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2018 ACM 网络选拔赛徐州赛区

A. Hard to prepare

  1 #include <cstdio>
  2 #include <cstdlib>
  3 #include <cmath>
  4 #include <cstring>
  5 #include <time.h>
  6 #include <string>
  7 #include <set>
  8 #include <map>
  9 #include <list>
 10 #include <stack>
 11 #include <queue>
 12 #include <vector>
 13 #include <bitset>
 14 #include <ext/rope>
 15 #include <algorithm>
 16 #include <iostream>
 17 using namespace std;
 18 #define ll long long
 19 #define minv 1e-6
 20 #define inf 1e9
 21 #define pi 3.1415926536
 22 #define nl 2.7182818284
 23 const ll mod=1e9+7;//998244353
 24 const int maxn=1e5+10;
 25 
 26 /**
 27 0: x1<>xn and x1<>~xn
 28 1: x1=xn
 29 2: x1=~xn
 30 **/
 31 
 32 ll a[3][3],b[3][3],c[3][3];
 33 
 34 ll mul(ll x,ll y)
 35 {
 36     ll r=1;
 37     while (y)
 38     {
 39         if (y & 1)
 40             r=r*x%mod;
 41         x=x*x%mod;
 42         y>>=1;
 43     }
 44     return r;
 45 }
 46 
 47 int main()
 48 {
 49     int t,n,i,j,k;
 50     ll z,v,vv,r;
 51 
 52 
 53     scanf("%d",&t);
 54     while (t--)
 55     {
 56         scanf("%d%lld",&n,&z);
 57         if (z==1)
 58         {
 59             printf("2
");
 60             continue;
 61         }
 62         v=mul(2,z);
 63         if (n==1)
 64         {
 65             printf("%lld
",v);
 66             continue;
 67         }
 68 
 69         for (i=0;i<3;i++)
 70             for (j=0;j<3;j++)
 71                 a[i][j]=0;
 72         a[1][0]=a[1][1]=a[2][0]=a[2][2]=1;
 73         a[0][0]=v-3;
 74         a[0][1]=v-2;
 75         a[0][2]=v-2;
 76 
 77         for (i=0;i<3;i++)
 78             for (j=0;j<3;j++)
 79                 b[i][j]=0;
 80         for (i=0;i<3;i++)
 81             b[i][i]=1;
 82 
 83         n-=2;
 84         while (n)
 85         {
 86             if (n & 1)
 87             {
 88                 for (i=0;i<3;i++)
 89                     for (j=0;j<3;j++)
 90                     {
 91                         c[i][j]=b[i][j];
 92                         b[i][j]=0;
 93                     }
 94                 for (i=0;i<3;i++)
 95                     for (j=0;j<3;j++)
 96                         for (k=0;k<3;k++)
 97                             b[i][j]=(b[i][j]+a[i][k]*c[k][j])%mod;
 98             }
 99             n>>=1;
100 
101             for (i=0;i<3;i++)
102                 for (j=0;j<3;j++)
103                 {
104                     c[i][j]=a[i][j];
105                     a[i][j]=0;
106                 }
107             for (i=0;i<3;i++)
108                 for (j=0;j<3;j++)
109                     for (k=0;k<3;k++)
110                         a[i][j]=(a[i][j]+c[i][k]*c[k][j])%mod;
111         }
112 
113         r=0;
114         vv=v*(v-2)%mod;
115         printf("%lld
",(
116                          vv*(b[0][0]+b[1][0])%mod
117                          +v*(b[0][1]+b[1][1])%mod
118                          +mod)%mod);
119     }
120     return 0;
121 }
122 /*
123 5 2
124 244
125 
126 1 3
127 8
128 
129 2 3
130 56
131 
132 3 3
133 344
134 
135 4 3
136 2408
137 
138 1 5
139 32
140 
141 2 5
142 992
143 
144 3 5
145 29792
146 */

