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  • LightOJ 1030 概率dp

    /********************
    
    Author:Cdegree
    
    ********************/
    #include <cstdio>
    #include <cstdlib>
    #include <cstring>
    #include <cmath>
    #include <cctype>
    #include <vector>
    #include <stack>
    #include <queue>
    #include <map>
    #include <algorithm>
    #include <iostream>
    #include <string>
    #include <set>
    #define X first
    #define Y second
    #define sqr(x) (x)*(x)
    #pragma comment(linker,"/STACK:102400000,102400000")
    using namespace std;
    const double PI = acos(-1.0);
    map<int, int>::iterator it;
    typedef long long LL ;
    template<typename T> void checkmin(T &x, T y) {x = min(x, y);}
    template<typename T> void checkmax(T &x, T y) {x = max(x, y);}
    
    const int N = 105;
    double a[N], dp[N];
    
    int main() {
        int T, n;
        scanf("%d", &T);
        for(int t = 1; t <= T; ++t) {
            scanf("%d", &n);
            for(int i = 0; i < n; ++i) {
                scanf("%lf", a + i);
            }
            dp[n-1]=0;
            for(int i = n - 2; i >= 0; --i) {
                int j = min(n - 1 - i, 6);
                dp[i]=0;
                for(int k = 1; k <= j; ++k) {
                    dp[i] += dp[i+k] + a[i+k];
                }
                dp[i] /= j;
            }
            dp[0] += a[0];
            printf("Case %d: %.6f
    ", t, dp[0]);
        }
        return 0;
    }
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  • 原文地址:https://www.cnblogs.com/cxw199204/p/3348529.html
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