zoukankan      html  css  js  c++  java
  • Who is Older?(水题)

    Who is Older?

    Time Limit: 1 Second      Memory Limit: 32768 KB

    Javaman and cpcs are arguing who is older. Write a program to help them.

    Input

    There are multiple test cases. The first line of input is an integer T (0 < T <= 1000) indicating the number of test cases. Then T test cases follow. The i-th line of the next T lines contains two dates, the birthday of javaman and the birthday of cpcs. The format of the date is "yyyy mm dd". You may assume the birthdays are both valid.

    Output

    For each test case, output who is older in a single line. If they have the same birthday, output "same" (without quotes) instead.

    Sample Input

    3
    1983 06 06 1984 05 02
    1983 05 07 1980 02 29
    1991 01 01 1991 01 01
    

    Sample Output

    javaman
    cpcs
    same

     1 #include <iostream>
     2 #include <cstdio>
     3 
     4 using namespace std;
     5 
     6 int main()
     7 {
     8     int t, x[3], y[3], tag;
     9     cin >> t;
    10     while(t--)
    11     {
    12         cin >> x[0] >> x[1] >> x[2] >> y[0] >> y[1] >> y[2];
    13         if(x[0] > y[0]) tag = 1;
    14         else if(x[0] < y[0]) tag = -1;
    15         else
    16         {
    17             if(x[1] > y[1]) tag = 1;
    18             else if(x[1] < y[1]) tag = -1;
    19             else
    20             {
    21                 if(x[2] > y[2]) tag = 1;
    22                 else if(x[2] < y[2]) tag = -1;
    23                 else tag = 0;
    24             }
    25         }
    26         if(tag > 0) puts("cpcs");
    27         else if(tag < 0) puts("javaman");
    28         else puts("same");
    29     } 
    30     return 0;
    31 }
  • 相关阅读:
    flex 居中并两端对齐
    搭建Docker环境---私有仓库registry搭建
    搭建Docker环境---常用命令
    搭建Docker环境---Docker安装(centos7)
    搭建Docker环境---Docker概述
    Shell脚本
    安装webstrom2019
    mysql主从配置
    MySql5.7安装(centos 7)
    MySQL父子节点查询
  • 原文地址:https://www.cnblogs.com/cszlg/p/2912822.html
Copyright © 2011-2022 走看看