反转一个链表并输出各个结点的值

typedef struct Link
{
    int data;
    struct Link* next;
}NODE,*pNODE;

void reverse(pNODE *pphead)
{
    pNODE pcur = *pphead, ppre = NULL, ptemp;
    while(pcur != NULL)
    {
        ptemp = pcur->next;
        pcur->next = ppre;
        ppre = pcur;
        pcur = ptemp;
    }
    *pphead = ppre;
}