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  • HDU 4300 KMP

    #include <cstdio>
    #include <cstdlib>
    #include <cstring>
    #include <cmath>
    #include <cctype>
    #include <vector>
    #include <stack>
    #include <queue>
    #include <map>
    #include <algorithm>
    #include <iostream>
    #include <string>
    #include <set>
    #define X first
    #define Y second
    #define sqr(x) (x)*(x)
    #pragma comment(linker,"/STACK:102400000,102400000")
    using namespace std;
    const double PI = acos(-1.0);
    map<int, int>::iterator it;
    typedef long long LL ;
    template<typename T> void checkmin(T &x, T y) {x = min(x, y);}
    template<typename T> void checkmax(T &x, T y) {x = max(x, y);}
    
    const int N = 100005;
    int p[N];
    int KMP(char *a, int n, char *b, int m) {
        p[0] = -1;
        int i, j = -1;
        for(i = 1; i <= m; i++) {
            while((j > -1) && (b[j+1] != b[i]))
                j = p[j];
            if(b[j+1] == b[i]) j++;
            p[i] = j;
        }
        //for(i=0;i<m;i++) printf("%d   ",p[i]); printf("
    ");
        j = -1;
        for(i = 0; i < n; i++) {
            while((j > -1) && (b[j+1] != a[i])) j = p[j];
            if(b[j+1] == a[i]) {
                j++;
            }
            if(j == m - 1) {
                //printf("i=%d
    ",i);
                //return i-m+1;
                j = p[j];
            }
        }
        return -1;
    }
    char mp[27],back[256];
    char s[N], t[N];
    int main() {
        int T;
        scanf("%d", &T);
        while(T--) {
            scanf("%s%s", mp, s);
            for(int i=0;i<26;++i)
            {
                back[ mp[i] ]='a'+i;
            }
            int n = strlen(s);
            strcpy(t, s);
            int m = 0;
            for(int i = (n + 1) / 2; i < n; ++i) {
                ++m;
                s[i] = mp[ s[i] - 'a' ];
            }
            KMP(s, n, s, n);
            /*
            for(int i = 0; i < n; ++i) {
                printf("%3c", s[i]);
            } puts("");
            for(int i = 0; i < n; ++i) {
                printf("%3d", p[i]);
            } puts("");
            */
            int len = 0, q = n - 1;
            while(~p[q])--q, ++len;
            //printf("len =%d
    ", len);
            len = min(len, m);
            printf("%s", t);
            for(int i = len; i < n - len ; ++i) {
                printf("%c", back[t[i]]);
            } puts("");
        }
        return 0;
    }
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  • 原文地址:https://www.cnblogs.com/cxw199204/p/3348504.html
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