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  • 2017 ACM/ICPC 沈阳 I题 Little Boxes

    Little boxes on the hillside. 
    Little boxes made of ticky-tacky. 
    Little boxes. 
    Little boxes. 
    Little boxes all the same. 
    There are a green boxes, and b pink boxes. 
    And c blue boxes and d yellow boxes. 
    And they are all made out of ticky-tacky. 
    And they all look just the same. 

    InputThe input has several test cases. The first line contains the integer t (1 ≤ t ≤ 10) which is the total number of test cases. 
    For each test case, a line contains four non-negative integers a, b, c and d where a, b, c, d ≤ 2^62, indicating the numbers of green boxes, pink boxes, blue boxes and yellow boxes. 
    OutputFor each test case, output a line with the total number of boxes. 
    Sample Input

    4
    1 2 3 4
    0 0 0 0
    1 0 0 0
    111 222 333 404

    Sample Output

    10
    0
    1
    1070
    题解: 题意就是求a+b+c+d的结果
    C++大数模板求即可Orz
      1 #include <bits/stdc++.h>
      2 using namespace std;
      3 // base and base_digits must be consistent
      4 constexpr int base = 1000000000;
      5 constexpr int base_digits = 9;
      6 struct bigint{
      7     vector<int> z;
      8     int sign;
      9     bigint() : sign(1) {}
     10     bigint(long long v) { *this = v; }
     11     bigint& operator=(long long v)
     12     {
     13         sign = v < 0 ? -1 : 1;
     14         v*=sign;
     15         z.clear();
     16         for(; v > 0; v = v / base) z.push_back((int)(v % base));
     17         return *this;
     18     }
     19 
     20     bigint(const string& s) { read(s); }
     21 
     22     bigint& operator+=(const bigint& other)
     23     {
     24         if (sign == other.sign)
     25         {
     26             for (int i = 0, carry = 0; i < other.z.size() || carry; ++i)
     27             {
     28                 if(i==z.size()) z.push_back(0);
     29                 z[i] += carry + (i < other.z.size() ? other.z[i] : 0);
     30                 carry = z[i] >= base;
     31                 if(carry) z[i] -= base;
     32             }
     33         }
     34         else if (other != 0 /* prevent infinite loop */)
     35         {
     36             *this -= -other;
     37         }
     38         return *this;
     39     }
     40 
     41     friend bigint operator+(bigint a, const bigint& b)
     42     {
     43         return a += b;
     44     }
     45 
     46     bigint& operator-=(const bigint& other)
     47     {
     48         if (sign == other.sign)
     49         {
     50             if (sign == 1 && *this >= other || sign == -1 && *this <= other)
     51             {
     52                 for (int i = 0, carry = 0; i < other.z.size() || carry; ++i)
     53                 {
     54                     z[i] -= carry + (i < other.z.size() ? other.z[i] : 0);
     55                     carry = z[i] < 0;
     56                     if(carry) z[i] += base;
     57                 }
     58                 trim();
     59             }
     60             else
     61             {
     62                 *this = other - *this;
     63                 this->sign = -this->sign;
     64             }
     65         }
     66         else *this += -other;
     67         return *this;
     68     }
     69 
     70     friend bigint operator - (bigint a,const bigint& b)
     71     {
     72         return a -= b;
     73     }
     74 
     75     bigint& operator*=(int v)
     76     {
     77         if(v<0) sign=-sign,v=-v;
     78         for(int i=0,carry=0;i<z.size() || carry;++i)
     79         {
     80             if(i==z.size()) z.push_back(0);
     81             long long cur = (long long)z[i] * v + carry;
     82             carry = (int)(cur / base);
     83             z[i] = (int)(cur % base);
     84         }
     85         trim();
     86         return *this;
     87     }
     88 
     89     bigint operator*(int v) const
     90     {
     91         return bigint(*this) *= v;
     92     }
     93 
     94     friend pair<bigint, bigint> divmod(const bigint& a1, const bigint& b1)
     95     {
     96         int norm = base / (b1.z.back() + 1);
     97         bigint a = a1.abs() * norm;
     98         bigint b = b1.abs() * norm;
     99         bigint q, r;
    100         q.z.resize(a.z.size());
    101 
    102         for (int i = (int)a.z.size() - 1; i >= 0; i--)
    103         {
    104             r*=base; r+=a.z[i];
    105             int s1 = b.z.size() < r.z.size() ? r.z[b.z.size()] : 0;
    106             int s2 = b.z.size() - 1 < r.z.size() ? r.z[b.z.size() - 1] : 0;
    107             int d = (int)(((long long)s1 * base + s2) / b.z.back());
    108             r -= b * d;
    109             while(r < 0) r+=b,--d;
    110             q.z[i] = d;
    111         }
    112 
    113         q.sign = a1.sign * b1.sign;
    114         r.sign = a1.sign;
