第一周训练 | STL和基本数据结构

A - 圆桌问题： HDU - 4841

#include<iostream>
#include<vector>
#include<stdio.h>
#include<string>
using namespace std;
int main()
{
    vector<int> table;
    int n,m;
    while(scanf("%d%d",&n,&m)!=EOF)
    {
        table.clear();
        for(int i=0;i<2*n;++i)
        {
            table.push_back(i);
        }
        int pos = 0;
        for(int i=0;i<n;++i)
        {
            pos = (pos+m-1)%table.size();
            table.erase(table.begin()+pos);
        }
        int j=0;
        for(int i=0;i<2*n;++i)
        {
            if(!(i%50)&&i)cout<<endl;
            if(j<table.size()&&i==table[j])
            {
                ++j;
                cout<<"G";
            }
            else
            {
                cout<<"B";
            }
        }
        cout<<endl<<endl;
    }
    return 0;
 } 

C - 简单计算器 HDU - 1237

好自闭啊，找了半天还是WA了，完全不知道WA在哪里了Orz，先存一个档：

#include<iostream>
#include<stack>
#include<stdio.h>
#include<string>
#include<map>
#define CHECK_NUM(ch) ('0'<=ch&&ch<='9') 
#define CHECK_OP(ch) ('+'==ch ||'-'==ch||'*'==ch||'/'==ch ||''==ch)
using namespace std;
map<char,int>dir;
stack<double> num;
stack<char> op;
stack<double> newnum;
stack<char> newop;
double OPT(double one,double two,char temp)
{    
//    printf("%f",two);
    double three=0;
    switch(temp) 
    {
        case '+':three = two + one;break;
        case '-':three = two - one;break;
        case '*':three = two * one;break;
        case '/':three = two / one;break;
    }
//    printf("%c %lf = %lf
",temp,one,three);
    return three;
}
void initi()
{
    while(!num.empty())num.pop();
    while(!op.empty())op.pop();
    while(!newop.empty())newop.pop();
    while(!newnum.empty())newnum.pop();
}
void STACK(char ch)
{
//    cout<<ch<<endl; 
    if(!op.empty()&&num.size()>1)
    {
        char temp=op.top();
//        cout<<"当前栈顶："<<temp<<",当前扫描："<<ch<<endl;
        if(dir[temp]>=dir[ch])
        {     
            op.pop(); 
            double one=num.top();num.pop();
            double two=num.top();num.pop();
            num.push(OPT(one,two,temp));    
//            cout<<"入栈num:"<<num.top()<<endl;
        }
     
    }
    op.push(ch);
}
int main()
{
    char ch='';
    double result=0;
    
    dir['+']=1;    dir['-']=1;
    dir['*']=2;    dir['/']=2;
    dir['']=0;
    while(1)
    {
        string a="";
        getline(cin,a);
        initi();
        
        if(a=="0")break;
        for(int i=0;i<=a.length();++i)
        {    
            double nums=0;
            if(CHECK_NUM(a[i]))
            {
                while(CHECK_NUM(a[i]))
                {
                    nums+=a[i]-'0';
                    nums*=10;
                    i++;            
                }
                nums/=10;
//                cout<<"nums"<<nums<<endl; 
                num.push(nums);
//                printf("%.2f
",num.top());
            }
            
            if(CHECK_OP(a[i])) 
            {
                STACK(a[i]); //如果是操作数就入操作数栈
            }
        }
        
        while(!op.empty()) 
        {
            newop.push(op.top());
            op.pop();
        }
        while(!num.empty()) 
        {
            newnum.push(num.top());
            num.pop();
        }
        while(!newop.empty()&&newnum.size()>1)
        {
            char temp=newop.top();newop.pop();
//            cout<<"当前弹出："<<temp<<endl; 
            double one=newnum.top();newnum.pop();
            double two=newnum.top();newnum.pop();
            newnum.push(OPT(two,one,temp));    
//            cout<<"入栈num:"<<newnum.top()<<endl;    
        }
//        printf(">>%.2lf
",newnum.top());
//        cout<<newnum.size(); 
        printf("%.2lf
",newnum.top());
    }
    return 0;
 } 

贴一个师傅的AC:

