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  • 紫书p199 八数码(BFS,hash)

    八数码问题  紫书上的简单搜索  渣渣好久才弄懂

    #include<cstdio>
    #include<cstring>
    using namespace std;
    const int M = 1000003;
    int x[4] = { -1, 1, 0, 0}, y[4] = {0, 0, -1, 1};
    int dis[M], h[M], s[M][9], e[9];
    
    int aton(int a[])
    {
        int t = 0;
        for(int i = 0; i < 9; ++i)
            t = t * 10 + a[i];
        return t;
    }
    
    int search_hash(int a[])
    {
        int t = aton(a), p = t % M;
        while(h[p])
        {
            if(h[p] == t) return p;
            ++p;
            if(p >= M) p = 0;
        }
        return p;
    }
    
    int bfs()
    {
        memset(h, 0, sizeof(h));
        int fro = 1, rear = 2, r, c, k = 0, p;
        int t[9], tmp, cur, nr, nc, nk;
    
        while(fro < rear)
        {
            memcpy(t, s[fro], sizeof(t));
            cur = search_hash(t);
            if(memcmp(t, e, sizeof(t)) == 0) return dis[cur];
            for(k = 0; t[k];) ++k;
            r = k / 3, c = k % 3;
            for(int i = 0; i < 4; ++i)
            {
                memcpy(t, s[fro], sizeof(t));
                nr = r + x[i], nc = c + y[i], nk = nr * 3 + nc;
                if(nr < 0 || nr > 2 || nc < 0 || nc > 2) continue;
                tmp = t[nk];
                t[nk] = 0;
                t[k] = tmp;
                p = search_hash(t);
                if(h[p] == 0)
                {
                    h[p] = aton(t);
                    dis[p] = dis[cur] + 1;
                    memcpy(s[rear], t, sizeof(t));
                    ++rear;
                }
            }
            ++fro;
        }
        return -1;
    }
    
    int main()
    {
        while(~scanf("%d", &s[1][0]))
        {
            memset(dis, 0, sizeof(dis));
            for(int i = 1; i < 9; ++i)
                scanf("%d", &s[1][i]);
            for(int i = 0; i < 9; ++i)
                scanf("%d", &e[i]);
            h[aton(s[1]) % M] = aton(s[1]);
            int ans = bfs();
            if(ans != -1)
                printf("%d
    ", ans);
            else  printf("No solution
    ");
        }
        return 0;
    }
    /*
    2 6 4 1 3 7 0 5 8
    8 1 5 7 3 6 4 0 2
    2 3 4 1 5 0 7 6 8
    1 2 3 4 5 6 7 8 0
    */
    


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  • 原文地址:https://www.cnblogs.com/cxchanpin/p/7206886.html
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