zoukankan      html  css  js  c++  java
  • HDU 1712 ACboy needs your help

    ACboy needs your help

    Time Limit: 1000ms
    Memory Limit: 32768KB
    This problem will be judged on HDU. Original ID: 1712
    64-bit integer IO format: %I64d      Java class name: Main
    ACboy has N courses this term, and he plans to spend at most M days on study.Of course,the profit he will gain from different course depending on the days he spend on it.How to arrange the M days for the N courses to maximize the profit?
     

    Input

    The input consists of multiple data sets. A data set starts with a line containing two positive integers N and M, N is the number of courses, M is the days ACboy has.
    Next follow a matrix A[i][j], (1<=i<=N<=100,1<=j<=M<=100).A[i][j] indicates if ACboy spend j days on ith course he will get profit of value A[i][j].
    N = 0 and M = 0 ends the input.
     

    Output

    For each data set, your program should output a line which contains the number of the max profit ACboy will gain.
     

    Sample Input

    2 2
    1 2
    1 3
    2 2
    2 1
    2 1
    2 3
    3 2 1
    3 2 1
    0 0

    Sample Output

    3
    4
    6

    Source

     
    解题:分组背包,把每门课程看成一组背包
     
     1 #include <bits/stdc++.h>
     2 using namespace std;
     3 const int maxn = 110;
     4 int dp[maxn],n,m,A[maxn][maxn];
     5 int main() {
     6     while(scanf("%d %d",&n,&m),n||m) {
     7         for(int i = 0; i < n; ++i)
     8             for(int j = 0; j < m; ++j)
     9                 scanf("%d",A[i]+j);
    10         memset(dp,0,sizeof dp);
    11         for(int i = 0; i < n; ++i) {
    12             for(int j = m; j >= 0; --j) {
    13                 for(int k = 1; k <= j; ++k)
    14                     dp[j] = max(dp[j],dp[j-k]+A[i][k-1]);
    15             }
    16         }
    17         printf("%d
    ",dp[m]);
    18     }
    19     return 0;
    20 }
    View Code
  • 相关阅读:
    Linux
    CUDA开发
    Linux C++
    Python
    C++
    模式识别
    Linux
    算法
    算法
    leetcode 数组,链表,跳表
  • 原文地址:https://www.cnblogs.com/crackpotisback/p/4447247.html
Copyright © 2011-2022 走看看