testA

 1 #include <cstdio>
 2 #include <cstdlib>
 3 #include <cmath>
 4 #include <cstring>
 5 #include <time.h>
 6 #include <string>
 7 #include <set>
 8 #include <map>
 9 #include <list>
10 #include <stack>
11 #include <queue>
12 #include <vector>
13 #include <bitset>
14 #include <ext/rope>
15 #include <algorithm>
16 #include <iostream>
17 using namespace std;
18 #define ll long long
19 #define minv 1e-6
20 #define inf 1e9
21 #define pi 3.1415926536
22 #define nl 2.7182818284
23 const ll mod=1e9+7;//998244353
24 const int maxn=1e5+10;
25 
26 int n=2;
27 int k=31;///2^z-1
28 int a[maxn];
29 int tot=0;
30 
31 void dfs(int index)
32 {
33     int i;
34     if (index==n+1)
35     {
36         if (a[n]+a[1]!=k)
37         {
38 //            for (i=1;i<=n;i++)
39 //                printf("%d ",a[i]);
40 //            printf("
");
41             tot++;
42         }
43         return;
44     }
45     for (i=0;i<=k;i++)
46         if (i+a[index-1]!=k)
47         {
48             a[index]=i;
49             dfs(index+1);
50         }
51 }
52 
53 int main()
54 {
55     a[0]=-10000;
56     dfs(1);
57     printf("%d",tot);
58     return 0;
59 }
60 /*
61 5 2
62 244
63 
64 1 3
65 8
66 
67 2 3
68 56
69 
70 3 3
71 344
72 
73 4 3
74 2408
75 
76 1 5
77 32
78 
79 2 5
80 992
81 
82 3 5
83 29792
84 */

B. BE, GE or NE

  1 #include <cstdio>
  2 #include <cstdlib>
  3 #include <cmath>
  4 #include <cstring>
  5 #include <time.h>
  6 #include <string>
  7 #include <set>
  8 #include <map>
  9 #include <list>
 10 #include <stack>
 11 #include <queue>
 12 #include <vector>
 13 #include <bitset>
 14 #include <ext/rope>
 15 #include <algorithm>
 16 #include <iostream>
 17 using namespace std;
 18 #define ll long long
 19 #define minv 1e-6
 20 #define inf 1e9
 21 #define pi 3.1415926536
 22 #define nl 2.7182818284
 23 const ll mod=1e9+7;//998244353
 24 const int maxn=1e3+10;
 25 const int maxm=2e2+10;
 26 
 27 int f[maxn][maxm],dif=100,n,l,r;
 28 int a[maxn],b[maxn],c[maxn],last[maxm];
 29 
 30 void dfs(int i,int x)
 31 {
 32     int y;
 33 
 34     if (a[i]!=0)
 35     {
 36         y=min(x+a[i],100);
 37         if (i==n)
 38             f[i+1][y+dif]=last[y+dif];
 39         else if (f[i+1][y+dif]==-2 || f[i+1][y+dif]==2)
 40                 dfs(i+1,y);
 41         if (i & 1)
 42             f[i][x+dif]=max(f[i][x+dif],f[i+1][y+dif]);
 43         else
 44             f[i][x+dif]=min(f[i][x+dif],f[i+1][y+dif]);
 45     }
 46     if (b[i]!=0)
 47     {
 48         y=max(x-b[i],-100);
 49         if (i==n)
 50             f[i+1][y+dif]=last[y+dif];
 51         else if (f[i+1][y+dif]==-2 || f[i+1][y+dif]==2)
 52                 dfs(i+1,y);
 53         if (i & 1)
 54             f[i][x+dif]=max(f[i][x+dif],f[i+1][y+dif]);
 55         else
 56             f[i][x+dif]=min(f[i][x+dif],f[i+1][y+dif]);
 57     }
 58     if (c[i]!=0)
 59     {
 60         y=-x;
 61         if (i==n)
 62             f[i+1][y+dif]=last[y+dif];
 63         else if (f[i+1][y+dif]==-2 || f[i+1][y+dif]==2)
 64                 dfs(i+1,y);
 65         if (i & 1)
 66             f[i][x+dif]=max(f[i][x+dif],f[i+1][y+dif]);
 67         else
 68             f[i][x+dif]=min(f[i][x+dif],f[i+1][y+dif]);
 69     }
 70 }
 71 
 72 int main()
 73 {
 74     int m,i,j;
 75     scanf("%d%d%d%d",&n,&m,&r,&l);
 76     for (i=1;i<=n;i++)
 77         scanf("%d%d%d",&a[i],&b[i],&c[i]);
 78     ///Koutarou first max
 79     for (i=1;i<=n;i++)
 80         for (j=0;j<=200;j++)
 81             if (i & 1)  ///max
 82                 f[i][j]=-2;
 83             else
 84                 f[i][j]=2;
 85 
 86     for (i=0;i<=l+100;i++)
 87         last[i]=-1;
 88     for (i=r+100;i<=200;i++)
 89         last[i]=1;
 90 
 91     dfs(1,m);
 92 
 93     if (f[1][m+dif]==1)
 94         printf("Good Ending");
 95     else if (f[1][m+dif]==-1)
 96         printf("Bad Ending");
 97     else
 98         printf("Normal Ending");
 99     return 0;
100 }

