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  • [LeetCode] Unique Paths II

    Follow up for "Unique Paths":

    Now consider if some obstacles are added to the grids. How many unique paths would there be?

    An obstacle and empty space is marked as 1 and 0 respectively in the grid.

    For example,

    There is one obstacle in the middle of a 3x3 grid as illustrated below.

    [
      [0,0,0],
      [0,1,0],
      [0,0,0]
    ]
    

    The total number of unique paths is 2.

    Note: m and n will be at most 100.

    同上题,稍作修改。

     1 class Solution {
     2 public:
     3     int uniquePathsWithObstacles(vector<vector<int> > &obstacleGrid) {
     4         // Start typing your C/C++ solution below
     5         // DO NOT write int main() function
     6         vector<vector<int> > f(obstacleGrid.size(), vector<int>(obstacleGrid[0].size()));
     7                
     8         f[0][0] = obstacleGrid[0][0] == 1 ? 0 : 1;
     9         for(int i = 1; i < f.size(); i++)
    10             f[i][0] = obstacleGrid[i][0] == 1 ? 0 : f[i-1][0];
    11             
    12         for(int i = 1; i < f[0].size(); i++)
    13             f[0][i] = obstacleGrid[0][i] == 1 ? 0 : f[0][i-1];
    14             
    15         for(int i = 1; i < f.size(); i++)
    16             for(int j = 1; j < f[i].size(); j++)
    17                 f[i][j] = obstacleGrid[i][j] == 1 ? 0 : f[i-1][j] + f[i][j-1];
    18                 
    19         return f[f.size()-1][f[0].size()-1];
    20     }
    21 };
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  • 原文地址:https://www.cnblogs.com/chkkch/p/2772282.html
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