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  • Commonly Used Data Structures And Time Complexity

    Trie

    Time Complexity

    Insert/search O(l), l is the length of the word

    Space Complexity

    O(prefixes), O(n * l * l) n words with length l


    Binary Search Tree

    H is the height of the tree, if the tree is balanced, h = logn


    Data Structure

    get

    search

    insert

    delete

    Array

    O(1)

    O(n)

    O(n)

    O(n)

    ArrayList

    O(1)

    O(n)

    O(1)

    O(1)

    LinkedList

    O(n)

    O(n)

    O(1)

    O(1)

    Stack

    O(n)

    O(n)

    O(1)

    O(1)

    PriorityQueue

    O(logn)

    O(n)

    O(logn )

    O(n)

    HashMap

    O(1)

    O(1)

    O(1)

    O(1)

    TreeMap

    O(logn)

    O(n)

    O(logn)

    O(logn)

    HashSet

    O(1)

    O(1)

    O(1)

    O(1)

    Trie

    O(L)

    O(L)

    O(L)

    O(L)

    B Tree

    O(logn)

    O(logn)

    O(logn)

    O(logn)

    Binary Search Tree

    O(h)

    O(h)

    O(h)

    O(h)

     

    Master Theorem Cheatsheet

    EquationTimeSpaceExamples
    T(n) = 2*T(n/2) + O(n) O(nlogn) O(logn) quick_sort
    T(n) = 2*T(n/2) + O(n) O(nlogn) O(n + logn) merge_sort
    T(n) = T(n/2) + O(1) O(logn) O(logn) Binary search
    T(n) = 2*T(n/2) + O(1) O(n) O(logn) Binary tree traversal
    T(n) = T(n-1) + O(1) O(n) O(n) Binary tree traversal
    T(n) = T(n-1) + O(n) O(n^2) O(n) quick_sort(worst case)
    T(n) = n * T(n-1) O(n!) O(n) permutation
    T(n) = T(n-1)+T(n-2)+…+T(1) O(2^n) O(n) combination
        @Test
        public void testQueue() {
            Queue<String> queue = new LinkedList<>();
            queue.offer("a");
            queue.offer("b");
            System.out.println(queue.peek()); // a
            System.out.println(queue.poll()); // a
        }
    
        @Test
        public void testStack() {
            Stack<String> stack = new Stack<>();
            stack.push("a");
            stack.push("b");
            System.out.println(stack.peek()); // b
            System.out.println(stack.pop());  // b
        }
    
        @Test
        public void testDeque() {
            Deque<String> deque = new LinkedList<>();
            String[] array = {"1", "2", "3", "4"};
    
            // used as a stack
            for (String ele: array) {
                deque.push(ele);
            }
            System.out.println(deque.peekFirst()); // 4
            System.out.println(deque.peekLast());  // 1
            System.out.println(deque.pop());  // 4
            System.out.println(deque.removeFirst());  // 3
            System.out.println(deque.removeLast());  // 1
    
            deque.clear();
    
            // used as a queue
            for (String ele: array) {
                deque.offer(ele);
            }
            System.out.println(deque.peekFirst()); // 1
            System.out.println(deque.peekLast());  // 4
            System.out.println(deque.poll());  // 1
            System.out.println(deque.removeFirst());  // 2
            System.out.println(deque.removeLast());  // 4
        }
    
        @Test
        public void testPriorityQueue() {
            Integer[] array = {3, 1, 4, 2};
            // By default it is a min heap
            PriorityQueue<Integer> minHeap = new PriorityQueue<>();
            for (Integer ele: array) {
                minHeap.offer(ele);
            }
    
            System.out.println(minHeap.poll());  // 1
    
            // Create a max heap
            PriorityQueue<Integer> maxHeap = new PriorityQueue<>(Collections.reverseOrder());
            // PriorityQueue<Integer> maxHeap = new PriorityQueue<>((x, y) -> y - x);
    
            for (Integer ele: array) {
                maxHeap.offer(ele);
            }
    
            System.out.println(maxHeap.poll());  // 4
        }
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  • 原文地址:https://www.cnblogs.com/codingforum/p/9990861.html
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