C. Cacti Lottery

  1 #include <cstdio>
  2 #include <cstdlib>
  3 #include <cmath>
  4 #include <cstring>
  5 #include <time.h>
  6 #include <string>
  7 #include <set>
  8 #include <map>
  9 #include <list>
 10 #include <stack>
 11 #include <queue>
 12 #include <vector>
 13 #include <bitset>
 14 #include <ext/rope>
 15 #include <algorithm>
 16 #include <iostream>
 17 using namespace std;
 18 #define ll long long
 19 #define minv 1e-6
 20 #define inf 1e9
 21 #define pi 3.1415926536
 22 #define nl 2.7182818284
 23 const ll mod=1e9+7;//998244353
 24 const int maxn=1e6+10;
 25 
 26 int n=9,z[10];
 27 struct node
 28 {
 29     int a[10],price;
 30     int each[8];
 31 }f[maxn],cur;
 32 bool vis[10];
 33 char s[20];
 34 int award[30];
 35 int number=362880;
 36 int tot_know,tot_num,pos[maxn],each[8];
 37 int x,xx;
 38 ll y;
 39 double yy=0;
 40 
 41 void DFS(int j)
 42 {
 43     int i;
 44     if (j==n+1)
 45     {
 46         int value=0,k;
 47         memset(vis,0,sizeof(vis));
 48         for (i=1;i<=n;i++)
 49         {
 50             k=0;
 51             for (j=1;j<cur.a[i];j++)
 52                 if (!vis[j])
 53                     k++;
 54             value+=k*z[n-i];
 55             vis[cur.a[i]]=1;
 56         }
 57         f[value]=cur;
 58         f[value].each[0]=award[ cur.a[1]+cur.a[4]+cur.a[7] ];
 59         f[value].each[1]=award[ cur.a[2]+cur.a[5]+cur.a[8] ];
 60         f[value].each[2]=award[ cur.a[3]+cur.a[6]+cur.a[9] ];
 61         f[value].each[3]=award[ cur.a[1]+cur.a[2]+cur.a[3] ];
 62         f[value].each[4]=award[ cur.a[4]+cur.a[5]+cur.a[6] ];
 63         f[value].each[5]=award[ cur.a[7]+cur.a[8]+cur.a[9] ];
 64         f[value].each[6]=award[ cur.a[1]+cur.a[5]+cur.a[9] ];
 65         f[value].each[7]=award[ cur.a[3]+cur.a[5]+cur.a[7] ];
 66 
 67         f[value].price=
 68             max(
 69             max(max(f[value].each[0],f[value].each[1]),
 70             max(f[value].each[2],f[value].each[3])),
 71             max(max(f[value].each[4],f[value].each[5]),
 72             max(f[value].each[6],f[value].each[7])) );
 73         return ;
 74     }
 75 
 76     for (i=j;i<=n;i++)
 77     {
 78         swap(cur.a[j],cur.a[i]);
 79         DFS(j+1);
 80         swap(cur.a[j],cur.a[i]);
 81     }
 82 }
 83 
 84 void init()
 85 {
 86 award[6]=    10000;
 87 award[7]=    36;
 88 award[8]=    720;
 89 award[9]=    360;
 90 award[10]=    80;
 91 award[11]=    252;
 92 award[12]=    108;
 93 award[13]=    72;
 94 award[14]=    54;
 95 award[15]=    180;
 96 award[16]=    72;
 97 award[17]=    180;
 98 award[18]=    119;
 99 award[19]=    36;
100 award[20]=    360;
101 award[21]=    1080;
102 award[22]=    144;
103 award[23]=    1800;
104 award[24]=    3600;
105 cur.price=0;
106 }
107 
108 /**
109 * :konw
110 # :don't konw
111 **/
112 
113 void dfs2(int j)
