having发生在分组group by之后,因而Having中可以使用分组的字段,无法直接取到其他字段,可以使用聚合函数

    验证:

    mysql> select * from employee where salary>1000000;
    +----+------+------+-----+------------+---------+--------------+------------+--------+-----------+
    | id | name | sex  | age | hire_date  | post    | post_comment | salary     | office | depart_id |
    +----+------+------+-----+------------+---------+--------------+------------+--------+-----------+
    |  2 | alex | male |  78 | 2015-03-02 | teacher |              | 1000000.31 |    401 |         1 |
    +----+------+------+-----+------------+---------+--------------+------------+--------+-----------+
    row in set (0.00 sec)
    
    mysql> select * from employee having salary>1000000;
    ERROR 1463 (42000): Non-grouping field 'salary' is used in HAVING clause
    
    # 必须使用group by才能使用group_concat()函数,将所有的name值连接
    mysql> select post,group_concat(name) from emp group by post having salary > 10000; ##错误,分组后无法直接取到salary字段
    ERROR 1054 (42S22): Unknown column 'post' in 'field list'
    View Code

    练习

    # 题1:查询各岗位内包含的员工个数小于2的岗位名、岗位内包含员工名字、个数
    mysql> select post,group_concat(name),count(id) from employee group by post;
    +-----------------------------------------+-----------------------------------------------------------+-----------+
    | post                                    | group_concat(name)                                        | count(id) |
    +-----------------------------------------+-----------------------------------------------------------+-----------+
    | operation                               | 程咬铁,程咬铜,程咬银,程咬金,张野                          |         5 |
    | sale                                    | 格格,星星,丁丁,丫丫,歪歪                                  |         5 |
    | teacher                                 | xiaomage,jinxin,jingliyang,liwenzhou,yuanhao,wupeiqi,alex |         7 |
    | 老男孩驻沙河办事处外交大使              | egon                                                      |         1 |
    +-----------------------------------------+-----------------------------------------------------------+-----------+
    rows in set (0.00 sec)
    
    mysql> select post,group_concat(name),count(id) from employee group by post having count(id)<2;
    +-----------------------------------------+--------------------+-----------+
    | post                                    | group_concat(name) | count(id) |
    +-----------------------------------------+--------------------+-----------+
    | 老男孩驻沙河办事处外交大使              | egon               |         1 |
    +-----------------------------------------+--------------------+-----------+
    row in set (0.00 sec)
    
    
    #题2:查询各岗位平均薪资大于10000的岗位名、平均工资
    mysql> select post,avg(salary) from employee group by post having avg(salary) > 10000;
    +-----------+---------------+
    | post      | avg(salary)   |
    +-----------+---------------+
    | operation |  16800.026000 |
    | teacher   | 151842.901429 |
    +-----------+---------------+
    rows in set (0.00 sec)
    
    #题3:查询各岗位平均薪资大于10000且小于20000的岗位名、平均工资
    mysql> select post,avg(salary) from employee group by post having avg(salary) > 10000 and avg(salary) <20000;
    +-----------+--------------+
    | post      | avg(salary)  |
    +-----------+--------------+
    | operation | 16800.026000 |
    +-----------+--------------+
    row in set (0.00 sec)
    View Code