#include<cstdio>
#include<cstring>
#include<algorithm>
#include<cmath>
#include<iostream>
#include<iomanip>
using namespace std;
 
typedef long long LL;
#define rep(i,a,b) for(int i=a;i<b;++i)
 
const double eps=1e-9;
const int N=1010;
char str[N];
 
double stk1[N];//操作数栈 
int p1;//操作数栈的栈顶指针 
char stk2[N];//运算符栈 
int p2;//运算符栈的栈顶指针 
 
double op(double a,double b,char ch){
    if(ch=='+')return a+b;
    else if(ch=='-')return a-b;
    else if(ch=='*')return a*b;
    else return a/b;
}
 
//优先级比较函数加括号的话,只需要修改这里就好了 
//ch1:扫描到的,ch2:栈顶的
int comp(char ch1,char ch2)
{
    int a=0,b=0;
    if(ch1=='*'||ch1=='/')a=1;
    if(ch2=='*'||ch2=='/')b=1;
    return a<=b;
}
int main()
{
    while(gets(str)) //读入一行 
    {
        
        p1=0,p2=0;
        int len=strlen(str);
        if(len==1&&str[0]=='0')break;
        int i=0;
        double sum=0;
        while(i<len&&str[i]>='0'&&str[i]<='9') 
        {
            sum=sum*10+str[i]-'0';
            i++;
        }
        stk1[p1++]=sum;//得到操作数 
        while(i<len) 
        {
            i++;//跳过空格 
            char ch=str[i];//读取操作数 
            i+=2;//跳过空格 
            double sum=0;//得到第二个操作数 
            while(i<len&&str[i]>='0'&&str[i]<='9') 
            {
                sum=sum*10+str[i]-'0';
                i++;
            }
            
            if(p2==0)//如果操作符栈为空，操作符就进栈 
            {
                stk2[p2++]=ch;
            }
            else
            {    
                //当前读到的操作数的优先级小于等于栈顶的优先级 
                //并且运算符栈不为空
                while(p2>0&&comp(ch,stk2[p2-1]))
                {
                     
                    double ans=op(stk1[p1-2],stk1[p1-1],stk2[p2-1]);//计算新的值        
                    p2-=1;
                    p1-=2;
                    stk1[p1++]=ans;//新的值入操作数栈 
                }
                stk2[p2++]=ch;
            }
            stk1[p1++]=sum;
        }
        while(p2!=0)//当操作符栈不为空 
        {
            double ans=op(stk1[p1-2],stk1[p1-1],stk2[p2-1]);
            p1-=2;
            stk1[p1++]=ans;
            p2--;
        }         
        printf("%.2f
",stk1[0]);
    }
    return 0;
}

D - ACboy needs your help again! HDU - 1702

#include<iostream>
#include<string>
#include<queue>
#include<stack>
using namespace std;
int main()
{
    int t,n,temp;
    cin>>t;
    while(t--)
    {
        string str,str1;
        queue<int>Q;
        stack<int>S;
        cin>>n>>str;
        for(int i=0;i<n;++i)
        {
            if(str=="FIFO")
            {
                cin>>str1;
                if(str1=="IN")
                {
                    cin>>temp;
                    Q.push(temp);
                }
                if(str1=="OUT")
                {
                    if(Q.empty()) cout<<"None"<<endl;
                    else
                    {
                        cout<<Q.front()<<endl;
                        Q.pop();
                    }
                }
            }
            else
            {
                cin>>str1;
                if(str1=="IN")
                {
                    cin>>temp;S.push(temp);
                }
                if(str1=="OUT")
                {
                    if(S.empty()) cout<<"None"<<endl;
                    else
                    {
                        cout<<S.top()<<endl;
                        S.pop(); 
                    }
                    
                }    
            }
        }
    } 
    return 0;
}

E - 看病要排队 HDU - 1873 

#include<iostream>
#include<string>
#include<queue>
#include<stack>
using namespace std;

int id;
typedef struct p
{
    int id;
    int pr;    
}people;
bool operator < (const people &a,const people &b)
{
    //当a,b的优先级一样的时候，比较a,b的编号 
    if(a.pr== b.pr) return (a.id > b.id);//当优先级一样的时候，先来的人先看病 
    return (a.pr < b.pr);
 
