zoukankan      html  css  js  c++  java
  • 判断2个正整数是否互质

    1.   Two positive integers i and j are considered to be co-prime if there exists no integer greater than 1 that divides them both. 

    Write a function co-prime that has two input parameters, i and j, and returns a value of 1 for true if i and j are co-prime. 

    Otherwise, co-prime should return a value of 0 for false.  Also, write a driver program to test the your function. 

    You should specify the input / output format of your program.

     

    使用欧几里得算法(辗转相除法)

    GCD is stand for greatest common divisor最大公约数

    Hint - You can use the Euclidean Algorithm which is outlined as below:

    To find the greatest common divisor between two natural numbers, divide one by the other and take the remainder (i.e. modulus operation). 

    为了找到2个自然数a,b的最大公约数,用一个数a除以另外一个数b,取余数

    If the remainder is non-zero, take the divider and the modulus as the input and repeat the modulus operation until the modulus becomes zero. 

    如果余数不是0,把除数和余数作为输入,重复求余的操作。直到余数变为0

    The last divider used before the modulus becomes zero is the greatest common divisor (GCD) between the two numbers that we start out with. 

    在余数变为0前的最后一个除数,是2个数字的最大公约数

    If the GCD is 1, then the two numbers are co-prime (i.e. relatively prime).  (30 points)

    如果最大公约数是1,那么这2个数字互质

    Example 1: Find the GCD of 84 and 140.

    140 % 84 = 56 ,  84 % 56 = 28,  56 % 28 = 0

    the GCD of 84 and 140 is 28 Þ not co-prime.

    Example 2: Find the GCD of 12 and 35

    12 % 35 = 12,  35 % 12 = 11,  12 % 11 = 1,  11 % 1 = 0

    the GCD of 35 and 12 is 1 Þ co-prime.

            public static bool CoPrime(int a,int b)
            {
                bool flag = false;
                int c;
                while (true)
                {
                    c = a % b;
                    if (c == 0)
                    {
                        if (b == 1)
                        {
                            flag = true;
                        }
                        break;
                    }
                    a = b;
                    b = c;
                }
                return flag;
            }
  • 相关阅读:
    五星评价
    IE9以上 CSS文件因Mime类型不匹配而被忽略 其他浏览器及IE8以下显示正常
    js时间显示设置
    jq手风琴---点击时列表的左边距逐渐减小
    break continue return
    validate插件:验证密码没有空格 用户名是5-10位 至少包含数字和大小写字母中的两种字符
    Commons IO
    Servlet & JSP
    设计模式
    Table of Contents
  • 原文地址:https://www.cnblogs.com/chucklu/p/4626855.html
Copyright © 2011-2022 走看看