Maps包方法列表:
还是泛型创建Map:
public static <K, V> HashMap<K, V> newHashMap() { return new HashMap<K, V>(); } public static <K, V> HashMap<K, V> newHashMapWithExpectedSize(int expectedSize) { return new HashMap<K, V>(capacity(expectedSize)); } public static <K, V> HashMap<K, V> newHashMap(Map<? extends K, ? extends V> map) { return new HashMap<K, V>(map); } public static <K, V> LinkedHashMap<K, V> newLinkedHashMap() { return new LinkedHashMap<K, V>(); } public static <K, V> LinkedHashMap<K, V> newLinkedHashMapWithExpectedSize(int expectedSize) { return new LinkedHashMap<K, V>(capacity(expectedSize)); } public static <K, V> LinkedHashMap<K, V> newLinkedHashMap(Map<? extends K, ? extends V> map) { return new LinkedHashMap<K, V>(map); } public static <K, V> ConcurrentMap<K, V> newConcurrentMap() { return new MapMaker().<K, V>makeMap(); } public static <K extends Comparable, V> TreeMap<K, V> newTreeMap() { return new TreeMap<K, V>(); }
还有一些EnumMap、IdentitiyMap等,但是不经常用,就不贴了。
Map中的不同,还有其他几种方式,这里就只贴个最常用的吧。
public static <K, V> MapDifference<K, V> difference( Map<? extends K, ? extends V> left, Map<? extends K, ? extends V> right) { if (left instanceof SortedMap) { SortedMap<K, ? extends V> sortedLeft = (SortedMap<K, ? extends V>) left; SortedMapDifference<K, V> result = difference(sortedLeft, right); return result; } return difference(left, right, Equivalence.equals()); }
Set和其他内容转Map,这个方法在获得某些对象转Map操作比较好用。
public static <K, V> Map<K, V> asMap(Set<K> set, Function<? super K, V> function) { if (set instanceof SortedSet) { return asMap((SortedSet<K>) set, function); } else { return new AsMapView<K, V>(set, function); } }
某些对象转不可变Map,和上面一样,你只要声明一个Guava的Function覆盖以下它的方法然后传入进来即可:
public static <K, V> ImmutableMap<K, V> toMap( Iterable<K> keys, Function<? super K, V> valueFunction) { return toMap(keys.iterator(), valueFunction); }
接下来这个有点牛逼的,然后从来不知道该用在哪里的方法,反正我是没碰到这种场景:
/** * Returns a view of a map where each value is transformed by a function. All * other properties of the map, such as iteration order, are left intact. For * example, the code: <pre> {@code * * Map<String, Integer> map = ImmutableMap.of("a", 4, "b", 9); * Function<Integer, Double> sqrt = * new Function<Integer, Double>() { * public Double apply(Integer in) { * return Math.sqrt((int) in); * } * }; * Map<String, Double> transformed = Maps.transformValues(map, sqrt); * System.out.println(transformed);}</pre> * * ... prints {@code {a=2.0, b=3.0}}. * public static <K, V1, V2> Map<K, V2> transformValues( Map<K, V1> fromMap, Function<? super V1, V2> function) { return transformEntries(fromMap, asEntryTransformer(function)); }
基本上每种类型的Map都会有几个方法去处理,不一一列举。
接下里又是传入Prediction过滤Map:
@CheckReturnValue public static <K, V> Map<K, V> filterKeys( Map<K, V> unfiltered, final Predicate<? super K> keyPredicate) { if (unfiltered instanceof SortedMap) { return filterKeys((SortedMap<K, V>) unfiltered, keyPredicate); } else if (unfiltered instanceof BiMap) { return filterKeys((BiMap<K, V>) unfiltered, keyPredicate); } checkNotNull(keyPredicate); Predicate<Entry<K, ?>> entryPredicate = keyPredicateOnEntries(keyPredicate); return (unfiltered instanceof AbstractFilteredMap) ? filterFiltered((AbstractFilteredMap<K, V>) unfiltered, entryPredicate) : new FilteredKeyMap<K, V>(checkNotNull(unfiltered), keyPredicate, entryPredicate); }
@CheckReturnValue public static <K, V> Map<K, V> filterValues( Map<K, V> unfiltered, final Predicate<? super V> valuePredicate) { if (unfiltered instanceof SortedMap) { return filterValues((SortedMap<K, V>) unfiltered, valuePredicate); } else if (unfiltered instanceof BiMap) { return filterValues((BiMap<K, V>) unfiltered, valuePredicate); } return filterEntries(unfiltered, Maps.<V>valuePredicateOnEntries(valuePredicate)); }
@CheckReturnValue public static <K, V> Map<K, V> filterEntries( Map<K, V> unfiltered, Predicate<? super Entry<K, V>> entryPredicate) { if (unfiltered instanceof SortedMap) { return filterEntries((SortedMap<K, V>) unfiltered, entryPredicate); } else if (unfiltered instanceof BiMap) { return filterEntries((BiMap<K, V>) unfiltered, entryPredicate); } checkNotNull(entryPredicate); return (unfiltered instanceof AbstractFilteredMap) ? filterFiltered((AbstractFilteredMap<K, V>) unfiltered, entryPredicate) : new FilteredEntryMap<K, V>(checkNotNull(unfiltered), entryPredicate); }
应该我碰到的场景太少了,List、set、map中都有大量代码去处理Navigate类型和immutable类型的集合,感觉还是用的太少了。需要再深入研究一下。