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  • 另一个小数点

     1 import java.util.Scanner;
    2 public class Test30009{
    3 public static void main(String args[]){
    4 int repeat, ri;
    5 int a,b,c,d;
    6 double x1,x2;
    7 Scanner in=new Scanner(System.in);
    8 repeat=in.nextInt();
    9 for(ri = 1; ri <= repeat; ri++){
    10 a=in.nextInt();b=in.nextInt();c=in.nextInt();
    11 /*---------*/
    12 d=b*b-4*a*c;
    13 if(a==0&&b==0&&c==0){
    14 System.out.println("a=b=c=0,meaningless");
    15 }else if(a==0&&b==0&&c!=0){
    16 System.out.println("a=b=0,c!=0,error");
    17 }else if(a==0&&b!=0&&c!=0){
    18 System.out.println("x="+(double)Math.round((double)(-c)/b*100)/100);
    19 }else if(d>=0){
    20 System.out.println("x1="+(double)Math.round(((-b)+Math.sqrt(d))/(2*a)*100)/100);
    21 System.out.println("x2="+(double)Math.round(((-b)-Math.sqrt(d))/(2*a)*100)/100);
    22 }else if(d<0){
    23 System.out.println("x1="+(double)(-b)/(2*a)+"+"+(double)Math.round((Math.sqrt(-d)/(2*a))*100)/100+"i");
    24 System.out.println("x2="+(double)(-b)/(2*a)+"-"+(double)Math.round((Math.sqrt(-d)/(2*a))*100)/100+"i");
    25 }
    26 }
    27 }
    28 }
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  • 原文地址:https://www.cnblogs.com/clara/p/2412675.html
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