1148 Werewolf

1148 Werewolf - Simple Version (20分)

Werewolf（狼人杀） is a game in which the players are partitioned into two parties: the werewolves and the human beings. Suppose that in a game,

player #1 said: "Player #2 is a werewolf.";
player #2 said: "Player #3 is a human.";
player #3 said: "Player #4 is a werewolf.";
player #4 said: "Player #5 is a human."; and
player #5 said: "Player #4 is a human.".

Given that there were 2 werewolves among them, at least one but not all the werewolves were lying, and there were exactly 2 liars. Can you point out the werewolves?

Now you are asked to solve a harder version of this problem: given that there were N players, with 2 werewolves among them, at least one but not all the werewolves were lying, and there were exactly 2 liars. You are supposed to point out the werewolves.
Input Specification:

Each input file contains one test case. For each case, the first line gives a positive integer N (5≤N≤100). Then N lines follow and the i-th line gives the statement of the i-th player (1≤i≤N), which is represented by the index of the player with a positive sign for a human and a negative sign for a werewolf.
Output Specification:

If a solution exists, print in a line in ascending order the indices of the two werewolves. The numbers must be separated by exactly one space with no extra spaces at the beginning or the end of the line. If there are more than one solution, you must output the smallest solution sequence -- that is, for two sequences A=a[1],...,a[M] and B=b[1],...,b[M], if there exists 0≤k<M such that a[i]=b[i] (i≤k) and a[k+1]<b[k+1], then A is said to be smaller than B. In case there is no solution, simply print No Solution.
Sample Input 1:

5
-2
+3
-4
+5
+4

Sample Output 1:

1 4

Sample Input 2:

6
+6
+3
+1
-5
-2
+4

Sample Output 2 (the solution is not unique):

1 5

Sample Input 3:

5
-2
-3
-4
-5
-1

Sample Output 3:

No Solution

思路

暴力：
时间复杂度o3 N<= 100 , 100 * 100 * 100 = 1e6
每次假设两个人是狼， 然后判断n个人说的话， 如果有人说的是狼但是不是假设的狼，此人就在说谎， 如果有人说是好人但是是狼那么此人在说谎,
判断说谎人的时候还需要统计一下，狼说谎的数量。 当有一组数据满足要求输出答案即可

代码

#include<bits/stdc++.h>
using namespace std;
int main()
{
    int n;
    scanf("%d", &n);
    vector<int> v;
    int num;
    for(int i = 0; i < n; i++) {
        scanf("%d", &num);
        v.push_back(num);
    }
    for(int i = 1; i <= n; i++) {
        for(int j = i + 1; j <= n; j++) {
            int liers = 0, wolf = 0;
            for(int k = 0; k < v.size(); k++) {
                if(v[k] > 0) {
                    if(v[k] == i || v[k] == j) {
                        if(k + 1 == i || k + 1 == j) {
                            wolf++;
                        }
                        liers++;
                    }
                } else {
                    if(abs(v[k]) != i && abs(v[k]) != j) {
                        if(k + 1 == i || k + 1 == j) wolf++;
                        liers++;
                    }
                }
            }
            if(liers == 2 && wolf == 1) {
                printf("%d %d
", i, j);
                return 0;
            }
        }
    }
    printf("No Solution
");
    return 0;
}