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  • 张量积

    张量积:

    [A otimes B = {left[ {egin{array}{*{20}{c}}
    {{a_{11}}B}&{...}&{{a_{1n}}B}\
    {...}&{...}&{...}\
    {{a_{m1}}B}&{...}&{{a_{mm}}B}
    end{array}} ight]_{m imes p,n imes q}}]

    张量积性质:

    (1)右进法则:

    [left[ {egin{array}{*{20}{c}}
    A&B\
    C&D
    end{array}} ight] otimes E = left[ {egin{array}{*{20}{c}}
    {A otimes E}&{B otimes E}\
    {C otimes E}&{D otimes E}
    end{array}} ight]]

    (2)左进法则不成立

    (3)吸收公式:$({A_1} otimes {B_1})({A_2} otimes {B_2}) = ({A_1}{A_2} otimes {B_1}{B_2})$

    (4)${(A otimes B)^H} = {A^H} otimes {B^H}$

    (5)${(A otimes B)^ + } = {A^ + } otimes {B^ + }$

    (6)${(A otimes B)^ {-1} } = {A^ {-1} } otimes {B^ {-1} }$

    (7)$A=A_{m imes m}, B=B_{n imes n}$,$tr(A otimes B) = tr(A)tr(B)$

    (8)$A=A_{m imes m}, B=B_{n imes n}$,$det (A otimes B) = det {(A)^n}det {(B)^m}$

    张量积的用法:

    (1)求广义逆:

    (i)

    [{left[ {egin{array}{*{20}{c}}
    A&0
    end{array}} ight]^ + } = {(left[ {egin{array}{*{20}{c}}
    1&0
    end{array}} ight] otimes A)^ + } = {left[ {egin{array}{*{20}{c}}
    1&0
    end{array}} ight]^ + } otimes {A^ + } = left[ {egin{array}{*{20}{c}}
    1\
    0
    end{array}} ight] otimes {A^ + } = left[ {egin{array}{*{20}{c}}
    {{A^ + }}\
    0
    end{array}} ight]]

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  • 原文地址:https://www.cnblogs.com/codeDog123/p/10238625.html
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