    115         q.trim();
    116         r.trim();
    117         return {q, r / norm};
    118     }
    119 
    120     friend bigint sqrt(const bigint& a1)
    121     {
    122         bigint a=a1;
    123         while(a.z.empty()||a.z.size()%2==1) a.z.push_back(0);
    124 
    125         int n = a.z.size();
    126         int firstDigit = (int)::sqrt((double)a.z[n - 1] * base + a.z[n - 2]);
    127         int norm = base / (firstDigit + 1);
    128         a *= norm;
    129         a *= norm;
    130         while(a.z.empty()||a.z.size()%2==1) a.z.push_back(0);
    131 
    132         bigint r = (long long)a.z[n - 1] * base + a.z[n - 2];
    133         firstDigit = (int)::sqrt((double)a.z[n - 1] * base + a.z[n - 2]);
    134         int q = firstDigit;
    135         bigint res;
    136         for (int j = n / 2 - 1; j >= 0; j--)
    137         {
    138             for(;;--q)
    139             {
    140                 bigint r1=(r-(res*2*base+q)*q)*base*base+(j>0?(long long)a.z[2*j-1]*base+a.z[2*j-2]:0);
    141                 if(r1>=0) { r=r1; break; }
    142             }
    143             res*=base;res+=q;
    144             if(j>0)
    145             {
    146                 int d1 = res.z.size() + 2 < r.z.size() ? r.z[res.z.size() + 2] : 0;
    147                 int d2 = res.z.size() + 1 < r.z.size() ? r.z[res.z.size() + 1] : 0;
    148                 int d3 = res.z.size() < r.z.size() ? r.z[res.z.size()]:0;
    149                 q = (int)(((long long)d1*base*base+(long long)d2*base+d3)/(firstDigit*2));
    150             }
    151         }
    152 
    153         res.trim();
    154         return res / norm;
    155     }
    156 
    157     bigint operator/(const bigint& v) const
    158     {
    159         return divmod(*this, v).first;
    160     }
    161 
    162     bigint operator%(const bigint& v) const
    163     {
    164         return divmod(*this, v).second;
    165     }
    166 
    167     bigint& operator/=(int v)
    168     {
    169         if(v<0) sign=-sign,v=-v;
    170         for (int i = (int)z.size() - 1, rem = 0; i >= 0; --i)
    171         {
    172             long long cur = z[i] + rem * (long long)base;
    173             z[i] = (int)(cur / v);
    174             rem = (int)(cur % v);
    175         }
    176         trim();
    177         return *this;
    178     }
    179 
    180     bigint operator/(int v) const
    181     {
    182         return bigint(*this) /= v;
    183     }
    184 
    185     int operator%(int v) const
    186     {
    187         if(v<0) v=-v;
    188         int m=0;
    189         for(int i=(int)z.size()-1;i>=0;--i) m=(int)((z[i]+m*(long long)base)%v);
    190         return m * sign;
    191     }
    192 
    193     bigint& operator*=(const bigint& v)
    194     {
    195         *this = *this * v;
    196         return *this;
    197     }
    198 
    199     bigint& operator/=(const bigint& v)
    200     {
    201         *this = *this / v;
    202         return *this;
    203     }
    204 
    205     bool operator<(const bigint& v) const
    206     {
    207         if(sign!=v.sign) return sign < v.sign;
    208         if(z.size()!=v.z.size()) return z.size()*sign<v.z.size()*v.sign;
    209         for(int i = (int)z.size() - 1; i >= 0; i--)
    210             if(z[i] != v.z[i])  return z[i] * sign < v.z[i] * sign;
    211         return false;
    212     }
    213 
    214     bool operator>(const bigint& v) const { return v < *this; }
    215     bool operator<=(const bigint& v) const { return !(v < *this); }
    216     bool operator>=(const bigint& v) const { return !(*this < v); }
    217     bool operator==(const bigint& v) const { return !(*this < v) && !(v < *this); }
    218     bool operator!=(const bigint& v) const { return *this < v || v < *this; }
    219 
    220     void trim()
    221     {
    222         while(!z.empty() && z.back() == 0) z.pop_back();
    223         if(z.empty()) sign = 1;
    224     }
    225 
    226     bool isZero() const { return z.empty(); }
    227 
    228     friend bigint operator-(bigint v)
    229     {
    230         if(!v.z.empty()) v.sign = -v.sign;
    231         return v;
    232     }
    233 
    234     bigint abs() const
    235     {
    236         return sign == 1 ? *this : -*this;
    237     }
    238 
    239     long long longValue() const
    240     {
    241         long long res = 0;
    242         for(int i = (int)z.size() - 1; i >= 0; i--) res = res * base + z[i];
    243         return res * sign;
    244     }
    245 
    246     friend bigint gcd(const bigint& a, const bigint& b)
    247     {
    248         return b.isZero() ? a : gcd(b, a % b);
    249     }
    250 
    251     friend bigint lcm(const bigint& a, const bigint& b)
    252     {
    253         return a / gcd(a, b) * b;
    254     }
    255 
    256     void read(const string& s)
    257     {
