zoukankan      html  css  js  c++  java
  • PAT 1073 Scientific Notation

    1073 Scientific Notation (20 分)
     

    Scientific notation is the way that scientists easily handle very large numbers or very small numbers. The notation matches the regular expression [+-][1-9].[0-9]+E[+-][0-9]+ which means that the integer portion has exactly one digit, there is at least one digit in the fractional portion, and the number and its exponent's signs are always provided even when they are positive.

    Now given a real number A in scientific notation, you are supposed to print A in the conventional notation while keeping all the significant figures.

    Input Specification:

    Each input contains one test case. For each case, there is one line containing the real number A in scientific notation. The number is no more than 9999 bytes in length and the exponent's absolute value is no more than 9999.

    Output Specification:

    For each test case, print in one line the input number A in the conventional notation, with all the significant figures kept, including trailing zeros.

    Sample Input 1:

    +1.23400E-03
    

    Sample Output 1:

    0.00123400
    

    Sample Input 2:

    -1.2E+10
    

    Sample Output 2:

    -12000000000
    #include<bits/stdc++.h>
    using namespace std;
    typedef long long ll;
    
    
    int to_int(string s){
        int sum=0;
        for(int i=0;i < s.size();i++){
            sum = sum*10+(s[i]-'0');
        }
        return sum;
    }
    
    
    
    int main(){
        string s;cin >> s;
        if(s[0] == '-')cout << "-";
        s = s.substr(1,s.size()-1);
    
        int pose = 0;
        for(int i=0;i < s.size();i++){
            if(s[i] == 'E')pose=i;
        }
        string s1 = s.substr(0,pose);
        string s2 = s.substr(pose+2,s.size()-pose-2);
    //    cout << s1 << " " << s2 <<endl;
    //    cout << to_int(s2);
        int cnt = to_int(s2);
    
    
        string temp="";
        for(int i=0;i<s1.size();i++){
            if(s1[i]!='.')temp = temp+s1[i];
        }
    //    cout << temp;
        if(s[pose+1] == '-'){
            string head = "0.";
            for(int i=0;i < cnt-1;i++) head = head+"0";
            head = head + temp;
            cout << head;
        }
        else if(s[pose+1] == '+'){
            if(temp.size() > cnt){
                for(int i=0;i <= cnt;i++)cout << temp[i];
                if(cnt != temp.size()-1)cout << ".";
                for(int i=cnt+1;i < temp.size();i++)cout << temp[i];
            }
            else{
                cout << temp;
                for(int i=0;i <= cnt-temp.size();i++)cout << "0";
            }
        }
    
    
    
        return 0;
    }

    _1AC

     
  • 相关阅读:
    一个Spring的应用看起来象什么?
    IOC的优点是什么?
    解释对象/关系映射集成模块?
    XMLBeanFactory?
    使用Spring框架的好处是什么?
    什么是Spring MVC框架的控制器?
    什么是Spring的MVC框架?
    在Spring AOP 中,关注点和横切关注的区别是什么?
    你更倾向用那种事务管理类型?
    Spring支持的事务管理类型?
  • 原文地址:https://www.cnblogs.com/cunyusup/p/10774874.html
Copyright © 2011-2022 走看看