114 {
115     int i;
116     if (j==tot_num+1)
117     {
118         int value=0,k;
119         memset(vis,0,sizeof(vis));
120         for (i=1;i<=n;i++)
121         {
122             k=0;
123             for (j=1;j<cur.a[i];j++)
124                 if (!vis[j])
125                     k++;
126             value+=k*z[n-i];
127             vis[cur.a[i]]=1;
128         }
129 
130         for (i=0;i<8;i++)
131             each[i]+=f[value].each[i];
132         x++;
133         return ;
134     }
135 
136     for (i=j;i<=tot_num;i++)
137     {
138         swap(cur.a[pos[j]],cur.a[pos[i]]);
139         dfs2(j+1);
140         swap(cur.a[pos[j]],cur.a[pos[i]]);
141     }
142 }
143 
144 void dfs1(int j)
145 {
146     int i;
147     if (j==tot_know+1)
148     {
149         memset(each,0,sizeof(each));
150         x=0;
151         dfs2(j);
152             y=
153         max(
154         max(max(each[0],each[1]),
155         max(each[2],each[3])),
156         max(max(each[4],each[5]),
157         max(each[6],each[7])) );
158 
159         xx++;
160         yy+=1.0*y/x;
161         ///add have 10000 ... exit directly
162         return ;
163     }
164 
165     for (i=j;i<=tot_num;i++)
166     {
167         swap(cur.a[pos[j]],cur.a[pos[i]]);
168         dfs1(j+1);
169         swap(cur.a[pos[j]],cur.a[pos[i]]);
170     }
171 }
172 
173 int main()
174 {
175     int t,i,j;
176 
177     init();
178     z[1]=1;
179     for (i=2;i<=9;i++)
180         z[i]=z[i-1]*i;
181 
182     for (i=1;i<=9;i++)
183         cur.a[i]=i;
184 
185     DFS(1);
186 
187     scanf("%d",&t);
188     while (t--)
189     {
190         scanf("%s",s+1);
191         scanf("%s",s+4);
192         scanf("%s",s+7);
193 
194         memset(vis,0,sizeof(vis));
195         x=0,y=0;
196         tot_know=0;
197         for (i=1;i<=9;i++)
198             if (s[i]>='1' && s[i]<='9')
199             {
200                 cur.a[i]=s[i]-48;
201                 vis[cur.a[i]]=1;
202             }
203             else if (s[i]=='*')
204             {
205                 tot_know++;
206                 pos[tot_know]=i;
207             }
208 
209         tot_num=tot_know;
210         for (i=1;i<=9;i++)
211             if (s[i]=='#')
212             {
213                 tot_num++;
214                 pos[tot_num]=i;
215             }
216 
217         for (i=1;i<=9;i++)
218             if (s[i]=='#' || s[i]=='*')
219             {
220                 for (j=1;j<=9;j++)
221                     if (!vis[j])
222                         break;
223                 cur.a[i]=j;
224                 vis[j]=1;
225             }
226 
227         xx=0;
228         yy=0;
229         dfs1(1);
230 
231         printf("%.10f
",1.0*yy/xx);
232     }
233     return 0;
234 }
235 /*
236 2
237 ***
238 ***
239 ***
240 
241 ##*
242 #*#
243 *##
244 */