    258         sign = 1;
    259         z.clear();
    260         int pos = 0;
    261         while(pos < s.size() && (s[pos] == '-' || s[pos] == '+'))
    262         {
    263             if(s[pos] == '-') sign = -sign;
    264             ++pos;
    265         }
    266         for(int i=(int)s.size()-1;i>=pos;i-=base_digits)
    267         {
    268             int x=0;
    269             for(int j=max(pos,i-base_digits+1);j<=i;j++) x=x*10+s[j]-'0';
    270             z.push_back(x);
    271         }
    272         trim();
    273     }
    274 
    275     friend istream& operator>>(istream& stream, bigint& v)
    276     {
    277         string s;
    278         stream >> s;
    279         v.read(s);
    280         return stream;
    281     }
    282 
    283     friend ostream& operator<<(ostream& stream, const bigint& v)
    284     {
    285         if(v.sign == -1) stream << '-';
    286         stream << (v.z.empty() ? 0 : v.z.back());
    287         for(int i = (int)v.z.size() - 2; i >= 0; --i)
    288             stream << setw(base_digits) << setfill('0') << v.z[i];
    289         return stream;
    290     }
    291 
    292     static vector<int> convert_base(const vector<int>& a, int old_digits, int new_digits)
    293     {
    294         vector<long long> p(max(old_digits, new_digits) + 1);
    295         p[0] = 1;
    296         for(int i=1;i<p.size();i++) p[i]=p[i-1]*10;
    297         vector<int> res;
    298         long long cur = 0;
    299         int cur_digits = 0;
    300         for(int v : a)
    301         {
    302             cur += v * p[cur_digits];
    303             cur_digits += old_digits;
    304             while (cur_digits >= new_digits)
    305             {
    306                 res.push_back(int(cur % p[new_digits]));
    307                 cur /= p[new_digits];
    308                 cur_digits -= new_digits;
    309             }
    310         }
    311         res.push_back((int)cur);
    312         while(!res.empty() && res.back()==0)
    313             res.pop_back();
    314         return res;
    315     }
    316 
    317     typedef vector<long long> vll;
    318     static vll karatsubaMultiply(const vll& a, const vll& b)
    319     {
    320         int n=a.size();
    321         vll res(n + n);
    322         if(n <= 32)
    323         {
    324             for (int i = 0; i < n; i++)
    325                 for (int j = 0; j < n; j++)
    326                     res[i + j] += a[i] * b[j];
    327             return res;
    328         }
    329 
    330         int k = n >> 1;
    331         vll a1(a.begin(), a.begin() + k);
    332         vll a2(a.begin() + k, a.end());
    333         vll b1(b.begin(), b.begin() + k);
    334         vll b2(b.begin() + k, b.end());
    335         vll a1b1 = karatsubaMultiply(a1, b1);
    336         vll a2b2 = karatsubaMultiply(a2, b2);
    337         for(int i=0;i<k;i++) a2[i]+=a1[i];
    338         for(int i=0;i<k;i++) b2[i]+=b1[i];
    339 
    340         vll r = karatsubaMultiply(a2, b2);
    341         for(int i=0;i<a1b1.size();i++) r[i]-=a1b1[i];
    342         for(int i=0;i<a2b2.size();i++) r[i]-=a2b2[i];
    343         for(int i=0;i<r.size();i++) res[i+k]+=r[i];
    344         for(int i=0;i<a1b1.size();i++) res[i]+=a1b1[i];
    345         for(int i = 0;i<a2b2.size();i++) res[i+n]+=a2b2[i];
    346         return res;
    347     }
    348 
    349     bigint operator*(const bigint& v) const
    350     {
    351         vector<int> a6=convert_base(this->z,base_digits,6);
    352         vector<int> b6=convert_base(v.z,base_digits,6);
    353         vll a(a6.begin(),a6.end());
    354         vll b(b6.begin(),b6.end());
    355         while(a.size()<b.size()) a.push_back(0);
    356         while(b.size()<a.size()) b.push_back(0);
    357         while(a.size()&(a.size()-1)) a.push_back(0),b.push_back(0);
    358         vll c=karatsubaMultiply(a, b);
    359         bigint res;
    360         res.sign = sign * v.sign;
    361         for (int i = 0, carry = 0; i < c.size(); i++)
    362         {
    363             long long cur = c[i] + carry;
    364             res.z.push_back((int)(cur % 1000000));
    365             carry = (int)(cur / 1000000);
    366         }
    367         res.z = convert_base(res.z, 6, base_digits);
    368         res.trim();
    369         return res;
    370     }
    371 };
    372 int main()
    373 {
    374     ios::sync_with_stdio(0);
    375     cin.tie(0);
    376     bigint a, b, c, d;
    377     int T; cin >> T;
    378     while(T--)
    379     {
    380         cin >>a>>b>>c>>d;
    381         a=a+b+c+d;
    382         cout<<a<<endl;
    383         
    384     }
    385     return 0;
    386 }
    View Code

      

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  • 原文地址:https://www.cnblogs.com/csushl/p/9784966.html
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