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  • Codeforces Round #663 (Div. 2)

    link

    Problems

    # Name
    A Suborrays
    B Fix You
    C Cyclic Permutations
    D 505
    E Pairs of Pairs

    Solution

    A

    #include<set>
    #include<map>
    #include<ctime>
    #include<queue>
    #include<stack>
    #include<vector>
    #include<cstdio>
    #include<cstdlib>
    #include<cstring>
    #include<iostream>
    #include<algorithm>
    #define rint register int
    typedef long long LL;
    typedef unsigned long long ULL;
    using namespace std;
    int T,n;
    int main()
    {
    //	freopen("1.in","r",stdin);
    	scanf("%d",&T);
    	while(T--) {
    		scanf("%d",&n);
    		for(int i=1;i<=n;i++) 
    			printf("%d ",i);
    		printf("
    ");
    	}
    	return 0;
    }
    

    B

    #include<set>
    #include<map>
    #include<ctime>
    #include<queue>
    #include<stack>
    #include<vector>
    #include<cstdio>
    #include<cstdlib>
    #include<cstring>
    #include<iostream>
    #include<algorithm>
    #define rint register int
    typedef long long LL;
    typedef unsigned long long ULL;
    using namespace std;
    const int N=256;
    int T,n,m;
    char a[N][N];
    int main()
    {
    //	freopen("1.in","r",stdin);
    	int i;
    	scanf("%d",&T);
    	while(T--) {
    		scanf("%d%d",&n,&m);
    		int ans=0;
    		for(i=1;i<=n;i++)
    			scanf("%s",a[i]+1);
    		for(i=1;i<=n;i++) 
    			ans+=(a[i][m]=='R');
    		for(i=1;i<=m;i++) 
    			ans+=(a[n][i]=='D');
    		cout<<ans<<endl;
    	}
    	return 0;
    }
    

    C

    #include<set>
    #include<map>
    #include<ctime>
    #include<queue>
    #include<stack>
    #include<vector>
    #include<cstdio>
    #include<cstdlib>
    #include<cstring>
    #include<iostream>
    #include<algorithm>
    #define rint register int
    typedef long long ULL;
    using namespace std;
    const ULL MOD=1e9+7;
    ULL n;
    ULL p=1,k=1;
    int main()
    {
    	scanf("%lld",&n);
    	for(ULL i=1;i<=n;i++) 
    		p=p*i%MOD;
    	for(ULL i=1;i<=n-1;i++) 
    		k=k*2%MOD;
    	printf("%lld",((p-k)%MOD+MOD)%MOD);
    	return 0;
    }
    
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  • 原文地址:https://www.cnblogs.com/cjl-world/p/13467366.html
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