Key Set
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 131072/131072 K (Java/Others)
Total Submission(s): 1763 Accepted Submission(s): 928
Problem Description
soda has a set S
with n
integers {1,2,…,n} .
A set is called key set if the sum of integers in the set is an even number. He wants to know how many nonempty subsets of
S
are key set.
Input
There are multiple test cases. The first line of input contains an integer
T
(1≤T≤105) ,
indicating the number of test cases. For each test case:
The first line contains an integern
(1≤n≤109) ,
the number of integers in the set.
The first line contains an integer
Output
For each test case, output the number of key sets modulo 1000000007.
Sample Input
4 1 2 3 4
Sample Output
0 1 3 7
对于一个有n的元素的集合,组成的非空子集有2^n - 1个,其中和为奇数的个数比和为偶数的个数多一个。注意利用快速幂函数,不要超过了long long。
#include <stdio.h> __int64 pow(__int64 x, __int64 y) { __int64 res = 1; __int64 base = x; y -= 1; while (y) { if (y&1) res = base*res%1000000007; base = base*base%1000000007; y >>= 1; } return res; } int main() { int t; __int64 n; scanf("%d", &t); while (t--) { scanf("%I64d", &n); printf("%I64d ", pow(2, n) - 1); } return 0; }