F. Features Track

  1 #include <cstdio>
  2 #include <cstdlib>
  3 #include <cmath>
  4 #include <cstring>
  5 #include <time.h>
  6 #include <string>
  7 #include <set>
  8 #include <map>
  9 #include <list>
 10 #include <stack>
 11 #include <queue>
 12 #include <vector>
 13 #include <bitset>
 14 #include <ext/rope>
 15 #include <algorithm>
 16 #include <iostream>
 17 using namespace std;
 18 #define ll long long
 19 #define minv 1e-6
 20 #define inf 1e9
 21 #define pi 3.1415926536
 22 #define nl 2.7182818284
 23 const ll mod=1e9+7;//998244353
 24 const int maxn=1e5+10;
 25 
 26 struct node
 27 {
 28     int x,y,z;
 29 }f[maxn];
 30 
 31 int cmp(node a,node b)
 32 {
 33     if (a.x<b.x)
 34         return 1;
 35     else if (a.x>b.x)
 36         return 0;
 37     if (a.y<b.y)
 38         return 1;
 39     else if (a.y>b.y)
 40         return 0;
 41     if (a.z<b.z)
 42         return 1;
 43     else
 44         return 0;
 45 }
 46 
 47 int main()
 48 {
 49     int t,n,m,i,j,k,r;
 50     scanf("%d",&t);
 51     while (t--)
 52     {
 53         scanf("%d",&n);
 54         j=0;
 55         for (i=1;i<=n;i++)
 56         {
 57             scanf("%d",&m);
 58             while (m--)
 59             {
 60                 j++;
 61                 scanf("%d%d",&f[j].x,&f[j].y);
 62                 f[j].z=i;
 63             }
 64         }
 65         sort(f+1,f+j+1,cmp);
 66 
 67         r=0;
 68         f[j+1].x=f[j].x-1;
 69         k=1;
 70         for (i=1;i<=j;i++)
 71         {
 72             if (f[i].x==f[i+1].x && f[i].y==f[i+1].y)
 73             {
 74                 if (f[i].z==f[i+1].z)
 75                     continue;
 76                 else if (f[i].z==f[i+1].z-1)
 77                 {
 78                     k++;
 79                     continue;
 80                 }
 81             }
 82             r=max(r,k);
 83             k=1;
 84         }
 85         printf("%d
",r);
 86     }
 87     return 0;
 88 }
 89 /*
 90 3
 91 
 92 8
 93 2 1 1 2 2
 94 2 1 1 1 4
 95 2 1 1 2 2
 96 2 2 2 1 4
 97 0
 98 0
 99 1 1 1
100 1 1 1
101 
102 5
103 1 1 1
104 2 2 2 1 1
105 3 1 1 1 1 1 1
106 1 2 3
107 1 1 1
108 
109 5
110 1 1 1
111 2 2 2 1 3
112 3 1 1 1 1 1 1
113 1 2 3
114 1 1 1
115 */

