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  • 大数相乘(hdu 1402)

    ------------------题目链接---------------------

    题目没啥说的,两个数相乘,fft,一发模板就AC,kuangbin模板大法好,不懂原理的小白也能体验AC。

    个人学的比较菜,不懂原理,把学习资料整合一下。存一下模板。


    大佬的讲解 另一个讲解

    #include <cstdio>
    #include <cstring>
    #include <cctype>
    #include <cmath>
    #include <set>
    #include <map>
    #include <list>
    #include <queue>
    #include <deque>
    #include <stack>
    #include <string>
    #include <vector>
    #include <iostream>
    #include <algorithm>
    #include <stdlib.h>
    #include <time.h>
    #include <complex>
    using namespace std;
    typedef long long LL;
    const int INF=2e9+1e8;
    
    const int MOD=1e9+7;
    const double eps=0.0000000001;
    void fre()
    {
        freopen("test.in","r",stdin);
        freopen("test.out","w",stdout);
    }
    #define MSET(a,b) memset(a,b,sizeof(a))
    
    
    const double PI=acos(-1.0);
    typedef complex<double> Complex;
    void change(Complex y[],int len)
    {
        int i,j,k;
        for(i=1,j=len/2; i<len-1; i++)
        {
            if(i<j)
                swap(y[i],y[j]);
            k=len/2;
            while(j>=k)
            {
                j-=k;
                k/=2;
            }
            if(j<k) j+=k;
        }
    }
    void fft(Complex y[],int len,int on)
    {
        change(y,len);
        for(int h=2; h<=len; h<<=1)
        {
            Complex wn(cos(-on * 2 * PI / h), sin(-on * 2 * PI / h));
            for(int j=0; j<len; j+=h)
            {
                Complex w(1,0);
                for(int k=j; k<j+h/2; k++)
                {
                    Complex u=y[k];
                    Complex t=w*y[k+h/2];
                    y[k]=u+t;
                    y[k+h/2]=u-t;
                    w=w*wn;
                }
            }
        }
        if(on==-1)
        {
            for(int i=0; i<len; i++)
                y[i].real(y[i].real()/len);
        }
    }
    /******************************************************/
    
    const int MAXN = 200010;
    Complex x1[MAXN], x2[MAXN];
    char str1[MAXN / 2], str2[MAXN / 2];
    int sum[MAXN];
    int main()
    {
        while (scanf("%s%s", str1, str2) == 2)
        {
            int len1 = strlen(str1);
            int len2 = strlen(str2);
            int len = 1;
            while (len < len1 * 2 || len < len2 * 2) //2^n<
                len <<= 1;
            for (int i = 0; i < len1; i++)
                x1[i] = Complex(str1[len1 - 1 - i] - '0', 0);
            for (int i = len1; i < len; i++)
                x1[i] = Complex(0, 0);
            for (int i = 0; i < len2; i++)
                x2[i] = Complex(str2[len2 - 1 - i] - '0', 0);
            for (int i = len2; i < len; i++)
                x2[i] = Complex(0, 0);
            //求DFT
            fft(x1, len, 1);
            fft(x2, len, 1);
            for (int i = 0; i < len; i++)
                x1[i] = x1[i] * x2[i];
            fft(x1, len, -1);
            for (int i = 0; i < len; i++)
                sum[i] = (int)(x1[i].real() + 0.5);
            for (int i = 0; i < len; i++)
            {
                sum[i + 1] += sum[i] / 10;
                sum[i] %= 10;
            }
            len = len1 + len2 - 1;
            while (sum[len] <= 0 && len > 0)
                len--;
            for (int i = len; i >= 0; i--)
                printf("%c", sum[i] + '0');
            printf("
    ");
        }
        return 0;
    }
    
    
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  • 原文地址:https://www.cnblogs.com/coded-ream/p/7286016.html
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