zoukankan      html  css  js  c++  java
  • poj 2236 并查集

    题意:一张图上分布着n台坏了的电脑,并知道它们的坐标。两台修好的电脑如果距离<=d就可以联网,也可以通过其他修好的电脑间接相连。给出操作“O x”表示修好x,给出操作“S x y”,请你判断x和y在此时有没有连接上。

    链接:点我

    水并查集,注意节点从1开始

     1 #include<cstdio>
     2 #include<iostream>
     3 #include<algorithm>
     4 #include<cstring>
     5 #include<cmath>
     6 #include<queue>
     7 #include<map>
     8 using namespace std;
     9 #define MOD 1000000007
    10 const int INF=0x3f3f3f3f;
    11 const double eps=1e-5;
    12 #define cl(a) memset(a,0,sizeof(a))
    13 #define ts printf("*****
    ");
    14 const int MAXN=1005;
    15 int n,m,tt;
    16 int f[MAXN];
    17 bool g[MAXN][MAXN];
    18 struct node
    19 {
    20     double x,y;
    21     void in()
    22     {
    23         scanf("%lf%lf",&x,&y);
    24     }
    25 }nn[MAXN];
    26 double dis(node a,node b)
    27 {
    28     return sqrt((a.x-b.x)*(a.x-b.x)+(a.y-b.y)*(a.y-b.y));
    29 }
    30 int find(int x)
    31 {
    32     if(f[x]==-1)return x;
    33     return f[x]=find(f[x]);
    34 }
    35 void bing(int u,int v)
    36 {
    37     int t1=find(u),t2=find(v);
    38     if(t1!=t2)f[t1]=t2;
    39 }
    40 bool vis[MAXN];
    41 int main()
    42 {
    43     int i,j,k;
    44     #ifndef ONLINE_JUDGE
    45     freopen("1.in","r",stdin);
    46     #endif
    47     memset(g,false,sizeof(g));
    48     memset(vis,false,sizeof(vis));
    49     memset(f,-1,sizeof(f));
    50     int d,u,v;
    51     scanf("%d%d",&n,&d);
    52     for(i=1;i<=n;i++)
    53         nn[i].in();
    54     for(i=1;i<=n;i++)
    55     {
    56         for(j=1;j<=n;j++)
    57         {
    58             if(dis(nn[i],nn[j])<=d+eps)
    59             {
    60                 g[i][j]=1;
    61             }
    62         }
    63     }
    64     char s[8];
    65     while(scanf("%s",&s)==1)
    66     {
    67         if(s[0]=='O')
    68         {
    69             scanf("%d",&u);
    70             if(!vis[u])
    71             {
    72                 for(int i=1;i<=n;i++)
    73                   if(vis[i]&&g[u][i])
    74                     bing(u,i);
    75                 vis[u]=true;
    76             }
    77         }
    78         else
    79         {
    80             scanf("%d%d",&u,&v);
    81             if(find(u)==find(v))printf("SUCCESS
    ");
    82             else printf("FAIL
    ");
    83         }
    84     }
    85 }
  • 相关阅读:
    51Nod1119
    stoi
    坑爹大质数
    USACO07OPEN Cheapest Palindrome
    USACO08NOV Mixed Up Cows
    USACO12FEB Nearby Cows
    SCOI2009 粉刷匠
    USACO16OPEN 248
    POI2014 PTA-Little Bird
    USACO17FEB Why Did the Cow Cross the Road I G
  • 原文地址:https://www.cnblogs.com/cnblogs321114287/p/4481126.html
Copyright © 2011-2022 走看看