超强的验证时间的函数，可以验证是否为闰年

正则表达式在C#中的应用函数  
超强的验证时间的函数，可以验证是否为闰年
 public bool myTime(string str)
                {
                       bool flag=false;
                        string regex = @"^((\d{2}(([02468][048])|([13579][26]))[\-\/\s]?((((0?[13578]
                                        )|(1[02]))[\-\/\s]?((0?[1-9])|([1-2][0-9])|(3[01])))|(((0?[4
                                        69])|(11))[\-\/\s]?((0?[1-9])|([1-2][0-9])|(30)))|(0?2[\-\/\
                                        s]?((0?[1-9])|([1-2][0-9])))))|(\d{2}(([02468][1235679])|([1
                                        3579][01345789]))[\-\/\s]?((((0?[13578])|(1[02]))[\-\/\s]?((
                                        0?[1-9])|([1-2][0-9])|(3[01])))|(((0?[469])|(11))[\-\/\s]?((
                                        0?[1-9])|([1-2][0-9])|(30)))|(0?2[\-\/\s]?((0?[1-9])|(1[0-9]
                                        )|(2[0-8]))))))"; //日期部分
                                        regex += @"(\s(((0?[0-9])|([1-2][0-3]))\:([0-5]?[0-9])((\s)|(\:([0-5]?[0-9])))))?$"; //时间部分
                        RegexOptions options = ((RegexOptions.IgnorePatternWhitespace | RegexOptions.Multiline) | RegexOptions.IgnoreCase);
                        Regex reg = new Regex(regex, options);
                        if(reg.IsMatch(str))
                        {
                                flag=true;
                        }
                        return flag;
                }