    order by  查询排序

    单列排序
        SELECT * FROM employee ORDER BY age;
        SELECT * FROM employee ORDER BY age ASC;
        SELECT * FROM employee ORDER BY age DESC;
    按多列排序:先按照age升序排序,如果年纪相同,则按照id降序
        SELECT * from employee
            ORDER BY age ASC,
            id DESC;
    验证:
    SELECT * from employee ORDER BY age ASC,id DESC;
    mysql> SELECT * from employee ORDER BY age ASC,id DESC;
    +----+------------+--------+-----+------------+-----------------------------------------+--------------+------------+--------+-----------+
    | id | name       | sex    | age | hire_date  | post                                    | post_comment | salary     | office | depart_id |
    +----+------------+--------+-----+------------+-----------------------------------------+--------------+------------+--------+-----------+
    | 18 | 程咬铁     | female |  18 | 2014-05-12 | operation                               | NULL         |   17000.00 |    403 |         3 |
    | 17 | 程咬铜     | male   |  18 | 2015-04-11 | operation                               | NULL         |   18000.00 |    403 |         3 |
    | 16 | 程咬银     | female |  18 | 2013-03-11 | operation                               | NULL         |   19000.00 |    403 |         3 |
    | 15 | 程咬金     | male   |  18 | 1997-03-12 | operation                               | NULL         |   20000.00 |    403 |         3 |
    | 12 | 星星       | female |  18 | 2016-05-13 | sale                                    | NULL         |    3000.29 |    402 |         2 |
    | 11 | 丁丁       | female |  18 | 2011-03-12 | sale                                    | NULL         |    1000.37 |    402 |         2 |
    |  7 | jinxin     | male   |  18 | 1900-03-01 | teacher                                 | NULL         |   30000.00 |    401 |         1 |
    |  6 | jingliyang | female |  18 | 2011-02-11 | teacher                                 | NULL         |    9000.00 |    401 |         1 |
    |  1 | egon       | male   |  18 | 2017-03-01 | 老男孩驻沙河办事处外交大使              | NULL         |    7300.33 |    401 |         1 |
    | 14 | 张野       | male   |  28 | 2016-03-11 | operation                               | NULL         |   10000.13 |    403 |         3 |
    | 13 | 格格       | female |  28 | 2017-01-27 | sale                                    | NULL         |    4000.33 |    402 |         2 |
    |  5 | liwenzhou  | male   |  28 | 2012-11-01 | teacher                                 | NULL         |    2100.00 |    401 |         1 |
    | 10 | 丫丫       | female |  38 | 2010-11-01 | sale                                    | NULL         |    2000.35 |    402 |         2 |
    |  9 | 歪歪       | female |  48 | 2015-03-11 | sale                                    | NULL         |    3000.13 |    402 |         2 |
    |  8 | xiaomage   | male   |  48 | 2010-11-11 | teacher                                 | NULL         |   10000.00 |    401 |         1 |
    |  4 | yuanhao    | male   |  73 | 2014-07-01 | teacher                                 | NULL         |    3500.00 |    401 |         1 |
    |  2 | alex       | male   |  78 | 2015-03-02 | teacher                                 |              | 1000000.31 |    401 |         1 |
    |  3 | wupeiqi    | male   |  81 | 2013-03-05 | teacher                                 | NULL         |    8300.00 |    401 |         1 |
    +----+------------+--------+-----+------------+-----------------------------------------+--------------+------------+--------+-----------+
    rows in set (0.01 sec)
    
    mysql>
    View Code

    练习

    # 题目1.查询所有员工信息,先按照age升序排序,如果age相同则按照hire_date降序排序
    select * from employee ORDER BY age asc,hire_date desc;
    
    # 题目2.查询各岗位平均薪资大于10000的岗位名、平均工资,结果按平均薪资升序排列
    mysql> select post,avg(salary) from employee group by post having avg(salary) > 10000 order by avg(salary) asc;
    +-----------+---------------+
    | post      | avg(salary)   |
    +-----------+---------------+
    | operation |  16800.026000 |
    | teacher   | 151842.901429 |
    +-----------+---------------+
    rows in set (0.00 sec)
    
    # 题目3.查询各岗位平均薪资大于10000的岗位名、平均工资,结果按平均薪资降序排列 
    mysql> select post,avg(salary) from employee group by post having avg(salary) > 10000 order by avg(salary) desc;
    +-----------+---------------+
    | post      | avg(salary)   |
    +-----------+---------------+
    | teacher   | 151842.901429 |
    | operation |  16800.026000 |
    +-----------+---------------+
    rows in set (0.00 sec)
    
    mysql>
    View Code

    limit   限制查询的记录数

        SELECT * FROM employee ORDER BY salary DESC 
         LIMIT 3;                    #默认初始位置为0 
    