G. Trace

  1 #include <cstdio>
  2 #include <cstdlib>
  3 #include <cmath>
  4 #include <cstring>
  5 #include <time.h>
  6 #include <string>
  7 #include <set>
  8 #include <map>
  9 #include <list>
 10 #include <stack>
 11 #include <queue>
 12 #include <vector>
 13 #include <bitset>
 14 #include <ext/rope>
 15 #include <algorithm>
 16 #include <iostream>
 17 using namespace std;
 18 #define ll long long
 19 #define minv 1e-6
 20 #define inf 1e9
 21 #define pi 3.1415926536
 22 #define nl 2.7182818284
 23 const ll mod=1e9+7;//998244353
 24 const int maxn=5e4+10;
 25 
 26 struct node
 27 {
 28     int v,num;
 29 }x[maxn],y[maxn];
 30 
 31 struct rec
 32 {
 33     int x,y;
 34 }ff[maxn],f[maxn];
 35 
 36 int vx[maxn],vy[maxn],s[maxn];
 37 
 38 int cmp1(node a,node b)
 39 {
 40     return a.v>b.v;
 41 }
 42 
 43 int main()
 44 {
 45     int n,i,j,value;
 46     ll sum=0;
 47 
 48     scanf("%d",&n);
 49 //    for (i=1;i<=n;i++)
 50     for (i=n;i>=1;i--)
 51         scanf("%d%d",&ff[i].x,&ff[i].y);
 52     ff[0]={-1,-1};
 53 
 54 
 55     memset(s,0,sizeof(s));
 56     for (i=1;i<=n;i++)
 57     {
 58         x[i].num=i;
 59         x[i].v=ff[i].x;
 60     }
 61     sort(x+1,x+n+1,cmp1);
 62     j=0;
 63     for (i=1;i<=n;i++)
 64     {
 65         if (ff[i].x!=ff[i-1].x)
 66         {
 67             j++;
 68             vx[j]=ff[i].x;
 69         }
 70         f[x[i].num].x=j;
 71         f[x[i].num].y=ff[x[i].num].y;
 72     }
 73     for (i=1;i<=n;i++)
 74     {
 75         value=0;
 76         j=f[i].x-1;
 77         while (j>0)
 78         {
 79             value=max(value,s[j]);
 80             j-=(j & (-j));
 81         }
 82 
 83         sum+=f[i].y-value;
 84 
 85         j=f[i].x;
 86         while (j<=n)
 87         {
 88             s[j]=max(s[j],f[i].y);
 89             j+=(j & (-j));
 90         }
 91     }
 92 
 93 
 94     ///==========///
 95     ///y lisan
 96     memset(s,0,sizeof(s));
 97     for (i=1;i<=n;i++)
 98     {
 99         y[i].num=i;
100         y[i].v=ff[i].y;
101     }
102     sort(y+1,y+n+1,cmp1);
103     j=0;
104     for (i=1;i<=n;i++)
105     {
106         if (ff[i].y!=ff[i-1].y)
107         {
108             j++;
109             vy[j]=ff[i].y;
110         }
111         f[y[i].num].y=j;
112         f[y[i].num].x=ff[y[i].num].x;
113     }
114     for (i=1;i<=n;i++)
115     {
116         value=0;
117         j=f[i].y-1;
118         while (j>0)
119         {
120             value=max(value,s[j]);
121             j-=(j & (-j));
122         }
123 
124         sum+=f[i].x-value;
125 
126         j=f[i].y;
127         while (j<=n)
128         {
129             s[j]=max(s[j],f[i].x);
130             j+=(j & (-j));
131         }
132     }
133 
134     printf("%lld",sum);
135 
136     return 0;
137 }
138 /*
139 3
140 1 4
141 3 3
142 4 1
143 
144 2
145 1 4
146 4 1
147 */