}
priority_queue<people> A;
priority_queue<people> B;
priority_queue<people> C;
int intital()
{
    while(!A.empty()) A.pop();
    while(!B.empty()) B.pop();
    while(!C.empty()) C.pop();
    id=0;
    return 0;
}
int main()
{
    int num=1;
    while(scanf("%d",&num)!=EOF)
    { 
        intital();
//        cout<<"输入的n:"<<num<<endl; 
        for(int i=0;i<num;++i)
        {
            string str;
            people person;
            int doctor;
            cin>>str>>doctor;
//            cout<<"str,doctor:"<<str<<","<<doctor<<endl;
            
             
            if(str=="IN")
            {
                ++id;//人数自增
                person.id=id;
                cin>>person.pr; 
                
//                cout<<",person.pr"<<person.pr<<endl;
                switch(doctor)
                {
                    case 1:
                    {
                        A.push(person);
                        break;
                    }
                    case 2:
                    {
                        B.push(person);
                        break;
                    } 
                    case 3:
                    {
                        C.push(person);
                        break;
                    }
                         
                }
            }
            else
            {
                switch(doctor)
                {
                    case 1:
                    {
                        if(A.empty())
                        {
                             cout<<"EMPTY"<<endl;
                        }
                        else
                        {
                            cout<<A.top().id<<endl;
                            A.pop();
                        }
                        break;
                    }
                    case 2:
                    {
                        if(B.empty())
                        {
                             cout<<"EMPTY"<<endl;
                        }
                        else
                        {
                            cout<<B.top().id<<endl;
                            B.pop();
                        }
                        break;
                    } 
                    case 3:
                    {
                        if(C.empty())
                        {
                             cout<<"EMPTY"<<endl;
                        }
                        else
                        {
                            cout<<C.top().id<<endl;
                            C.pop();
                        }
                        break;
                    }
                         
                }
            } 
        }
        
        
    }
    return 0;
}

士兵队列训练问题 HDU - 1276 

#include<iostream>
#include<map>
#include<string>
#include<list>
using namespace std;
int main()
{
    int t,n;
    cin>>t;
    while(t--)
    {
        cin>>n;
        int k=2;
        list<int>mylist;
        list<int>::iterator it;
        for(int i=1;i<=n;++i)mylist.push_back(i);
        while(mylist.size()>3)
        {
            int num=1;
            for(it=mylist.begin();it!=mylist.end();)
            {
                if(num++%k==0)
                {
                    it = mylist.erase(it);
                }
                else
                {
                    ++it;
                }
            }
            k==2?k=3:k=2;
        }
        for(it=mylist.begin();it!=mylist.end();++it)
        {
            if(it!=mylist.begin())cout<<" "; 
            cout<<*it;
        }
        cout<<endl;
    }
    return 0;
    
 } 

G - 产生冠军 HDU - 2094 

#include<iostream>
#include<set>
#include<string>
using namespace std;
int main()
{
    set<string>A,B;
    string s1,s2;
    int n;
    while(cin>>n&&n)
    {
        for(int i=0;i<n;++i)
        {
            cin>>s1>>s2;
            A.insert(s1);A.insert(s2);
            B.insert(s2);
        }
        if(A.size()-B.size()==1)
        {
            cout<<"Yes"<<endl;
        }
        else
        {
            cout<<"No"<<endl;
        }
        A.clear();
        B.clear();
    }
    return 0;
}

H - Shopping HDU - 2648 ：map的遍历

#include<iostream>
#include<map>
#include<string>
using namespace std;
int main()
{
    int  n,m,p;
    map<string,int>shop;
    while(cin>>n)
    {
        string s;
        for(int i=1;i<=n;++i)cin>>s;
        cin>>m; 
        while(m--)
        {
            for(int i=1;i<=n;++i)
            {
                cin>>p>>s;
                shop[s]+=p;
            }    
            int rank =1;
            map<string,int>::iterator it;
            for(it=shop.begin();it!=shop.end();it++)
            {
                if(it->second>shop["memory"])
                {
                    rank++;
                }
            }
            cout<<rank<<endl;
        }
        shop.clear();
    }

    
    return 0;
    
 } 

I - Ignatius and the Princess II HDU - 1027：next_permutation

#include<iostream>
#include<map>
#include<string>
#include<list>
#include<algorithm>
using namespace std;
int a[1001];
int main()
{
    int m,n;
    while(cin>>n>>m)
    {
        for(int i=1;i<=n;++i) a[i]=i;
        int b=1;
        do
        {
            if(b==m)break;
            b++;
         }while(next_permutation(a+1,a+n+1));
         for(int i=1;i<n;++i)
         {
             cout<<a[i]<<" ";
         }
         cout<<a[n]<<endl;
    }
    return 0;
 } 