        SELECT * FROM employee ORDER BY salary DESC
            LIMIT 0,5; #从第0开始,即先查询出第一条,然后包含这一条在内往后查5条
    
        SELECT * FROM employee ORDER BY salary DESC
            LIMIT 5,5; #从第5开始,即先查询出第6条,然后包含这一条在内往后查5条

    练习:

    # 第1页数据
      mysql> select * from  employee limit 0,5;
    +----+-----------+------+-----+------------+-----------------------------------------+--------------+------------+--------+-----------+
    | id | name      | sex  | age | hire_date  | post                                    | post_comment | salary     | office | depart_id |
    +----+-----------+------+-----+------------+-----------------------------------------+--------------+------------+--------+-----------+
    |  1 | egon      | male |  18 | 2017-03-01 | 老男孩驻沙河办事处外交大使              | NULL         |    7300.33 |    401 |         1 |
    |  2 | alex      | male |  78 | 2015-03-02 | teacher                                 |              | 1000000.31 |    401 |         1 |
    |  3 | wupeiqi   | male |  81 | 2013-03-05 | teacher                                 | NULL         |    8300.00 |    401 |         1 |
    |  4 | yuanhao   | male |  73 | 2014-07-01 | teacher                                 | NULL         |    3500.00 |    401 |         1 |
    |  5 | liwenzhou | male |  28 | 2012-11-01 | teacher                                 | NULL         |    2100.00 |    401 |         1 |
    +----+-----------+------+-----+------------+-----------------------------------------+--------------+------------+--------+-----------+
    rows in set (0.00 sec)
    # 第2页数据
    mysql> select * from  employee limit 5,5;
    +----+------------+--------+-----+------------+---------+--------------+----------+--------+-----------+
    | id | name       | sex    | age | hire_date  | post    | post_comment | salary   | office | depart_id |
    +----+------------+--------+-----+------------+---------+--------------+----------+--------+-----------+
    |  6 | jingliyang | female |  18 | 2011-02-11 | teacher | NULL         |  9000.00 |    401 |         1 |
    |  7 | jinxin     | male   |  18 | 1900-03-01 | teacher | NULL         | 30000.00 |    401 |         1 |
    |  8 | xiaomage   | male   |  48 | 2010-11-11 | teacher | NULL         | 10000.00 |    401 |         1 |
    |  9 | 歪歪       | female |  48 | 2015-03-11 | sale    | NULL         |  3000.13 |    402 |         2 |
    | 10 | 丫丫       | female |  38 | 2010-11-01 | sale    | NULL         |  2000.35 |    402 |         2 |
    +----+------------+--------+-----+------------+---------+--------------+----------+--------+-----------+
    rows in set (0.00 sec)
    # 第3页数据
    mysql> select * from  employee limit 10,5;
    +----+-----------+--------+-----+------------+-----------+--------------+----------+--------+-----------+
    | id | name      | sex    | age | hire_date  | post      | post_comment | salary   | office | depart_id |
    +----+-----------+--------+-----+------------+-----------+--------------+----------+--------+-----------+
    | 11 | 丁丁      | female |  18 | 2011-03-12 | sale      | NULL         |  1000.37 |    402 |         2 |
    | 12 | 星星      | female |  18 | 2016-05-13 | sale      | NULL         |  3000.29 |    402 |         2 |
    | 13 | 格格      | female |  28 | 2017-01-27 | sale      | NULL         |  4000.33 |    402 |         2 |
    | 14 | 张野      | male   |  28 | 2016-03-11 | operation | NULL         | 10000.13 |    403 |         3 |
    | 15 | 程咬金    | male   |  18 | 1997-03-12 | operation | NULL         | 20000.00 |    403 |         3 |
    +----+-----------+--------+-----+------------+-----------+--------------+----------+--------+-----------+
    rows in set (0.00 sec)
    View Code
    
    
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  • 原文地址:https://www.cnblogs.com/chenxi67/p/9799115.html
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