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  • Guava包学习---Maps

    Maps包方法列表:

    还是泛型创建Map:

    public static <K, V> HashMap<K, V> newHashMap() {
        return new HashMap<K, V>();
      }
    
    public static <K, V> HashMap<K, V> newHashMapWithExpectedSize(int expectedSize) {
        return new HashMap<K, V>(capacity(expectedSize));
      }
    
    public static <K, V> HashMap<K, V> newHashMap(Map<? extends K, ? extends V> map) {
    return new HashMap<K, V>(map);
    }
    
    public static <K, V> LinkedHashMap<K, V> newLinkedHashMap() {
    return new LinkedHashMap<K, V>();
    }
    
    public static <K, V> LinkedHashMap<K, V> newLinkedHashMapWithExpectedSize(int expectedSize) {
    return new LinkedHashMap<K, V>(capacity(expectedSize));
    }
    
     public static <K, V> LinkedHashMap<K, V> newLinkedHashMap(Map<? extends K, ? extends V> map) {
        return new LinkedHashMap<K, V>(map);
      }
    
     public static <K, V> ConcurrentMap<K, V> newConcurrentMap() {
        return new MapMaker().<K, V>makeMap();
      }
      public static <K extends Comparable, V> TreeMap<K, V> newTreeMap() {
        return new TreeMap<K, V>();
      }

    还有一些EnumMap、IdentitiyMap等,但是不经常用,就不贴了。

    Map中的不同,还有其他几种方式,这里就只贴个最常用的吧。

     public static <K, V> MapDifference<K, V> difference(
          Map<? extends K, ? extends V> left, Map<? extends K, ? extends V> right) {
        if (left instanceof SortedMap) {
          SortedMap<K, ? extends V> sortedLeft = (SortedMap<K, ? extends V>) left;
          SortedMapDifference<K, V> result = difference(sortedLeft, right);
          return result;
        }
        return difference(left, right, Equivalence.equals());
      }

    Set和其他内容转Map,这个方法在获得某些对象转Map操作比较好用。

      public static <K, V> Map<K, V> asMap(Set<K> set, Function<? super K, V> function) {
        if (set instanceof SortedSet) {
          return asMap((SortedSet<K>) set, function);
        } else {
          return new AsMapView<K, V>(set, function);
        }
      }

    某些对象转不可变Map,和上面一样,你只要声明一个Guava的Function覆盖以下它的方法然后传入进来即可:

     public static <K, V> ImmutableMap<K, V> toMap(
          Iterable<K> keys, Function<? super K, V> valueFunction) {
        return toMap(keys.iterator(), valueFunction);
      }

    接下来这个有点牛逼的,然后从来不知道该用在哪里的方法,反正我是没碰到这种场景:

      /**
       * Returns a view of a map where each value is transformed by a function. All
       * other properties of the map, such as iteration order, are left intact. For
       * example, the code: <pre>   {@code
       *
       *   Map<String, Integer> map = ImmutableMap.of("a", 4, "b", 9);
       *   Function<Integer, Double> sqrt =
       *       new Function<Integer, Double>() {
       *         public Double apply(Integer in) {
       *           return Math.sqrt((int) in);
       *         }
       *       };
       *   Map<String, Double> transformed = Maps.transformValues(map, sqrt);
       *   System.out.println(transformed);}</pre>
       *
       * ... prints {@code {a=2.0, b=3.0}}.
       *
      public static <K, V1, V2> Map<K, V2> transformValues(
          Map<K, V1> fromMap, Function<? super V1, V2> function) {
        return transformEntries(fromMap, asEntryTransformer(function));
      }

    基本上每种类型的Map都会有几个方法去处理,不一一列举。

    接下里又是传入Prediction过滤Map:

      @CheckReturnValue
      public static <K, V> Map<K, V> filterKeys(
          Map<K, V> unfiltered, final Predicate<? super K> keyPredicate) {
        if (unfiltered instanceof SortedMap) {
          return filterKeys((SortedMap<K, V>) unfiltered, keyPredicate);
        } else if (unfiltered instanceof BiMap) {
          return filterKeys((BiMap<K, V>) unfiltered, keyPredicate);
        }
        checkNotNull(keyPredicate);
        Predicate<Entry<K, ?>> entryPredicate = keyPredicateOnEntries(keyPredicate);
        return (unfiltered instanceof AbstractFilteredMap)
            ? filterFiltered((AbstractFilteredMap<K, V>) unfiltered, entryPredicate)
            : new FilteredKeyMap<K, V>(checkNotNull(unfiltered), keyPredicate, entryPredicate);
      }
      @CheckReturnValue
      public static <K, V> Map<K, V> filterValues(
          Map<K, V> unfiltered, final Predicate<? super V> valuePredicate) {
        if (unfiltered instanceof SortedMap) {
          return filterValues((SortedMap<K, V>) unfiltered, valuePredicate);
        } else if (unfiltered instanceof BiMap) {
          return filterValues((BiMap<K, V>) unfiltered, valuePredicate);
        }
        return filterEntries(unfiltered, Maps.<V>valuePredicateOnEntries(valuePredicate));
      }
      @CheckReturnValue
      public static <K, V> Map<K, V> filterEntries(
          Map<K, V> unfiltered, Predicate<? super Entry<K, V>> entryPredicate) {
        if (unfiltered instanceof SortedMap) {
          return filterEntries((SortedMap<K, V>) unfiltered, entryPredicate);
        } else if (unfiltered instanceof BiMap) {
          return filterEntries((BiMap<K, V>) unfiltered, entryPredicate);
        }
        checkNotNull(entryPredicate);
        return (unfiltered instanceof AbstractFilteredMap)
            ? filterFiltered((AbstractFilteredMap<K, V>) unfiltered, entryPredicate)
            : new FilteredEntryMap<K, V>(checkNotNull(unfiltered), entryPredicate);
      }

    应该我碰到的场景太少了,List、set、map中都有大量代码去处理Navigate类型和immutable类型的集合,感觉还是用的太少了。需要再深入研究一下。

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  • 原文地址:https://www.cnblogs.com/congsg2016/p/5119676.html
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