zoukankan      html  css  js  c++  java
  • PAT 1120 Friend Numbers

    1120 Friend Numbers (20 分)
     

    Two integers are called "friend numbers" if they share the same sum of their digits, and the sum is their "friend ID". For example, 123 and 51 are friend numbers since 1+2+3 = 5+1 = 6, and 6 is their friend ID. Given some numbers, you are supposed to count the number of different frind ID's among them.

    Input Specification:

    Each input file contains one test case. For each case, the first line gives a positive integer N. Then N positive integers are given in the next line, separated by spaces. All the numbers are less than 1.

    Output Specification:

    For each case, print in the first line the number of different frind ID's among the given integers. Then in the second line, output the friend ID's in increasing order. The numbers must be separated by exactly one space and there must be no extra space at the end of the line.

    Sample Input:

    8
    123 899 51 998 27 33 36 12
    

    Sample Output:

    4
    3 6 9 26
    #include<bits/stdc++.h>
    using namespace std;
    typedef long long ll;
    
    
    
    
    
    int main(){
        int t;
        cin >> t;
        set<int> st;
    
        while(t--){
            string s;
            cin >> s;
            int sum = 0;
            for(int i=0;i < s.size();i++){
                sum += s[i] - '0';
            }
            st.insert(sum);
        }
    
        cout << st.size() << endl;
        int cnt = 0;
    
        for(auto it=st.begin();it!=st.end();it++){
            cout << *it;
            cnt++;
            if(cnt!=st.size())cout << " ";
        }
    
        return 0;
    }

    这题白给

    最后一行无空格可以这样写

    if(it != s.begin()) printf(" ");
     
  • 相关阅读:
    NoSuchMethodError: Closure call with mismatched arguments:
    pod reopened update慢
    Flutter ListView 不满屏 无法滚动
    三分钟告诉你MBR和GPT的区别,选择适合自己的
    centos8 安装VMware,之后不能启动问题处理
    Docker学习之路
    JavaScript 编程语言
    工具
    Java开发
    Oracle的学习
  • 原文地址:https://www.cnblogs.com/cunyusup/p/10791296.html
Copyright © 2011-2022 走看看