zoukankan      html  css  js  c++  java
  • UVA 111 (复习dp, 14.07.09)

     History Grading 

    Background

    Many problems in Computer Science involve maximizing some measure according to constraints.

    Consider a history exam in which students are asked to put several historical events into chronological order. Students who order all the events correctly will receive full credit, but how should partial credit be awarded to students who incorrectly rank one or more of the historical events?

    Some possibilities for partial credit include:

    1. 1 point for each event whose rank matches its correct rank
    2. 1 point for each event in the longest (not necessarily contiguous) sequence of events which are in the correct order relative to each other.

    For example, if four events are correctly ordered 1 2 3 4 then the order 1 3 2 4 would receive a score of 2 using the first method (events 1 and 4 are correctly ranked) and a score of 3 using the second method (event sequences 1 2 4 and 1 3 4 are both in the correct order relative to each other).

    In this problem you are asked to write a program to score such questions using the second method.

    The Problem

    Given the correct chronological order of n events tex2html_wrap_inline34 as tex2html_wrap_inline36 where tex2html_wrap_inline38 denotes the ranking of event i in the correct chronological order and a sequence of student responses tex2html_wrap_inline42 where tex2html_wrap_inline44 denotes the chronological rank given by the student to event i; determine the length of the longest (not necessarily contiguous) sequence of events in the student responses that are in the correct chronological order relative to each other.

    The Input

    The first line of the input will consist of one integer n indicating the number of events with tex2html_wrap_inline50 . The second line will contain nintegers, indicating the correct chronological order of n events. The remaining lines will each consist of n integers with each line representing a student's chronological ordering of the n events. All lines will contain n numbers in the range tex2html_wrap_inline60 , with each number appearing exactly once per line, and with each number separated from other numbers on the same line by one or more spaces.

    The Output

    For each student ranking of events your program should print the score for that ranking. There should be one line of output for each student ranking.

    Sample Input 1

    4
    4 2 3 1
    1 3 2 4
    3 2 1 4
    2 3 4 1

    Sample Output 1

    1
    2
    3

    Sample Input 2

    10
    3 1 2 4 9 5 10 6 8 7
    1 2 3 4 5 6 7 8 9 10
    4 7 2 3 10 6 9 1 5 8
    3 1 2 4 9 5 10 6 8 7
    2 10 1 3 8 4 9 5 7 6
    

    Sample Output 2

    6
    5
    10
    9

    求最长公共子序列

    AC代码

    #include<stdio.h>
    #include<string.h>
    
    int max(int a, int b) {
    	if(a > b)
    		return a;
    	else
    		return b;
    }
    
    int main() {
    	int l;
    	int t;
    	int num1[100];
    	
    	scanf("%d", &l);
    	for(int i = 1; i <= l; i++) {
    		scanf("%d", &t);
    		num1[t] = i;
    	}
    	
    	int num2[100];
    	while(scanf("%d", &t) != EOF) {
    		num2[t] = 1;
    		for(int i = 2; i <= l; i++) {
    			scanf("%d", &t);
    			num2[t] = i;
    		}
    
    		int dp[100][100];
    		memset(dp, 0, sizeof(dp));
    
    		for(int i = 1; i <= l; i++) {
    			for(int j = 1; j <= l; j++) {
    				if(num1[i] == num2[j])
    					dp[i][j] = dp[i-1][j-1] + 1;
    				else
    					dp[i][j] = max(dp[i-1][j], dp[i][j-1]);
    			}
    		}
    
    		printf("%d
    ", dp[l][l]);
    	}
    
    	return 0;
    }



  • 相关阅读:
    day 71
    day 70
    day 69 Django 视图层(views)and 模板层(templates)
    Python基础语法 第1节课(标识符、注释、缩进、输入输出、变量、数据类型)
    第019讲:函数 我的地盘听我的--函数变量的作用域(课后测试题及答案 )
    第018讲:函数 灵活即强大(课后测试题及答案 )
    第017讲:函数 python的乐高积木(课后测试题及答案 )
    第012课:列表:一个打了激素的数组3(课后习题及解答)
    第011讲:列表:一个打了激素的数组2 (课后习题及答案)
    第016讲:序列!序列! (课后测试题及答案 )
  • 原文地址:https://www.cnblogs.com/clnchanpin/p/6807617.html
Copyright © 2011-2022 走看看