H. Ryuji doesn't want to study

 1 #include <cstdio>
 2 #include <cstdlib>
 3 #include <cmath>
 4 #include <cstring>
 5 #include <time.h>
 6 #include <string>
 7 #include <set>
 8 #include <map>
 9 #include <list>
10 #include <stack>
11 #include <queue>
12 #include <vector>
13 #include <bitset>
14 #include <ext/rope>
15 #include <algorithm>
16 #include <iostream>
17 using namespace std;
18 #define ll long long
19 #define minv 1e-6
20 #define inf 1e9
21 #define pi 3.1415926536
22 #define nl 2.7182818284
23 const ll mod=1e9+7;//998244353
24 const int maxn=1e5+10;
25 
26 ll x[maxn],y[maxn],s[maxn];
27 
28 int main()
29 {
30     int n,q,i,j,a,b,c;
31     ll sum;
32     scanf("%d%d",&n,&q);
33     for (i=1;i<=n;i++)
34     {
35         scanf("%d",&s[i]);
36         j=i;
37         while (j<=n)
38         {
39             x[j]+=s[i];
40             y[j]+=1ll*s[i]*(n-i);
41             j+=(j & (-j));
42         }
43     }
44 
45     while (q--)
46     {
47         scanf("%d%d%d",&a,&b,&c);
48         if (a==1)
49         {
50             sum=0;
51             j=c;
52             while (j>0)
53             {
54                 sum+=y[j]-x[j]*(n-c-1);
55                 j-=(j & (-j));
56             }
57             j=b-1;
58             while (j>0)
59             {
60                 sum-=y[j]-x[j]*(n-c-1);
61                 j-=(j & (-j));
62             }
63             printf("%lld
",sum);
64         }
65         else
66         {
67             j=b;
68             while (j<=n)
69             {
70                 x[j]-=s[b];
71                 y[j]-=s[b]*(n-b);
72                 j+=(j & (-j));
73             }
74 
75             j=b;
76             while (j<=n)
77             {
78                 x[j]+=c;
79                 y[j]+=1ll*c*(n-b);
80                 j+=(j & (-j));
81             }
82             s[b]=c;
83         }
84     }
85     return 0;
86 }
87 /*
88 5 5
89 1 2 3 4 5
90 1 2 5
91 2 3 -1
92 1 2 5
93 */

I. Characters with Hash

 1 #include <cstdio>
 2 #include <cstdlib>
 3 #include <cmath>
 4 #include <cstring>
 5 #include <time.h>
 6 #include <string>
 7 #include <set>
 8 #include <map>
 9 #include <list>
10 #include <stack>
11 #include <queue>
12 #include <vector>
13 #include <bitset>
14 #include <ext/rope>
15 #include <algorithm>
16 #include <iostream>
17 using namespace std;
18 #define ll long long
19 #define minv 1e-6
20 #define inf 1e9
21 #define pi 3.1415926536
22 #define nl 2.7182818284
23 const ll mod=1e9+7;//998244353
24 const int maxn=1e6+10;
25 
26 char str[maxn];
27 
28 int main()
29 {
30 //    printf("%d
",'z'-'o');
31 //    printf("%d
",'z'-'M');
32 //    printf("%d
",'z'-'l');
33     int t,len,v,i;
34     char c;
35     scanf("%d",&t);
36     while (t--)
37     {
38         scanf("%d %c",&len,&c);
39         scanf("%s",str);
40 
41         for (i=0;i<len;i++)
42             if (str[i]!=c)
43                 break;
44         if (i!=len && abs(c-str[i])<10)
45             v=1;
46         else
47             v=0;
48         printf("%d
",max(len*2-i*2-v,1));
49     }
50     return 0;
51 }