J - 排列2 HDU - 1716 

#include<iostream>
#include<map>
#include<string>
#include<list>
#include<vector>
#include<algorithm>
#include<set>
#include<string.h>
using namespace std;
int main()
{
    while(1)
    {
        int num[4]={};
        vector<int> m[100];
        int index[10];
        memset(index,0,sizeof(int)*10);
        int count=0;
        map<int,bool> visit;//标记是否重复出现 
        set<int>s;
        s.clear();
        for(int i=0;i<4;++i)
        {
            cin>>num[i];
            if(num[i]==0)++count; //计算0的个数
            index[num[i]]=1;
        }
        if(count==4)break;//如果有4个0就结束掉
        sort(num,num+4);
        do 
        {
            int str=0;
            if(num[0]==0)continue;
            for(int i=0;i<4;++i)
            {
                str+=num[i];
                str*=10;
            } 
            str/=10;
//            cout<<">>"<<str<<","<<visit[str]<<" ";
            if(!visit[str]) 
            {
                m[num[0]].push_back(str);
//                cout<<"输入到导出表的："<<"m["<<num[0]<<"]="<<str<<endl;
                visit[str]=1;
            }
                
        }while(next_permutation(num,num+4));
        int i=1,k=0;
        for(int j=0;j<10;++j)if(index[j])++k;
        for(;i<=9;++i)
        {    
            if(index[i])
            {
//                cout<<"第一组"<<i<<endl;
                index[i]=0;
                cout<<m[i][0];
                for(int j=1;j<m[i].size();++j)
                {
                    cout<<" "<<m[i][j];
                }
                k--;
                cout<<endl;
            }
            if(k==1)break;    
        }
        for(;i<=9;++i)
        {    
            
            if(index[i])
            {
                
                index[i]=0;
                cout<<m[i][0];
                for(int j=1;j<m[i].size();++j)
                {
                    cout<<" "<<m[i][j];
                }    
            }    
        }
        cout<<endl;
    }
    
    return 0;
 } 

贴一份AC:https://blog.csdn.net/leo6033/article/details/79249163

#include<stdio.h>
int a[4],i;
void sum(int num[],int x1, int x2, int x3, int x4)
{
    num[i++] = a[x1] * 1000 + a[x2] * 100 + a[x3] * 10 + a[x4];
    num[i++] = a[x1] * 1000 + a[x2] * 100 + a[x4] * 10 + a[x3];
    num[i++] = a[x1] * 1000 + a[x3] * 100 + a[x2] * 10 + a[x4];
    num[i++] = a[x1] * 1000 + a[x3] * 100 + a[x4] * 10 + a[x2];
    num[i++] = a[x1] * 1000 + a[x4] * 100 + a[x2] * 10 + a[x3];
    num[i++] = a[x1] * 1000 + a[x4] * 100 + a[x3] * 10 + a[x2];
}
int main()
{
    int p = 0;
    while (~scanf("%d %d %d %d", &a[0], &a[1], &a[2], &a[3]))
    {
        int  num[24] = { 0 };
        if (!a[0] && !a[1] && !a[2] && !a[3])
        {
            break;
        }
        if (p == 0)p = 1;
        else printf("
");
        i = 0;
        sum(num, 0, 1, 2, 3);
        sum(num, 1, 2, 3, 0);
        sum(num, 2, 3, 0, 1);
        sum(num, 3, 0, 1, 2);
        int temp,j;
        for (i = 23; i >0; i--)
        {
            for (j = 0; j < i-1; j++)
            {
                if (num[j] > num[j + 1])
                {
                    temp = num[j];
                    num[j] = num[j + 1];
                    num[j + 1] = temp;
                }
            }
        }
 
        for (i = 0; i < 23; i++)
        {
            //printf("%d ",num[i]);
            if (num[i] != num[i + 1]&&num[i]>1000)
            {
                printf("%d", num[i]);
                if (num[i] / 1000 != num[i + 1] / 1000)
                {
                    printf("
");
                }
                else
                {
                    printf(" ");
                }
            }
        }
        printf("%d
", num[i]);
    }
    return 0;
}