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  • UVA

    UVA- 796

    /**
              题意:给出一个图,然后看此图的存在的桥,并且输出是哪一个,
              做法:Tarjan(不存在重边)
    **/
    #include<iostream>
    #include<stdio.h>
    #include<string.h>
    #include<cmath>
    #include<algorithm>
    #include<vector>
    using namespace std;
    #define maxn 11000
    #define maxm 100010
    #define INF 0x3f3f3f3f
    struct Edge
    {
        int to;
        int next;
        bool cut;
    } edge[maxm];
    int head[maxn],tot;
    int Low[maxn],DFN[maxn],Stack[maxn];
    int Index,top;
    bool Instack[maxn];
    bool cut[maxn];
    int add_block[maxn];
    int bridge;
    void addedge(int u,int v)
    {
        edge[tot].to = v;
        edge[tot].next = head[u];
        edge[tot].cut = false;
        head[u] = tot++;
    }
    void Tarjan(int u,int pre)
    {
        int v;
        Low[u] = DFN[u] = ++Index;
        Stack[top++] = u;
        Instack[u] = true;
        int son = 0;
        for(int i=head[u]; i != -1; i = edge[i].next)
        {
            v = edge[i].to;
            if(v == pre)
            {
                continue;
            }
            if(!DFN[v])
            {
                son++;
                Tarjan(v,u);
                if(Low[u] > Low[v]) Low[u] = Low[v];
                ///
                if(Low[v]>DFN[u])
                {
                    bridge++;
                    edge[i].cut = true;
                    edge[i^1].cut = true;
                }
                ///割点
                if(u!=pre && Low[v] >= DFN[u])
                {
                    cut[u] = true;
                    add_block[u] ++;
                }
            }
            else if(Low[u] > DFN[v])
            {
                Low[u] = DFN[v];
            }
        }
        if(u == pre && son>1) cut[u] = true;
        if(u == pre)add_block[u] = son -1;
        Instack[u] = false;
        top--;
    }
    void solve(int N)
    {
        memset(DFN,0,sizeof(DFN));
        memset(Instack,false,sizeof(Instack));
        memset(add_block,0,sizeof(add_block));
        memset(cut,false,sizeof(cut));
        Index = top = 0;
        bridge = 0;
        for(int i=1; i<=N; i++)
        {
            if(!DFN[i]) Tarjan(i,i);
        }
        printf("%d critical links
    ",bridge);
        vector<pair <int,int> > ans;
        for(int u = 1;u<=N;u++)
        {
                        for(int i=head[u];i != -1;i = edge[i].next)
                        {
                                  if(edge[i].cut && edge[i].to > u)
                                  {
                                            ans.push_back(make_pair(u,edge[i].to));
                                  }
                        }
        }
        sort(ans.begin(),ans.end());
        for(int i=0;i<ans.size();i++)
        {
                        printf("%d - %d
    ",ans[i].first - 1,ans[i].second -1);
        }
        printf("
    ");
    }
    void Init()
    {
              tot = 0;
              memset(head,-1,sizeof(head));
    }
    int main()
    {
    #ifndef ONLINE_JUDGE
        freopen("in.txt","r",stdin);
    #endif // ONLINE_JUDGE
        int n;
        while(~scanf("%d",&n))
        {
            int u,Q,v;
            Init();
            for(int i=1;i<=n;i++)
            {
                                  scanf("%d (%d)",&u,&Q);
                                  u++;
                                  while(Q--)
                                  {
                                            scanf("%d",&v);
                                            v++;
                                            if(v<=u) continue;
                                            addedge(u,v);
                                            addedge(v,u);
                                  }
            }
            solve(n);
    
        }
        return 0;
    }
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  • 原文地址:https://www.cnblogs.com/chenyang920/p/4367689.html
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