J. Maze Designer

  1 /*
  2 打通n*m-1个相邻的格子。
  3 树：格子相当于一个点，相邻直接连通的格子有一条边
  4 删去树的边，使用剩下的边，
  5 所以使用最大生成树
  6 */
  7 #include <cstdio>
  8 #include <cstdlib>
  9 #include <cmath>
 10 #include <cstring>
 11 #include <time.h>
 12 #include <string>
 13 #include <set>
 14 #include <map>
 15 #include <list>
 16 #include <stack>
 17 #include <queue>
 18 #include <vector>
 19 #include <bitset>
 20 #include <ext/rope>
 21 #include <algorithm>
 22 #include <iostream>
 23 using namespace std;
 24 #define ll long long
 25 #define minv 1e-6
 26 #define inf 1e9
 27 #define pi 3.1415926536
 28 #define nl 2.7182818284
 29 const ll mod=1e9+7;//998244353
 30 const int maxn=5e2+10;
 31 const int maxt=maxn*maxn;
 32 const int maxq=1e5+10;
 33 
 34 struct rec
 35 {
 36     int x,y,z;
 37 }e[maxt*4];
 38 
 39 struct node
 40 {
 41     int d,num;
 42     node *next;
 43 }*ask[maxt];
 44 
 45 int z[maxt][5],fa[maxt],dist[maxt],rd[maxq];
 46 bool vis[maxt];
 47 
 48 int getfather(int d)
 49 {
 50     if (fa[d]==d)
 51         return d;
 52     fa[d]=getfather(fa[d]);
 53     return fa[d];
 54 }
 55 
 56 void merge(int x,int y)
 57 {
 58     x=getfather(x);
 59     y=getfather(y);
 60     fa[y]=x;
 61 }
 62 
 63 void dfs(int d)
 64 {
 65     int i,dd;
 66     node *r=ask[d];
 67     vis[d]=1;
 68     for (i=1;i<=z[d][0];i++)
 69     {
 70         dd=z[d][i];
 71         if (!vis[dd])
 72         {
 73             dist[dd]=dist[d]+1;
 74             dfs(dd);
 75             merge(d,dd);
 76         }
 77     }
 78     while (r)
 79     {
 80         dd=r->d;
 81         if (vis[dd])
 82             rd[r->num]=dist[d]+dist[dd]-2*dist[getfather(dd)];
 83         r=r->next;
 84     }
 85 }
 86 
 87 int cmp(rec a,rec b)
 88 {
 89     return a.z>b.z;
 90 }
 91 
 92 int main()
 93 {
 94     int n,m,q,Q,x,y,g=0,num,i,j,a,b,c,d,d1,d2;
 95     char c1,c2;
 96     node *p;
 97     scanf("%d%d
",&n,&m);
 98 
 99     g=0;
100     num=0;
101     for (i=0;i<n;i++)
102         for (j=0;j<m;j++)
103         {
104             scanf("%c %d %c %d
",&c1,&d1,&c2,&d2);
105             if (c1=='D')
106             {
107                 e[++g].x=num;
108                 e[g].y=num+m;
109                 e[g].z=d1;
110             }
111 
112             if (c2=='R')
113             {
114                 e[++g].x=num;
115                 e[g].y=num+1;
116                 e[g].z=d2;
117             }
118 
119             num++;
120         }
121     sort(e+1,e+g+1,cmp);
122 
123     for (i=0;i<n*m;i++)
124         fa[i]=i;
125     j=n*m-1;
126     for (i=1;j;i++)
127     {
128         while (1)
129         {
130             x=getfather(e[i].x);
131             y=getfather(e[i].y);
132             if (x!=y)
133                 break;
134             i++;
135         }
136 
137         fa[x]=y;
138         j--;
139 
140         z[e[i].x][0]++;
141         z[e[i].x][z[e[i].x][0]]=e[i].y;
142 
143 
144         z[e[i].y][0]++;
145         z[e[i].y][z[e[i].y][0]]=e[i].x;
146     }
147 
148     scanf("%d",&q);
149     for (Q=1;Q<=q;Q++)
150     {
151         scanf("%d%d%d%d",&a,&b,&c,&d);
152         a--,b--,c--,d--;
153 
154         a=a*m+b;
155         c=c*m+d;
156 
157         p=new node();
158         p->d=c;
159         p->num=Q;
160         p->next=ask[a];
161         ask[a]=p;
162 
163         p=new node();
164         p->d=a;
165         p->num=Q;
166         p->next=ask[c];
167         ask[c]=p;
168     }
169 
170     for (i=0;i<n*m;i++)
171         fa[i]=i;
172     dfs(0);
173 
174     for (i=1;i<=q;i++)
175         printf("%d
",rd[i]);
176     return 0;
177 }

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原文地址：https://www.cnblogs.com/cmyg/p/9668314.html

2018 ACM 网络选拔赛 徐州赛区

2018 ACM 网络选拔赛徐州赛区